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014: The time (in s) required for the current to get its one fifth initial value is: ontbele erit to sbutingsm arts sporb inlog B) 3.22 A) 1.39 68 C) 2.77 3 (A D) 0.72 For Q15 & Q16 For the circuit shown in the four if c E) 2.20 (Om. ni) xul tan erT .llede prisluent Isoherige s tuoriquanrit virmotinu betudhalb ai OS pro lloda odd to 20 Y

014: The time (in s) required for the current to get its one fifth initial value is: ontbele erit to sbutingsm arts sporb inlog B) 3.22 A) 1.39 68 C) 2.77 3 (A D) 0.72 For Q15 & Q16 For the circuit shown in the four if c E) 2.20 (Om. ni) xul tan erT .llede prisluent Isoherige s tuoriquanrit virmotinu betudhalb ai OS pro lloda odd to 20 Y

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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010; A parallel-plate capacitor has capacitance Co = 5 µF with no dielectric. It is then filled with a dielectric constant K = 2, a second capacitor of capacitance C is connected in series with the first one, and the capacitance of the series combination is Co. The value of the capacitance C (in HF) is: A) 6 sosis to tluse1 B) 2 ESOS-10- C) 10m2 E) 4 levd boilqqA 011: What is the current (in A) in a typical 120 V, 25 W lightbulb? A) 0.208-01 × B) 0.625 notbals C) 0.833 GM- D) 0.4170 x 28. E) 0.5230602 991 to divitis Indiendo c'umoivo 912: A battery has an emf & = 6 V and an internal resistance r = 0.05 2. Its terminals are connected to a load resistance battery. R= 32. Find the terminal voltage (in V) of the the term A) 17.70 B) 14.75 (in) of the b 0 5.(3 015: The current I₁ (in A) in the resistor 40 2 is: A) 2.0 D) 0.5 B) 3.0 med E) 1.0 D) 8 For Q13 & Q14 For the circuit shown in the figure, the capacitor is initially uncharged when the switch s is closed. 013: The charge (in uC) of the capacitor at t =1.8 s is: ره لها ملا D) 11.79 C) 8.05 biriw £-(0 C) 328 I On 03C) 2.5 stod s as bas bagad box art to unge sumont m Pel bris bo CS (D artA) 699 S InlogB) 451ysws m 1 inlog) 503 obudingsm D) 593 bole n6 2 E) 551 epnsrbloq bedsloel nA t 014: The time (in s) required for the current to get its one fifth initial value is: ontbals erit to obutingsm ert opnarb trilog A) 1.39 B) 3.22 C) 2.77 D) 0.72 3 (A E) 2.20 For Q15 & Q16 (Om. nl) xu ten erT .lledz pritsluani leoharige s tuoripuorit For the circuit shown in the figure, if £₂ = 20 V, virmotinu betudhtalb ai OS pr el lleria end to soshua 40 Ω wOA (A 0 9 oldet bedoetts odt ni lli E) 5.90 direction direction D) 5.37 S E10S (A ㅏ +1₁ Ezinu al m S -1₂-3A PE (8 016: The value of 83 (in V) is: E3 80 w A) 90B) 240 tills moC) 120 sonstalb 6 (WXn) blaft 1-0.5 Asm or bn A D) 280 E) 160 may 2= Avdianab episrib 2 (A For Q17 & Q18: neewed evom al nori u 2 shorts to dibiheq a to (ty ni) veneng ladneton ni sprierb ord el der Wa A proton is moving in a circular orbit of radius 14 cm in uniform 0.8 T magnetic field perpendicular to the velocity of the proton. 017: The linear speed (in Mm/s) of the proton is: 0001 (8 A) 2.68 els ruiw b B) 10.73 bisit ohbele art 018: The period (in ns) of the motion is: A) 164 B) 109 16binsdog ph ww A 40 ΚΩ #.0 20 venА 0193 50 μF at (8 E) 82 20 o ban A E wwwww inlog 81 (A E) 7.37 to Bulev erti al terW;a x -³x = (x)V P- (A D) 201 dela adr 019: A wire having a mass pere unit length of 0.8 g/cm carries a 1 A current horizontally to the right. The minimum magnetic field (in Tesla) needed to left this wire vertically upward is: (g = 10 m/s²) A) 0.784 B) 0.490 C) 0.511 D) 0.245 namsa adi to ahem sne 6 08 = 18.30 ulsy arti fert,novi bet art led tud 8 to ign of the magnetic force exerted on the electron is: 020: An electron moves in the negative x direction, through a uniform magnetic field in the negative z direction. The direction el (nl) i sorielaan 90 to sulsv erT:80 8 (A C) in the + k direction noto 322sq (An) inemus adT RE S (8 A (A E A) in the direction SE (B B) in the D) in the + j direction E) in the up wore srl azu eos 80 10 E) 0.098 bris 19 210talon Isohbnilva ow
Transcribed Image Text:010; A parallel-plate capacitor has capacitance Co = 5 µF with no dielectric. It is then filled with a dielectric constant K = 2, a second capacitor of capacitance C is connected in series with the first one, and the capacitance of the series combination is Co. The value of the capacitance C (in HF) is: A) 6 sosis to tluse1 B) 2 ESOS-10- C) 10m2 E) 4 levd boilqqA 011: What is the current (in A) in a typical 120 V, 25 W lightbulb? A) 0.208-01 × B) 0.625 notbals C) 0.833 GM- D) 0.4170 x 28. E) 0.5230602 991 to divitis Indiendo c'umoivo 912: A battery has an emf & = 6 V and an internal resistance r = 0.05 2. Its terminals are connected to a load resistance battery. R= 32. Find the terminal voltage (in V) of the the term A) 17.70 B) 14.75 (in) of the b 0 5.(3 015: The current I₁ (in A) in the resistor 40 2 is: A) 2.0 D) 0.5 B) 3.0 med E) 1.0 D) 8 For Q13 & Q14 For the circuit shown in the figure, the capacitor is initially uncharged when the switch s is closed. 013: The charge (in uC) of the capacitor at t =1.8 s is: ره لها ملا D) 11.79 C) 8.05 biriw £-(0 C) 328 I On 03C) 2.5 stod s as bas bagad box art to unge sumont m Pel bris bo CS (D artA) 699 S InlogB) 451ysws m 1 inlog) 503 obudingsm D) 593 bole n6 2 E) 551 epnsrbloq bedsloel nA t 014: The time (in s) required for the current to get its one fifth initial value is: ontbals erit to obutingsm ert opnarb trilog A) 1.39 B) 3.22 C) 2.77 D) 0.72 3 (A E) 2.20 For Q15 & Q16 (Om. nl) xu ten erT .lledz pritsluani leoharige s tuoripuorit For the circuit shown in the figure, if £₂ = 20 V, virmotinu betudhtalb ai OS pr el lleria end to soshua 40 Ω wOA (A 0 9 oldet bedoetts odt ni lli E) 5.90 direction direction D) 5.37 S E10S (A ㅏ +1₁ Ezinu al m S -1₂-3A PE (8 016: The value of 83 (in V) is: E3 80 w A) 90B) 240 tills moC) 120 sonstalb 6 (WXn) blaft 1-0.5 Asm or bn A D) 280 E) 160 may 2= Avdianab episrib 2 (A For Q17 & Q18: neewed evom al nori u 2 shorts to dibiheq a to (ty ni) veneng ladneton ni sprierb ord el der Wa A proton is moving in a circular orbit of radius 14 cm in uniform 0.8 T magnetic field perpendicular to the velocity of the proton. 017: The linear speed (in Mm/s) of the proton is: 0001 (8 A) 2.68 els ruiw b B) 10.73 bisit ohbele art 018: The period (in ns) of the motion is: A) 164 B) 109 16binsdog ph ww A 40 ΚΩ #.0 20 venА 0193 50 μF at (8 E) 82 20 o ban A E wwwww inlog 81 (A E) 7.37 to Bulev erti al terW;a x -³x = (x)V P- (A D) 201 dela adr 019: A wire having a mass pere unit length of 0.8 g/cm carries a 1 A current horizontally to the right. The minimum magnetic field (in Tesla) needed to left this wire vertically upward is: (g = 10 m/s²) A) 0.784 B) 0.490 C) 0.511 D) 0.245 namsa adi to ahem sne 6 08 = 18.30 ulsy arti fert,novi bet art led tud 8 to ign of the magnetic force exerted on the electron is: 020: An electron moves in the negative x direction, through a uniform magnetic field in the negative z direction. The direction el (nl) i sorielaan 90 to sulsv erT:80 8 (A C) in the + k direction noto 322sq (An) inemus adT RE S (8 A (A E A) in the direction SE (B B) in the D) in the + j direction E) in the up wore srl azu eos 80 10 E) 0.098 bris 19 210talon Isohbnilva ow
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