0.10 32 E, = 24 V + C d: R, = 5.0 2 ,0.5 Ω R5 = 20 2 12 ¿Ez = 48 V R, = 40 2 + a e k 13 0.20 N R3 = 78 N 13 = 0.05 N E= 36 V Ez = 6.0 V og hi 2.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Apply the junction rule to point a shown below.

0.10 Ω
E1 = 24 V
+
R, = 5.0 2
, = 0.5 Q
12
R5 = 20 N
12
E, = 48 V
R2 = 40 N
a
e
13
0.20 N
R = 78 Q
f
13 = 0.05 N
E= 36 V
Ez = 6.0 V
g
hị
Transcribed Image Text:0.10 Ω E1 = 24 V + R, = 5.0 2 , = 0.5 Q 12 R5 = 20 N 12 E, = 48 V R2 = 40 N a e 13 0.20 N R = 78 Q f 13 = 0.05 N E= 36 V Ez = 6.0 V g hị
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