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-.55 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input cur- rent is in the ladder circuit shown in Figure 2-53(a). SOLUTION: One approach is to combine parallel resistors and use voltage division to find no and then combine all resistances into a single equivalent to find the input current is. Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 2R and R resistors is Real- The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes needed to find the voltage no, nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as R 00-5 Rx2R 2 R+2R 3R R+R The input current is found by combining the equivalent resistance found previously. with the remaining resistor R to obtain REQ Uss 5 R+REQ -R-R- ls=- Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is 5 Ds 3 US RE 5 R 15 V Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage vo must be calculated before this reduction step is taken. ■ 330 ΩΣ ww N FIGURE P2-55 2013 38/3 FIGURE 2-53 (a) 100 mA w (b) SS 2-55 Use source transformation to find i, in Figure P2-55. 150 Ω W (0) Mus M

-.55 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input cur- rent is in the ladder circuit shown in Figure 2-53(a). SOLUTION: One approach is to combine parallel resistors and use voltage division to find no and then combine all resistances into a single equivalent to find the input current is. Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 2R and R resistors is Real- The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes needed to find the voltage no, nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as R 00-5 Rx2R 2 R+2R 3R R+R The input current is found by combining the equivalent resistance found previously. with the remaining resistor R to obtain REQ Uss 5 R+REQ -R-R- ls=- Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is 5 Ds 3 US RE 5 R 15 V Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage vo must be calculated before this reduction step is taken. ■ 330 ΩΣ ww N FIGURE P2-55 2013 38/3 FIGURE 2-53 (a) 100 mA w (b) SS 2-55 Use source transformation to find i, in Figure P2-55. 150 Ω W (0) Mus M

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2.55 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input cur rent is in the ladder circuit shown in Figure 2-53(a). SOLUTION: One approach is to combine parallel resistors and use voltage division to find no and then combine all resistances into a single equivalent to find the input current is. Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 28 and R resistors is Real- The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes. needed to find the voltage vo, nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as R DO 5 Dg= R+R Rx2R 2 - R R+2R The input current is found by combining the equivalent resistance found previously. with the remaining resistor R to obtain REQ2R+REQI =R- is = 2 5 US REG Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is = 15 V 05 3 US SR Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage vo must be calculated before this reduction step is taken. 330 Ω - (+ FIGURE P2-55 e is www A ZAYA 38/3 FIGURE 2-53 100 mA (a) Q (b) 2M (0) SS 2-55 Use source transformation to find i, in Figure P2-55. 150 (2 w Mugs Re
Transcribed Image Text:2.55 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input cur rent is in the ladder circuit shown in Figure 2-53(a). SOLUTION: One approach is to combine parallel resistors and use voltage division to find no and then combine all resistances into a single equivalent to find the input current is. Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 28 and R resistors is Real- The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes. needed to find the voltage vo, nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as R DO 5 Dg= R+R Rx2R 2 - R R+2R The input current is found by combining the equivalent resistance found previously. with the remaining resistor R to obtain REQ2R+REQI =R- is = 2 5 US REG Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is = 15 V 05 3 US SR Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage vo must be calculated before this reduction step is taken. 330 Ω - (+ FIGURE P2-55 e is www A ZAYA 38/3 FIGURE 2-53 100 mA (a) Q (b) 2M (0) SS 2-55 Use source transformation to find i, in Figure P2-55. 150 (2 w Mugs Re
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