A certain voltage is +11.1 V for 21.8 ms and -11.1V for the succeeding 21.8 ms and continues oscillating back and forth between these two values at 43.6 ms interval The voltage is present across a 59 12 resistor. Over any 43.6 ms interval, find: (a) the maximum value of the voltage (b) the average value of the voltage (c) the average value of the resistor current (d) the maximum value of the absorbed power (e) the average value of the absorbed power. (a) V (b) Vy= (c) Farg (d) Par (e) Parg = A W W

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A certain voltage is + 11.1V for 21.8 ms and -11.1 V for the succeeding 21.8 ms and continues oscillating back and forth between these two values at 43.6 ms intervals
The voltage is present across a 59 12 resistor.
Over any 43.6 ms interval, find:
(a) the maximum value of the voltage
(b) the average value of the voltage
(c) the average value of the resistor current
(d) the maximum value of the absorbed power
(e) the average value of the absorbed power.
(6) Vmax=
(b) Vary
(c) Kang
(d) Par
(e) Parg
R
V
A
W
W
Transcribed Image Text:A certain voltage is + 11.1V for 21.8 ms and -11.1 V for the succeeding 21.8 ms and continues oscillating back and forth between these two values at 43.6 ms intervals The voltage is present across a 59 12 resistor. Over any 43.6 ms interval, find: (a) the maximum value of the voltage (b) the average value of the voltage (c) the average value of the resistor current (d) the maximum value of the absorbed power (e) the average value of the absorbed power. (6) Vmax= (b) Vary (c) Kang (d) Par (e) Parg R V A W W
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