0.5 m B Example Replace the force system acting on the post by a resultant force, and specify where its line of action intersects the post AB measured from point A. 500 N 1 m 0.2 m 250 N 30 1 m 300 N SOLUTION 1 m Equivalent Resultant Force: Forces F, and F, are resolved into their x and y

A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: Fparallel + Fperpendicular = Ftotal 2013 Michael Swanbom BY NC SA d A FK values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F|DA = i. k) lb and b. FL DA =

Vertical point loads are applied at points A - E on a boat trailer, as shown. Forces applied at points F and G lie in the yz plane. Compute (a) an equivalent force system at point O, (b) an equivalent force system consisting of a single force, and specify the coordinates of the point where the force's line of action intersects the xy plane. 18 in. 18 in. X 400 lb A 10% 24 in. 400 lb B 300 lb 36 in. 300 lb 0 900 lb 24 in. 500 lb E B 24 in. 350 lb 130° 1450 18 in.

Given a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 509 N , Q = 388 N,  and  T = 444 N . Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of moment: use CW if clockwise , CCW if counterclockwise.