... 5.21 In Section 5.1.4, it was commented that g does change with altitude. The formula for g as function of altitude h above the surface of the Earth is GME (5.42) (RE + h)2 = 5.976 x 1024 kg 6378 km is the radius of the earth. What is the per cent change in g experienced by a plane that takes off from sea level and ascends to an altitude of 30, 000 ft? What altitude would be required for there to where G = 6.67 × 10-11 N-m² /kg² is a universal constant, ME is the mass of the Earth, and RE be a percent difference ing of 5%?

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Only question 5.21!!!
erminal
speet!
If your answer is, “Yes," provide an example; if your answer is, “No," explain why
5.19 Suppose a ball of radius 1.0 m and mass 1.0 kg falls and reaches a terminal
not.
cruisin
5.27
352 ft
(air de
drop to
in order
in order
..
speed of 25 m/s. What is the drag coefficient of the ball? (For the
determining the air density, assume the ball is at approximately sea level dur
the fall, where the air density is 1.225 kg/m³.) What net force acts on the b
when it is at half its terminal speed?
purpose of
5.20 Suppose you are designing a parachute with a drag coefficient of 0.5. What 352 ft/s
cross-sectional area should the parachute have if it is to provide a typical pilot t (air d
with a terminal speed of 10 mph?
" 5.28
..
to drop
decide t.
5.21 In Section 5.1.4, it was commented that g does change with altitude. The just long
...
formula for
as function of altitude h above the surface of the Earth is
how muc
GME
- 5.29
(5.42)
the plane
Ib of fuel
g =
(RE + h)2'
where G = 6.67 x 10-11 N-m² /kg² is a universal constant, MẸ = 5.976 × 104 kg
is the mass of the Earth, and Rp = 6378 km is the radius of the earth. What is
the per cent change in g experienced by a plane that takes off from sea level and
ascends to an altitude of 30, 000 ft? What altitude would be required for there to
be a percent difference in g of 5%?
at what
change;
thrust ch
5.30 A
ft/s at ar
denser pC
Yoasia odt o q
5.22 Given the equation for g in the previous problem, what is the acceleratiol
due to gravity on the surface of Mars?
the previe
coefficient
density, i
thrust cha
00.0l
Section 5.2
... 5.23 Here's a challenging one: Employing trigonometry identities, show that
Eqs. (5.15) and (5.16) are equivalent to Eqs. (5.17) and (5.18).
Section 5.3
* 5.31 Y
oriented a
+5.0°. W
ight
5.24 Show that, for cruising flight, th
equal the drag-to-lift ratio Cp/C
must
ratio is 5.
Transcribed Image Text:erminal speet! If your answer is, “Yes," provide an example; if your answer is, “No," explain why 5.19 Suppose a ball of radius 1.0 m and mass 1.0 kg falls and reaches a terminal not. cruisin 5.27 352 ft (air de drop to in order in order .. speed of 25 m/s. What is the drag coefficient of the ball? (For the determining the air density, assume the ball is at approximately sea level dur the fall, where the air density is 1.225 kg/m³.) What net force acts on the b when it is at half its terminal speed? purpose of 5.20 Suppose you are designing a parachute with a drag coefficient of 0.5. What 352 ft/s cross-sectional area should the parachute have if it is to provide a typical pilot t (air d with a terminal speed of 10 mph? " 5.28 .. to drop decide t. 5.21 In Section 5.1.4, it was commented that g does change with altitude. The just long ... formula for as function of altitude h above the surface of the Earth is how muc GME - 5.29 (5.42) the plane Ib of fuel g = (RE + h)2' where G = 6.67 x 10-11 N-m² /kg² is a universal constant, MẸ = 5.976 × 104 kg is the mass of the Earth, and Rp = 6378 km is the radius of the earth. What is the per cent change in g experienced by a plane that takes off from sea level and ascends to an altitude of 30, 000 ft? What altitude would be required for there to be a percent difference in g of 5%? at what change; thrust ch 5.30 A ft/s at ar denser pC Yoasia odt o q 5.22 Given the equation for g in the previous problem, what is the acceleratiol due to gravity on the surface of Mars? the previe coefficient density, i thrust cha 00.0l Section 5.2 ... 5.23 Here's a challenging one: Employing trigonometry identities, show that Eqs. (5.15) and (5.16) are equivalent to Eqs. (5.17) and (5.18). Section 5.3 * 5.31 Y oriented a +5.0°. W ight 5.24 Show that, for cruising flight, th equal the drag-to-lift ratio Cp/C must ratio is 5.
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