(01) If y² x y³=32 then find the value of y.. (02) Solve. 2x = 1 64 3 (03) Simplify. (a2)³

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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(01) If y² x y³=32 then find the
value of y.
(02) Solve.
2x = 1
64
3
(03) Simplify. (a¹²) ³
2/3
(04) Simplify.
64
27
(05) If x=5 find the value of x².
(06) Find the value of (81)³/4
(07) Simplify. (16)³ x 1 x 4-5/2
3√/27
(08) Simplify. (a²)²
-2
a³b-²
(09) Solve. 3√4x = 6
10
-6
(10) Simplify.
4
(√q) +
(11) Find the value of x.
-2/3
(12) Simplify. 64
27
(13) Solve. 4*
-
16 x 2.
-3
(14) Simplify. 2x³ x √(9x²)
12 x³
2/5
-3
(15) Simplify. 32 2
X
81
42x-1 = 8x
(01) Simplify. 2lg 5 + lg 4
(02) Simplify. 2 lg 5 + lg 8 - lg 2
(03) Simplify. 2 lg 20-lg 4
(04) Simplify. 2lg 20-3lg4+ lg 16
(05) If lg 2= 0.3010, lg 3 = 0.4771, find the
fin Value of lg 6 2/3.
(06) Simplify. 2lg 5 + Ig160 - 1 lg 64
3
(07) lg 35-lg 14 + 2lg6 - 2lg 30
(08) If a=lg 13,b=lg 600, c= 14 find a+b+c.
4
7
39
C=10
(09)Simplify. lg 625-lg 125 + lg (35x4)
7
(10) lg2=x, lg 3 = y, Express Ig24 in terms of
x and y.
(11) Solve. Ig x + lg 2 = lg 6
(12) Solve. Igx-lg2=lg3 + lg 5
(13) Solve. log 3 y = 4
(14) 2 lg 3 + 2lg x + lg 7 = lg 28
(15) 2 lg x + lg 2 = 1 lg 64 + 2lg 3
.
2
Transcribed Image Text:(01) If y² x y³=32 then find the value of y. (02) Solve. 2x = 1 64 3 (03) Simplify. (a¹²) ³ 2/3 (04) Simplify. 64 27 (05) If x=5 find the value of x². (06) Find the value of (81)³/4 (07) Simplify. (16)³ x 1 x 4-5/2 3√/27 (08) Simplify. (a²)² -2 a³b-² (09) Solve. 3√4x = 6 10 -6 (10) Simplify. 4 (√q) + (11) Find the value of x. -2/3 (12) Simplify. 64 27 (13) Solve. 4* - 16 x 2. -3 (14) Simplify. 2x³ x √(9x²) 12 x³ 2/5 -3 (15) Simplify. 32 2 X 81 42x-1 = 8x (01) Simplify. 2lg 5 + lg 4 (02) Simplify. 2 lg 5 + lg 8 - lg 2 (03) Simplify. 2 lg 20-lg 4 (04) Simplify. 2lg 20-3lg4+ lg 16 (05) If lg 2= 0.3010, lg 3 = 0.4771, find the fin Value of lg 6 2/3. (06) Simplify. 2lg 5 + Ig160 - 1 lg 64 3 (07) lg 35-lg 14 + 2lg6 - 2lg 30 (08) If a=lg 13,b=lg 600, c= 14 find a+b+c. 4 7 39 C=10 (09)Simplify. lg 625-lg 125 + lg (35x4) 7 (10) lg2=x, lg 3 = y, Express Ig24 in terms of x and y. (11) Solve. Ig x + lg 2 = lg 6 (12) Solve. Igx-lg2=lg3 + lg 5 (13) Solve. log 3 y = 4 (14) 2 lg 3 + 2lg x + lg 7 = lg 28 (15) 2 lg x + lg 2 = 1 lg 64 + 2lg 3 . 2
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