01:14LTEQuestion 4/51 pointWhat does the following code fragmentprint?int[] a = new int[10];for (int i = 0; i < 10; i++)a[i] = 9 - i;for (int i = 0; i < 10; i++)a[i] = a[a[i]];System.out.println(a[5]);Enter answer here...NEXT>

program code: import java.util.*; public class Main{ public static void main(String [] args){…

Answered: 01:14 Question 4/5 1 point What does…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Java - Gift Exchange *** Please include UML Diagram and notes in code Minimum requirements are: At least 1 loop An Array or ArrayList At least 3 Java classes Use methods I am trying to make it so that the program will: Prompt for the number of people included in exchange - If not even it will state that there has to be an even number and ask for the number of people included again (loops). Prompt to enter a participant's first name Prompt for the participant's age Print out the random matching of participants so that everyone gets a gift and everyone gives a gift. Please include UML Diagram
void changeAll(int x[]) { x[0] = x[0] + 5; return; The first element in an array would be increased by 5 The array would be the same because it was passed by value x would be increased by 5 All the elements in the passed array would be incremented by 5
#include <stdio.h>#include <limits.h> int findMissingUtil(int arr[], int low, int high, int diff){ if (high <= low)return INT_MAX; int mid = low + (high - low)/2; if (arr[mid+1] - arr[mid] != diff)return (arr[mid] + diff); if (mid > 0 && arr[mid] - arr[mid-1] != diff)return (arr[mid-1] + diff); if (arr[mid] == arr[0] + mid*diff)return findMissingUtil(arr, mid+1, high, diff); return findMissingUtil(arr, low, mid-1, diff);} int findMissing(int arr[], int n){int diff = (arr[n-1] - arr[0])/n; return findMissingUtil(arr, 0, n-1,diff);} int main(){int arr[] = {120001, 120013, 120025, 120037, 120049, 120061,120085,120097,120109,120121};int n = sizeof(arr)/sizeof(arr[0]);printf("The missing element is %d", findMissing(arr, n));return 0;} ______________________________________________________________________________ Convert the code above into Pseudocode

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01:14 Question 4/5 1 point What does the following code fragment print? int[] a = new int[10]; for (int i = 0; i < 10; i++) a[i] = 9 - i; for (int i = 0; i < 10; i++) a[i] = a[a[i]]; System.out.println(a[5]);