0.25, μk = 0.15. 4. A 10 kg object resting on a rough surface µ = (a) Draw a FBD diagram showing the forces acting on the body when pushed with the force of 20 N. What are the values of frictional force and net force in this case? Is frictional force static or kinetic? (b) Draw a FBD diagram showing the forces acting on the body when pushed with the force of 40 N. What are the values of frictional force and net force in this case? Is frictional force static or kinetic?
0.25, μk = 0.15. 4. A 10 kg object resting on a rough surface µ = (a) Draw a FBD diagram showing the forces acting on the body when pushed with the force of 20 N. What are the values of frictional force and net force in this case? Is frictional force static or kinetic? (b) Draw a FBD diagram showing the forces acting on the body when pushed with the force of 40 N. What are the values of frictional force and net force in this case? Is frictional force static or kinetic?
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Problem 4: Forces Acting on a 10 kg Object on a Rough Surface
**Parameters:**
- Mass of the object (\(m\)): 10 kg
- Coefficient of static friction (\(\mu_s\)): 0.25
- Coefficient of kinetic friction (\(\mu_k\)): 0.15
**Questions:**
**(a)** Draw a Free Body Diagram (FBD) showing the forces acting on the body when pushed with a force of 20 N. What are the values of the frictional force and net force in this case? Is the frictional force static or kinetic?
**(b)** Draw a Free Body Diagram (FBD) showing the forces acting on the body when pushed with a force of 40 N. What are the values of the frictional force and net force in this case? Is the frictional force static or kinetic?
---
### Explanation:
#### **(a) Analysis of the Object When Pushed with 20 N:**
1. **Free Body Diagram (FBD):**
- The object is subject to the following forces:
- Weight (\(W = mg = 10 \times 9.8 = 98 \text{ N}\))
- Normal force (\(N\)) exerted by the surface, which is equal to the weight (98 N) in magnitude but opposite in direction.
- Applied force (\(F_{\text{push}} = 20 \text{ N}\))
- Frictional force (\(f\)) resisting the applied force.
2. **Determine the Maximum Static Friction Force:**
- \(f_{\text{static, max}} = \mu_s \times N = 0.25 \times 98 \text{ N} = 24.5 \text{ N}\)
3. **Compare Applied Force to Maximum Static Friction:**
- Since \(F_{\text{push}} (20 \text{ N}) < f_{\text{static, max}} (24.5 \text{ N})\), the frictional force will balance out the applied force, which means no motion will happen, and the frictional force is static.
4. **Frictional Force and Net Force:**
- \(f = 20 \text{ N}\) (static friction)
- Net force \(F_{\text{net}} = F_{\text{push](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45088ba1-a1a3-4a96-b462-54f2c0a5a29e%2F5f1258ee-cd9b-4ee7-bbe2-efe32918f64d%2Fh81lpu_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem 4: Forces Acting on a 10 kg Object on a Rough Surface
**Parameters:**
- Mass of the object (\(m\)): 10 kg
- Coefficient of static friction (\(\mu_s\)): 0.25
- Coefficient of kinetic friction (\(\mu_k\)): 0.15
**Questions:**
**(a)** Draw a Free Body Diagram (FBD) showing the forces acting on the body when pushed with a force of 20 N. What are the values of the frictional force and net force in this case? Is the frictional force static or kinetic?
**(b)** Draw a Free Body Diagram (FBD) showing the forces acting on the body when pushed with a force of 40 N. What are the values of the frictional force and net force in this case? Is the frictional force static or kinetic?
---
### Explanation:
#### **(a) Analysis of the Object When Pushed with 20 N:**
1. **Free Body Diagram (FBD):**
- The object is subject to the following forces:
- Weight (\(W = mg = 10 \times 9.8 = 98 \text{ N}\))
- Normal force (\(N\)) exerted by the surface, which is equal to the weight (98 N) in magnitude but opposite in direction.
- Applied force (\(F_{\text{push}} = 20 \text{ N}\))
- Frictional force (\(f\)) resisting the applied force.
2. **Determine the Maximum Static Friction Force:**
- \(f_{\text{static, max}} = \mu_s \times N = 0.25 \times 98 \text{ N} = 24.5 \text{ N}\)
3. **Compare Applied Force to Maximum Static Friction:**
- Since \(F_{\text{push}} (20 \text{ N}) < f_{\text{static, max}} (24.5 \text{ N})\), the frictional force will balance out the applied force, which means no motion will happen, and the frictional force is static.
4. **Frictional Force and Net Force:**
- \(f = 20 \text{ N}\) (static friction)
- Net force \(F_{\text{net}} = F_{\text{push
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