. Two incompressible viscous fluids of the same density p flow, one on top of the other, down an inclined plane making an angle a with the horizontal. Their viscosities are µi and µ2, the lower fluid is of depth hị and the upper fluid is of depth hy. Show that: u(y) =| (h] +h2)y –- ,2 gsin a so that the velocity of the lower fluid u1(y) is dependent on the depth h2, but not the viscosity, of the upper fluid. Why is this?
. Two incompressible viscous fluids of the same density p flow, one on top of the other, down an inclined plane making an angle a with the horizontal. Their viscosities are µi and µ2, the lower fluid is of depth hị and the upper fluid is of depth hy. Show that: u(y) =| (h] +h2)y –- ,2 gsin a so that the velocity of the lower fluid u1(y) is dependent on the depth h2, but not the viscosity, of the upper fluid. Why is this?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:2. Two incompressible viscous fluids of the same density p flow, one on top of the other,
down an inclined plane making an angle a with the horizontal. Their viscosities are µi
and µ2, the lower fluid is of depth hị and the upper fluid is of depth h2. Show that:
u,(y) =
(hj +h2.
2
(t)-
)y -
1
2 gsin a
V1
so that the velocity of the lower fluid u¡(y) is dependent on the depth h2, but not the
viscosity, of the upper fluid. Why is this?
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