0.997 0.950 0.878

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Kindly compute the residual only

No. of
Critical Values for Correlation Coefficient
absences, x
1
2
3
4 5
Final
exam score, y 88.7 85.7
83.1
80.7
78.1
74.3
65.2 70.8
65.8 65.8
3
0.997
4.
0.950
Print
Done
5
0.878
0.811
7.
0.754
8
0.707
9
0.666
10
0.632
11
0.602
12
0.576
13
0.553
14
0.532
15
0.514
16
0.497
17
0.482
18
0.468
19
0.456
20
0.444
21
0.433
22
0.423
23
0.413
24
0.404
25
0.396
26
0.388
27
0.381
28
0.374
29
0.367
30
0.361
co
Transcribed Image Text:No. of Critical Values for Correlation Coefficient absences, x 1 2 3 4 5 Final exam score, y 88.7 85.7 83.1 80.7 78.1 74.3 65.2 70.8 65.8 65.8 3 0.997 4. 0.950 Print Done 5 0.878 0.811 7. 0.754 8 0.707 9 0.666 10 0.632 11 0.602 12 0.576 13 0.553 14 0.532 15 0.514 16 0.497 17 0.482 18 0.468 19 0.456 20 0.444 21 0.433 22 0.423 23 0.413 24 0.404 25 0.396 26 0.388 27 0.381 28 0.374 29 0.367 30 0.361 co
The accompanying data represent the number of days absent, x, and the final exam score, y, for a sample of college students in a general education course at a large state university. Complete parts (a) through (e) below.
E Click the icon to view the absence count and final exam score data
Click the icon to view a table of critical values for the correlation coefficient.
(a) Find the least-squares regression line treating number of absences as the explanatory variable and the final exam score as the response variable.
y = - 2.771 x+ 88.290
(Round to three decimal places as needed.)
(b) Interpret the slope and the y-intercept, if appropriate. Choose the correct answer below and fill in any answer boxes in your choice.
(Round to three decimal places as needed.)
The average final exam score of students who miss no classes is
It is not appropriate to interpret the slope.
B. For every additional absence, a student's final exam score drops 2.771 points, on average. The average final exam score of students who miss no classes is 88.29
O C. For every additional absence, a student's final exam score drops
points, on average. It is not appropriate to interpret the y-intercept.
D. It is not appropriate to interpret the slope or the y-intercept.
(c) Predict the final exam score for a student who misses five class periods.
y = 74.43 (Round to two decimal places as needed.)
Compute the residual.
(Round to two decimal places as needed.)
Transcribed Image Text:The accompanying data represent the number of days absent, x, and the final exam score, y, for a sample of college students in a general education course at a large state university. Complete parts (a) through (e) below. E Click the icon to view the absence count and final exam score data Click the icon to view a table of critical values for the correlation coefficient. (a) Find the least-squares regression line treating number of absences as the explanatory variable and the final exam score as the response variable. y = - 2.771 x+ 88.290 (Round to three decimal places as needed.) (b) Interpret the slope and the y-intercept, if appropriate. Choose the correct answer below and fill in any answer boxes in your choice. (Round to three decimal places as needed.) The average final exam score of students who miss no classes is It is not appropriate to interpret the slope. B. For every additional absence, a student's final exam score drops 2.771 points, on average. The average final exam score of students who miss no classes is 88.29 O C. For every additional absence, a student's final exam score drops points, on average. It is not appropriate to interpret the y-intercept. D. It is not appropriate to interpret the slope or the y-intercept. (c) Predict the final exam score for a student who misses five class periods. y = 74.43 (Round to two decimal places as needed.) Compute the residual. (Round to two decimal places as needed.)
Expert Solution
Step 1

According to the given sum, for the data set, the least square regression equation is y^=-2.771x+88.290.

The final exam score for a student who misses five class periods is

y^=-2.771x+88.290.

=(-2.771*5)+88.290

=74.43

We need to find the residual(ei) which is the difference between the actual value(yi) and observed value(y^). i.e. 

ei=yi-y^

 

 

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