.4. The approximate value of y=V4+sin.x at x=0.12, obtained from the tangent to the graph at x = 0, is (A) 2.00 (B) 2.03 (C) 2.06 (D) 2.12 (E) 2.24
.4. The approximate value of y=V4+sin.x at x=0.12, obtained from the tangent to the graph at x = 0, is (A) 2.00 (B) 2.03 (C) 2.06 (D) 2.12 (E) 2.24
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Chapter1: Functions
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Please do 14, 15, 17. Thank you for your help.
![14. The approximate value of y =V4+sinx at x= 0.12, obtained from the tangent to the graph at
x = 0, is
(A) 2.00
(В) 2.03
(C) 2.06
(D) 2.12
(E) 2.24
15. If f(x)=x +±, then the set of values for which ƒ increases is
(A) (-x, –1]U[1,∞)
(B) [-1,1]
(C) (-0,0)
(D) (0,0)
(E) (-x,0)U(0,∞)
16. If y = In(x² +y² ), then the value of
dy
at the point (1,0) is
dx
(A) 0
(В)
2
(С) 1
(D) 2
(E) undefined
17. Let g be a continuous function on the closed interval [0,1]. Let g(0) =1 and g(1) = 0. Which of
the following is NOT necessarily true?
(A) There exists a number h in [0,1] such that g(h) > g(x) for all x in [0,1].
(B) For all a and b in [0,1], if a =b, then g(a) = g(b).
(C) There exists a number h in [0,1] such that g(h) =-
3
(D) There exists a number h in [0,1] such that g(h)=
2
(E) For all h in the open interval (0,1), lim g(xr) = g(h).
x→h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1f6dc48-cadc-40dc-963c-1211dbb4eb52%2F95f81f8d-32d6-465c-b08c-c684f48ec212%2Ff4m28a_processed.png&w=3840&q=75)
Transcribed Image Text:14. The approximate value of y =V4+sinx at x= 0.12, obtained from the tangent to the graph at
x = 0, is
(A) 2.00
(В) 2.03
(C) 2.06
(D) 2.12
(E) 2.24
15. If f(x)=x +±, then the set of values for which ƒ increases is
(A) (-x, –1]U[1,∞)
(B) [-1,1]
(C) (-0,0)
(D) (0,0)
(E) (-x,0)U(0,∞)
16. If y = In(x² +y² ), then the value of
dy
at the point (1,0) is
dx
(A) 0
(В)
2
(С) 1
(D) 2
(E) undefined
17. Let g be a continuous function on the closed interval [0,1]. Let g(0) =1 and g(1) = 0. Which of
the following is NOT necessarily true?
(A) There exists a number h in [0,1] such that g(h) > g(x) for all x in [0,1].
(B) For all a and b in [0,1], if a =b, then g(a) = g(b).
(C) There exists a number h in [0,1] such that g(h) =-
3
(D) There exists a number h in [0,1] such that g(h)=
2
(E) For all h in the open interval (0,1), lim g(xr) = g(h).
x→h
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