0.5 m 20 kg A B C p= = 1000 kg T 0.15 m A container of water has a cross-sectional area of 0.50 m². A piston sits on top of the water (see the above figure). A spout is located 0.15 m from the bottom of the tank, open to the atmosphere, and a stream of water exits the spout. The cross-sectional area of the spout is 5.0 x 10-4 m². What is the pressure right under the piston? What is the velocity of the water as it leaves the spout? How far from the spout does the water hit the floor if the tank sits on the floor? Ignore all friction and dissipative forces.

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Chapter1: Units, Trigonometry. And Vectors
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0.5 m
20 kg
A
B
C
kg
p= 1000-
T
0.15 m
A container of water has a cross-sectional area of 0.50 m². A piston sits on top of the water (see the
above figure). A spout is located 0.15 m from the bottom of the tank, open to the atmosphere, and a
stream of water exits the spout. The cross-sectional area of the spout is 5.0 x 10-4 m².
What is the pressure right under the piston?
What is the velocity of the water as it leaves the spout?
How far from the spout does the water hit the floor if the tank sits on the floor? Ignore
all friction and dissipative forces.
Transcribed Image Text:0.5 m 20 kg A B C kg p= 1000- T 0.15 m A container of water has a cross-sectional area of 0.50 m². A piston sits on top of the water (see the above figure). A spout is located 0.15 m from the bottom of the tank, open to the atmosphere, and a stream of water exits the spout. The cross-sectional area of the spout is 5.0 x 10-4 m². What is the pressure right under the piston? What is the velocity of the water as it leaves the spout? How far from the spout does the water hit the floor if the tank sits on the floor? Ignore all friction and dissipative forces.
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