0 ^ 6 m / s in a particle accelerator, and leaves it in a horizontal direction, entering a uniform magnetic field. What field perpendicular to the speed of the proton would cancel out the force of gravity and keep the beam moving exactly i
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A: Given: B=0.450 T (East)q=-3.10*10-18 Cv=0.30 cm/s =0.3*10-2 m/s (straight down in B field)
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A: velocity, v = 6 X 107 m/s magnetic field, B = 5 X 10-5 T
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A: Time taken to complete one revolution (T) = 0.80 μsparticle = proton
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A: Concept and Formulation: Using force balance, Centripetal Force = Force due to magnetic field Fc =…
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Q: A magnet produces a 0.50-T uniform field between its poles, directed to the east. A dust particle…
A: Magnetic field (B→) = 0.5 T i^Charge on dust particle (q) = -4×10-18 C Velocity of dust particle…
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A: radius of charge particle in spectrometer = R= mVqB
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Q: A proton, traveling with a velocity of 6.8 × 106 m/s due east, experiences a maximum magnetic force…
A: Given, velocity of proton V = 6.8 × 106 m/s due east maximum magnetic force = F = 8.0 × 10-14 N…
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A: The time will be 0.0368 seconds.
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A: Given that charge q=0.9 C magnetic field B=0.4T velocity v=700 m/s angle=90 deg.
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Q: A proton moving at 2.15 x 106 m/s through a magnetic field of magnitude 4.47 T experiences a…
A: Velocity of proton,(v)=2.15 x 106 m/sec -----(1) [Given] The magnetic field,(B)=4.47 T -----(2)…
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A: Given strength of magnetic field, B = 0.41 T Radius, R = 0.027 m Charge on proton = Q = 1.6 × 10-19…
Q: What is the force on an electron moving in the negative-z direction with a speed of 2.5 x 106 m/s in…
A: Given: The speed of the electron in the negative z-direction is v=2.5×106 m/s The magnetic field in…
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