. Two point charges, +3 C and -6 C, are separated by 20 cm. They are NOT free to move. K = 9X10^9. a) What is the magnitude of the electrostatic (Coulomb) force between the charges? b) What is the electric field at the center point between the two charges? c) What is the electric potential at the center point between the two charges?
. Two point charges, +3 C and -6 C, are separated by 20 cm. They are NOT free to move. K = 9X10^9. a) What is the magnitude of the electrostatic (Coulomb) force between the charges? b) What is the electric field at the center point between the two charges? c) What is the electric potential at the center point between the two charges?
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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Question
![**Topic: Electrostatics and Coulomb's Law**
**Problem Statement:**
Two point charges, +3 C and -6 C, are separated by 20 cm. They are NOT free to move. The Coulomb constant, \( K \), is \( 9 \times 10^9 \, \text{N·m}^2/\text{C}^2 \).
**Questions:**
**a) What is the magnitude of the electrostatic (Coulomb) force between the charges?**
**b) What is the electric field at the center point between the two charges?**
**c) What is the electric potential at the center point between the two charges?**
**Detailed Explanations:**
For multiple parts of this problem:
1. **Electrostatic Force Calculation:**
- The magnitude of the electrostatic force between two point charges can be calculated using Coulomb's Law:
\[
F = \frac{K \cdot |q_1 \cdot q_2|}{r^2}
\]
where \( K \) is the Coulomb constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between them.
2. **Electric Field Calculation:**
- The electric field at a point due to a point charge is given by:
\[
E = \frac{K \cdot |q|}{r^2}
\]
The resultant electric field at a given point is the vector sum of the electric fields due to individual charges.
3. **Electric Potential Calculation:**
- The electric potential at a point due to a point charge is given by:
\[
V = \frac{K \cdot q}{r}
\]
The total electric potential is the algebraic sum of the potentials due to individual charges because electric potential is a scalar quantity.
**Refer to appropriate sections for the detailed solutions of each part.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6746fa6f-1856-443b-addc-ecae5d9da9b9%2F080e19fb-9665-46df-8c97-62de96f1cd67%2F9mgs9b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Topic: Electrostatics and Coulomb's Law**
**Problem Statement:**
Two point charges, +3 C and -6 C, are separated by 20 cm. They are NOT free to move. The Coulomb constant, \( K \), is \( 9 \times 10^9 \, \text{N·m}^2/\text{C}^2 \).
**Questions:**
**a) What is the magnitude of the electrostatic (Coulomb) force between the charges?**
**b) What is the electric field at the center point between the two charges?**
**c) What is the electric potential at the center point between the two charges?**
**Detailed Explanations:**
For multiple parts of this problem:
1. **Electrostatic Force Calculation:**
- The magnitude of the electrostatic force between two point charges can be calculated using Coulomb's Law:
\[
F = \frac{K \cdot |q_1 \cdot q_2|}{r^2}
\]
where \( K \) is the Coulomb constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between them.
2. **Electric Field Calculation:**
- The electric field at a point due to a point charge is given by:
\[
E = \frac{K \cdot |q|}{r^2}
\]
The resultant electric field at a given point is the vector sum of the electric fields due to individual charges.
3. **Electric Potential Calculation:**
- The electric potential at a point due to a point charge is given by:
\[
V = \frac{K \cdot q}{r}
\]
The total electric potential is the algebraic sum of the potentials due to individual charges because electric potential is a scalar quantity.
**Refer to appropriate sections for the detailed solutions of each part.**
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