(0) Thẻ Legendre's polynomials are defined on the interval [-1,1]. They are orthogonal with respect to inner product (p,q) = | p(x)q(x)dx -1 The recursion relation for Chebychev polynomials is given by (n + 1)Pn+1(x) = (2n+ 1)xP,(x) – nPn-1 (x) given that Po(x) = 1, P1(x) = x. (i) Find linear least squares approximation to f(x) = e2x. (ii) Calculate the absolute error at x = 0.5. %3D
(0) Thẻ Legendre's polynomials are defined on the interval [-1,1]. They are orthogonal with respect to inner product (p,q) = | p(x)q(x)dx -1 The recursion relation for Chebychev polynomials is given by (n + 1)Pn+1(x) = (2n+ 1)xP,(x) – nPn-1 (x) given that Po(x) = 1, P1(x) = x. (i) Find linear least squares approximation to f(x) = e2x. (ii) Calculate the absolute error at x = 0.5. %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![(8) The Legendre's polynomials are defined on the interval [-1,1]. They are orthogonal with
respect to inner product
(p,q) = | p(x)q(x)dx
-1
The recursion relation for Chebychev polynomials is given by
(n+1)Pn+1(x) = (2n+ 1)xP,(x) – nPr-1 (x)
given that Po(x) = 1, P1(x) = x.
(i) Find linear least squares approximation to f(x) = e2x.
%3D
(ii) Calculate the absolute error at x = 0.5.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0a44e4ff-1ba1-406c-801b-9669a60ff7fb%2Fd3fef183-ee16-4f9b-86ab-297e4a1954fd%2Fhi4pfh5i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(8) The Legendre's polynomials are defined on the interval [-1,1]. They are orthogonal with
respect to inner product
(p,q) = | p(x)q(x)dx
-1
The recursion relation for Chebychev polynomials is given by
(n+1)Pn+1(x) = (2n+ 1)xP,(x) – nPr-1 (x)
given that Po(x) = 1, P1(x) = x.
(i) Find linear least squares approximation to f(x) = e2x.
%3D
(ii) Calculate the absolute error at x = 0.5.
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