.80 Water (p = 62.4 lbm/ft³) flows from the large orifice at the ottom of the tank as shown. Assume that the flow is irrotation oint B is at zero elevation, and point A is at 1 ft elevation. If A = 4 ft/s at an angle of 45° with the horizontal and if VÂ = 1 /s vertically downward, what is the value of PA - PB? Answer B Vertical A 45°
.80 Water (p = 62.4 lbm/ft³) flows from the large orifice at the ottom of the tank as shown. Assume that the flow is irrotation oint B is at zero elevation, and point A is at 1 ft elevation. If A = 4 ft/s at an angle of 45° with the horizontal and if VÂ = 1 /s vertically downward, what is the value of PA - PB? Answer B Vertical A 45°
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:**Problem 4.80**
Water (\(\rho = 62.4 \, \text{lbm/ft}^3\)) flows from the large orifice at the bottom of the tank as shown. Assume that the flow is irrotational. Point B is at zero elevation, and point A is at 1 ft elevation. If \(V_A = 4 \, \text{ft/s}\) at an angle of \(45^\circ\) with the horizontal and if \(V_B = 12 \, \text{ft/s}\) vertically downward, what is the value of \(p_A - p_B\)?
**Diagram Explanation:**
The diagram illustrates a tank with water flowing out from a large orifice at the bottom. Point A, located inside the tank, is at an elevation of 1 ft and has a velocity of 4 ft/s at a \(45^\circ\) angle to the horizontal. Point B is situated at the base of the tank at zero elevation with a downward velocity of 12 ft/s. The vertical axis is labeled, indicating direction.
**Given:**
- Density of water: \(\rho = 62.4 \, \text{lbm/ft}^3\)
- \(V_A = 4 \, \text{ft/s}\) at \(45^\circ\)
- \(V_B = 12 \, \text{ft/s}\) vertically downward
- Point A at 1 ft elevation
- Point B at zero elevation
The problem asks for the pressure difference (\(p_A - p_B\)) between points A and B.
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