-0.64.1 (None] 0,20 Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer PCC)-.20 The Probability of choosing a incorrect answer P(() = 80. X Denates the number of correct. answers x=0,1,2 0.20 0.04 0.80 0.80 getting none right by guessing 0.36 One 0.20 980 P(x=27=0,20x0.20 P(x)=0,20x0,80 P(x=1=0,20x0.80 →0.16 + (x=0)=0.80 x 0.80 +0.64 The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting 0,4, and both right x 0 1 2 PG=A) 0.64 0.32/0.04 0.04 Both

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

Find the expected value of the number of questions you'd get right by guessing. What are the variance and standard deviation? (The pictures attached show work from the other question in order to anwer the question. Thank you)

-0.64.1
(None
Using the tree diagram you just constructed and make a table showing the probability
Histribution of getting zero, one, or both questions right by guessing.
Probability of choosing a
correct answer P(C) = -20
The Probability of choosing
a incorrect answer P(() = .80
0,20
0.80
getting none right by guessing
0.36
one
X Denates the number of corred p(x=27=0.20 0.20
answers x=0,1,2
0.04
0.80
0.20
P(x)=0.20*0.80
P(x=1=0,20x0.80
→ 0.16
аво
The probability value corresponding
to one question is right by guessing is:
P(x=1)=0,16+0.16
for getting and both
right
0.04
151 (Both
+ (x=0)=0.80 x 0.80
+0.64
X
0
1 2
PGx=x) 0.64 0.32/0.04
Transcribed Image Text:-0.64.1 (None Using the tree diagram you just constructed and make a table showing the probability Histribution of getting zero, one, or both questions right by guessing. Probability of choosing a correct answer P(C) = -20 The Probability of choosing a incorrect answer P(() = .80 0,20 0.80 getting none right by guessing 0.36 one X Denates the number of corred p(x=27=0.20 0.20 answers x=0,1,2 0.04 0.80 0.20 P(x)=0.20*0.80 P(x=1=0,20x0.80 → 0.16 аво The probability value corresponding to one question is right by guessing is: P(x=1)=0,16+0.16 for getting and both right 0.04 151 (Both + (x=0)=0.80 x 0.80 +0.64 X 0 1 2 PGx=x) 0.64 0.32/0.04
You're taking a multiple-choice exam and you don't know the answers to two of the questions.
Each question has five choices, so the probability of getting a question right by guessing is
.20. Draw a tree diagram showing the probabilities of getting none, one, or both questions
right by guessing.
P(X=x) = ()P/-P)n-x
X is random variable denote
of questions quessed right
n=2&P=0₁2
non quessed Right
P(x=0) = (2) x(0.2))x(1-0.2) (2-0)
02-0) (0.8)2
= 2
1x0.64
=
non quesses right 0.64
=64
One guessed right
P(x-1)=(2)x(0.2) ¹x (1-0.2) (2-1)
= 7(2-1) × (0.2) ¹x (0.8)'
x
= 2x0.2x0.8 0.32
One guessed right is 0.32
both guessed right
P(x-2)=(2)x(0.2)x(1-0.2) (²
= 2(2-2) × (0.2)² x (0.8) O
=1*0.04=0.04
Both guessed right is 0.04
Transcribed Image Text:You're taking a multiple-choice exam and you don't know the answers to two of the questions. Each question has five choices, so the probability of getting a question right by guessing is .20. Draw a tree diagram showing the probabilities of getting none, one, or both questions right by guessing. P(X=x) = ()P/-P)n-x X is random variable denote of questions quessed right n=2&P=0₁2 non quessed Right P(x=0) = (2) x(0.2))x(1-0.2) (2-0) 02-0) (0.8)2 = 2 1x0.64 = non quesses right 0.64 =64 One guessed right P(x-1)=(2)x(0.2) ¹x (1-0.2) (2-1) = 7(2-1) × (0.2) ¹x (0.8)' x = 2x0.2x0.8 0.32 One guessed right is 0.32 both guessed right P(x-2)=(2)x(0.2)x(1-0.2) (² = 2(2-2) × (0.2)² x (0.8) O =1*0.04=0.04 Both guessed right is 0.04
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps with 14 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman