0.9 0.8 0.7 Run #15 0.6 0.5 0.4 0.0 0.2 0,4 0,6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 Time (s) 2.2 2.4 2.6 0.05 0.00 -0.05 -0.10 V -0.15 Run #15 -0.20 Linear -0.25 mt + b m = -0.161021 ± 4.12x10 b = 0.0225582 + 6.53x10 -0.30 -0.35 T=-1.000 -0.40 -0.45 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 Time (s) aph title here] A Position (m)
0.9 0.8 0.7 Run #15 0.6 0.5 0.4 0.0 0.2 0,4 0,6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 Time (s) 2.2 2.4 2.6 0.05 0.00 -0.05 -0.10 V -0.15 Run #15 -0.20 Linear -0.25 mt + b m = -0.161021 ± 4.12x10 b = 0.0225582 + 6.53x10 -0.30 -0.35 T=-1.000 -0.40 -0.45 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 Time (s) aph title here] A Position (m)
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter38: Refraction And Images Formed By Refraction
Section: Chapter Questions
Problem 70PQ: A Fill in the missing entries in Table P38.70. Table P38.70
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- Use the information from the graph to answer the following question
- Do not enter units into your answer
a.) the cart is moving to the blank( right or left) and it is moving at ( a constant speed, speeding up or slowing down)
B.) the acceleration of the cart has blank ( 1,2,3,4,) significant numbers
C.) the final result for the acceleration is blank +/- blank
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