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.. initial acid concentration is 0.042mol/L Calculate the initial [H,0'] in mol/L in the weak acid sample using the initial pH measurement. Show all work. Given: Initial pH = 3.30 pH = -log(H30'] can be used [H30*] = 10PH M (H30°] = 103.30M [H30"] = 5.0119 x 10“ M .. Initial (H30°] is 5.01 x 104 mol/L

.. initial acid concentration is 0.042mol/L Calculate the initial [H,0'] in mol/L in the weak acid sample using the initial pH measurement. Show all work. Given: Initial pH = 3.30 pH = -log(H30'] can be used [H30*] = 10PH M (H30°] = 103.30M [H30"] = 5.0119 x 10“ M .. Initial (H30°] is 5.01 x 104 mol/L

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the data from questions 3 and 4, calculate the experimental value of K, for this unknown acid using an ICE table.
Transcribed Image Text:Using the data from questions 3 and 4, calculate the experimental value of K, for this unknown acid using an ICE table.
Given: V of unknown acid = 0.25L V of 0.1M NAOH = 0.105L HA (ag) + NaOH (ag) -> NaA (aq) + H20) meaning its a 1:1 reaction Vi*Sı = V2*S2 can be used Cunknown acid = (0.105L x 0.1mol/L) / (0.25L) = 0.042mol/L initial acid concentration is 0.042mol/L Calculate the initial [H,O'] in mol/L in the weak acid sample using the initial pH measurement. Show all work. Given: Initial pH = 3.30 pH = -log(H30*] can be used [H30*] = 10PH M [H30°] = 103.30M [H30*] = 5.0119 x 10“ M .. Initial [H30*] is 5.01 x 104 mol/L
Transcribed Image Text:Given: V of unknown acid = 0.25L V of 0.1M NAOH = 0.105L HA (ag) + NaOH (ag) -> NaA (aq) + H20) meaning its a 1:1 reaction Vi*Sı = V2*S2 can be used Cunknown acid = (0.105L x 0.1mol/L) / (0.25L) = 0.042mol/L initial acid concentration is 0.042mol/L Calculate the initial [H,O'] in mol/L in the weak acid sample using the initial pH measurement. Show all work. Given: Initial pH = 3.30 pH = -log(H30*] can be used [H30*] = 10PH M [H30°] = 103.30M [H30*] = 5.0119 x 10“ M .. Initial [H30*] is 5.01 x 104 mol/L
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