A company wants to test the claim that their batteries last more than 40 hours. Using a simple random sample of 18 batteries yielded the following battery life: 35 54 36 50 53 42 37 51 37 40 55 45 45 42 52 45 39 47 Test this claim using a significance level of 0.01. What is the value of t-critical? (Answer in 2 decimal place) Your answer What is the test statistic? (Answer in 1 decimal place) Your answer What is the decision? Reject the null hypothesis O Fail to reject the null hypothesis

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Chapter1: Starting With Matlab
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A company wants to test the claim that their batteries last more than 40 hours. Using a simple random
sample of 18 batteries yielded the following battery life:
35 54 36
50 53 42
37 51 37
40 55 45
45 42 52
45 39 47
Test this claim using a significance level of 0.01.
What is the value of t-critical? (Answer in 2 decimal place)
Your answer
What is the test statistic? (Answer in 1 decimal place)
Your answer
What is the decision?
Reject the null hypothesis
Fail to reject the null hypothesis
Transcribed Image Text:A company wants to test the claim that their batteries last more than 40 hours. Using a simple random sample of 18 batteries yielded the following battery life: 35 54 36 50 53 42 37 51 37 40 55 45 45 42 52 45 39 47 Test this claim using a significance level of 0.01. What is the value of t-critical? (Answer in 2 decimal place) Your answer What is the test statistic? (Answer in 1 decimal place) Your answer What is the decision? Reject the null hypothesis Fail to reject the null hypothesis
What is the null hypothesis?
What is the alternative hypothesis?
Ho μ < 40
Ho: µ < 40
Ho μ- 40
Ha σE 40
Ο H: μΕ 18
H: σ< 40
Ο Hμ#40
H: μ= 40
Ο H& σ= 40
H: σ> 18
Ο H: μ 18
H: μ= 18
Hi: μ > 40
H: μ+ 18
Ο H: μ< 40
H:: p > 18
Ο H: μέ 18
H μ>18
H: σ< 40
Ho: H # 40
Ο H: σ> 18
Ha: σ 18
Ho: μ >18
H:: μ< 40
H: μ= 40
Ho μ- 40
Ο H& σ= 18
H: μ > 40
Ο Hεμε 18
H μ= 18
|
Transcribed Image Text:What is the null hypothesis? What is the alternative hypothesis? Ho μ < 40 Ho: µ < 40 Ho μ- 40 Ha σE 40 Ο H: μΕ 18 H: σ< 40 Ο Hμ#40 H: μ= 40 Ο H& σ= 40 H: σ> 18 Ο H: μ 18 H: μ= 18 Hi: μ > 40 H: μ+ 18 Ο H: μ< 40 H:: p > 18 Ο H: μέ 18 H μ>18 H: σ< 40 Ho: H # 40 Ο H: σ> 18 Ha: σ 18 Ho: μ >18 H:: μ< 40 H: μ= 40 Ho μ- 40 Ο H& σ= 18 H: μ > 40 Ο Hεμε 18 H μ= 18 |
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