-0.64.1 (None] 0,20 Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer PCC)-.20 The Probability of choosing a incorrect answer P(() = 80. X Denates the number of correct. answers x=0,1,2 0.20 0.04 0.80 0.80 getting none right by guessing 0.36 One 0.20 980 P(x=27=0,20x0.20 P(x)=0,20x0,80 P(x=1=0,20x0.80 →0.16 + (x=0)=0.80 x 0.80 +0.64 The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting 0,4, and both right x 0 1 2 PG=A) 0.64 0.32/0.04 0.04 Both
-0.64.1 (None] 0,20 Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer PCC)-.20 The Probability of choosing a incorrect answer P(() = 80. X Denates the number of correct. answers x=0,1,2 0.20 0.04 0.80 0.80 getting none right by guessing 0.36 One 0.20 980 P(x=27=0,20x0.20 P(x)=0,20x0,80 P(x=1=0,20x0.80 →0.16 + (x=0)=0.80 x 0.80 +0.64 The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting 0,4, and both right x 0 1 2 PG=A) 0.64 0.32/0.04 0.04 Both
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Find the

Transcribed Image Text:-0.64.1
(None
Using the tree diagram you just constructed and make a table showing the probability
Histribution of getting zero, one, or both questions right by guessing.
Probability of choosing a
correct answer P(C) = -20
The Probability of choosing
a incorrect answer P(() = .80
0,20
0.80
getting none right by guessing
0.36
one
X Denates the number of corred p(x=27=0.20 0.20
answers x=0,1,2
0.04
0.80
0.20
P(x)=0.20*0.80
P(x=1=0,20x0.80
→ 0.16
аво
The probability value corresponding
to one question is right by guessing is:
P(x=1)=0,16+0.16
for getting and both
right
0.04
151 (Both
+ (x=0)=0.80 x 0.80
+0.64
X
0
1 2
PGx=x) 0.64 0.32/0.04

Transcribed Image Text:You're taking a multiple-choice exam and you don't know the answers to two of the questions.
Each question has five choices, so the probability of getting a question right by guessing is
.20. Draw a tree diagram showing the probabilities of getting none, one, or both questions
right by guessing.
P(X=x) = ()P/-P)n-x
X is random variable denote
of questions quessed right
n=2&P=0₁2
non quessed Right
P(x=0) = (2) x(0.2))x(1-0.2) (2-0)
02-0) (0.8)2
= 2
1x0.64
=
non quesses right 0.64
=64
One guessed right
P(x-1)=(2)x(0.2) ¹x (1-0.2) (2-1)
= 7(2-1) × (0.2) ¹x (0.8)'
x
= 2x0.2x0.8 0.32
One guessed right is 0.32
both guessed right
P(x-2)=(2)x(0.2)x(1-0.2) (²
= 2(2-2) × (0.2)² x (0.8) O
=1*0.04=0.04
Both guessed right is 0.04
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