.Q11) The general solution of y"-4y' +9y = 0, is: a) y(t) = c₂e²t cos(5 t) + c₂e²t sin (5 t) c)y(t) = Cet cos(√5 t) + c₂e2t sin (√5 t) b)y(t) = ce cos(√5 t) + c₂e'sin (√5t) d) y(t)= ce cos(5 t) + c₂e'sin (5 t) Q12) The formula of the particular solution y of y(4) + 4y" = 3 sin(2t) - 5cos2t, is: a) yp= Asin(t) + Bcos(t) = c) yp Asin(2t) + Bcos(2t) b) yp Atsin(t) + Btcos(t) d) Y = Atsin(2t) + Btcos(2t)]
.Q11) The general solution of y"-4y' +9y = 0, is: a) y(t) = c₂e²t cos(5 t) + c₂e²t sin (5 t) c)y(t) = Cet cos(√5 t) + c₂e2t sin (√5 t) b)y(t) = ce cos(√5 t) + c₂e'sin (√5t) d) y(t)= ce cos(5 t) + c₂e'sin (5 t) Q12) The formula of the particular solution y of y(4) + 4y" = 3 sin(2t) - 5cos2t, is: a) yp= Asin(t) + Bcos(t) = c) yp Asin(2t) + Bcos(2t) b) yp Atsin(t) + Btcos(t) d) Y = Atsin(2t) + Btcos(2t)]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![.Q11) The general solution of y" - 4y' +9y = 0, is:
a) y(t) = c₂e²t cos(5 t) + c₂e2tsin (5 t)
c)y(t) = Cet cos(√5 t) + ₂e2t sin (√5 t)
b)y(t) = ce cos(√5 t) + c₂e¹sin (√5t)
d) y(t) = cet cos(5 t) + c₂e'sin (5 t)
Q12) The formula of the particular solution yp of y(4) + 4y" = 3 sin(2t) - 5cos2t, is:
a) Ур
=
Asin(t) + Bcos(t)
c) yp Asin(2t) + Bcos(2t)
b) yp = Atsin(t) + Btcos (t)
d) Yo=Atsin(2t) + Btcos(2t)]
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff642c1e3-2750-4de6-b32d-528cbede41a7%2F652fe6bf-1d20-483e-85eb-fd3f3fe05381%2Fhqmapvq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:.Q11) The general solution of y" - 4y' +9y = 0, is:
a) y(t) = c₂e²t cos(5 t) + c₂e2tsin (5 t)
c)y(t) = Cet cos(√5 t) + ₂e2t sin (√5 t)
b)y(t) = ce cos(√5 t) + c₂e¹sin (√5t)
d) y(t) = cet cos(5 t) + c₂e'sin (5 t)
Q12) The formula of the particular solution yp of y(4) + 4y" = 3 sin(2t) - 5cos2t, is:
a) Ур
=
Asin(t) + Bcos(t)
c) yp Asin(2t) + Bcos(2t)
b) yp = Atsin(t) + Btcos (t)
d) Yo=Atsin(2t) + Btcos(2t)]
=
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