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0.80 m F=900 N 19

0.80 m F=900 N 19

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In our first example, we will see that we can use a lever arm to greatly increase the torque without having to provide more force. Suppose, for instance, that an amateur plumber, unable to loosen a pipe fitting, slips a plece of scrap pipe (sometimes called a "cheater") over the handle of his wrench, He then applies his full weight of 900 N to the end of the cheater by standing on it. The distance from the center of the fitting to the point where the weight acts is 0.80 m, and the wrench handle and cheater make an angle of 19° with the horizontal (Figure 1). Find the magnitude and direction Figure of 1 0.80 m F= 900 N 19"
Transcribed Image Text:In our first example, we will see that we can use a lever arm to greatly increase the torque without having to provide more force. Suppose, for instance, that an amateur plumber, unable to loosen a pipe fitting, slips a plece of scrap pipe (sometimes called a "cheater") over the handle of his wrench, He then applies his full weight of 900 N to the end of the cheater by standing on it. The distance from the center of the fitting to the point where the weight acts is 0.80 m, and the wrench handle and cheater make an angle of 19° with the horizontal (Figure 1). Find the magnitude and direction Figure of 1 0.80 m F= 900 N 19"
If the pipe fitting under consideration can withstand a maximum torque of 650 N- m without breaking, what is the smallest angle at which our amateur plumber can safely stand on the end of the cheater and apply his full weight without breaking the pipe fitting? Express your answer in degrees. ΑΣφ
Transcribed Image Text:If the pipe fitting under consideration can withstand a maximum torque of 650 N- m without breaking, what is the smallest angle at which our amateur plumber can safely stand on the end of the cheater and apply his full weight without breaking the pipe fitting? Express your answer in degrees. ΑΣφ
Expert Solution
Step 1

Force acting by plumber F = 900 N

The distance between the center and point of action = 0.80 m

maximum torque acting on pipe without breaking τ = 650 N . m

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