0.250 molH PO LH3PO4 0.250 mol H₂PO4 LH₂PO₂ X 3 mol NaOH 1 mol H₂PO4 3 1 A solution of phosphoric acid (H3PO4) with a known concentration of 0.250 M H3PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H3PO4 according to the following balanced chemical equation: mol NaOH molH3PO4 72.0 mL H₂PO4 0.800 mol NaOH = 67.5 mL NaOH 0.800 43.2 X 0.250 H3PO4 + 3 NaOH → Na3PO4 + 3 H₂O 72.0 0.800 0.0675 1000 MH3PO4 mol H3PO4 mL H3PO4 M NaOH mL NaOH mol NaOH 67.5 6.75 x 104 g NaOH g H3PO4 1 22.5 = 0.001 67.5 72.0 LH3PO4 mol NaOH mL NaOH 3 7.50 mL H3PO4 LNaOH 2
0.250 molH PO LH3PO4 0.250 mol H₂PO4 LH₂PO₂ X 3 mol NaOH 1 mol H₂PO4 3 1 A solution of phosphoric acid (H3PO4) with a known concentration of 0.250 M H3PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H3PO4 according to the following balanced chemical equation: mol NaOH molH3PO4 72.0 mL H₂PO4 0.800 mol NaOH = 67.5 mL NaOH 0.800 43.2 X 0.250 H3PO4 + 3 NaOH → Na3PO4 + 3 H₂O 72.0 0.800 0.0675 1000 MH3PO4 mol H3PO4 mL H3PO4 M NaOH mL NaOH mol NaOH 67.5 6.75 x 104 g NaOH g H3PO4 1 22.5 = 0.001 67.5 72.0 LH3PO4 mol NaOH mL NaOH 3 7.50 mL H3PO4 LNaOH 2
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.103E
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Transcribed Image Text:0.250
molH3PO4
LH3PO4
0.250 mol H₂PO4
LH₂PO4
X
3 mol NaOH
1 mol H₂PO4
3
1
A solution of phosphoric acid (H3PO4) with a known concentration of 0.250 M H3PO4
is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to
reach the third equivalence point with a starting volume of 72.0 mL H3PO4
according to the following balanced chemical equation:
mol NaOH
molH3PO4
72.0 mL H3PO4
0.800 mol NaOH
= 67.5 mL NaOH
0.800
43.2
X
0.250
H3PO4 + 3 NaOH Na3PO4 +
mL H3PO4
72.0
0.800
0.0675
1000
M H3PO4 mol H3PO4
67.5
mol NaOH
6.75 x 104
M NaOH
mL NaOH
g NaOH
g H3PO4
1
22.5
=
3 H₂O
0.001
67.5
72.0
LH3PO4
mol NaOH
mL NaOH
3
7.50
mL H3PO4
L NaOH
2
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