.Use integration by parts to evaluate the following integrals: a) fx² In x dx b) S- x dx (Partial fraction)

Q: 2/7 + -4/3

A: Given,

Q: (4) y=x +4 -5 -4 -3 6.

A: The given equation is: y=x+4

Q: 1/3+2/9

A: Given 1/3 + 2/9

Q: (1-2=) dr

A:

Q: 5 3 4 x-3 x-2 x-3'

A: Given that 5/(x-3)-3/(x-2)=4/(x-3) To solve for x

Q: -2- 4- 3 10

A:

Q: V81x6 V3x3

A: Given expression is:  81x63x3 =81x63x3=27x6-3

Q: 6/7-2/3

A: our objective is to find the difference.

Q: 8 in images

A: It is an important part of statistics . It is widely used .

Q: 目 +8 LI +T 现 +04 +C4 |F|E|F|| ||||4 4 4 2 2

A:

Q: Let Mbe as in Equation (3.14) and let X = [1, 0, ½]¹. Show that the entries of Y=MX sum to 1.

A:

Q: 9.2 2 15 5 3 16

A:

Q: graph shows the relationship between the volume of the dilated box and the scale factor. diusuon 5.…

A:

Q: 0 1 2 4 0 2 4 0 0 3 9 12

A:

Q: 2(3+d-1)

A: Solve the given expression  given expression is 2(3+d-1)

Q: 1/4 +5/4

A: Solution: The objective is to find the value of the given expression

Q: 3. Identify all the cycles at each node of the directed graph above.

A: Cycle is defined as a path that start and end at the same vertex.

Q: -2(5a)

A: To evaluate-2(5a)

Q: limx→- f(x) limo+ f(x) limx→ = = =

A:

Q: (24) Half the product of a number t and 48

A: The objective is to half the product of a number t and 48.

Q: 10. 3 + Зу- 1 + у

A: Given that                     3+3y-1+y Now we simplify this.                           3+3y-1+y…

Q: X5 y / x4 y6

A: Given: x5yx4y6

Q: %3D 2. 416

A: See the details solution in below

Q: -5/9 + 1/2

A: The given expression is

Q: 8y3 + 216

A:

Q: limx→2 f(x) = lim, ¹x→−1+ f(x) =

A: Given graph of the function fx is   1. Find :  limx→2 fx. 2. Find :limx→-1+ fx.

Q: -3 -2 -1 1 2 0000000 3.

A:

Q: /2 2. 1/2

A: (a12+b12)(2a12-3b12)=2a12a12+2a12b12-3a12b12-3b12b12=2a+2a12b12-3a12b12-3b=2a-a12b12-3b

Q: -4 -2- 4 8

A: We are asked to find the horizontal asymptote and vertical asymptote. Horizontal asymptote (HA) - It…

Q: -2 -4 and D = 4 8

A:

Q: 3(m – 5) + m

A: 3(m-5)+m=0 3m-15+m=0 add both side 15 we get 2m=15

Q: AB 20

A: From the figure, we can see that triangle AXB and triangle AXC are congruent. If they are congruent…

Q: the series

A: