.TOTAL DEFLECTION at JOINT H OF THE TRUSS SHOWN BELOW. CROSS SECTIONAL AREASMEMBER GRE SHOWN. E 200 GPG AND THE SAME200KNG(wwoosz)327 kN D(2500 mm²)A(1300 mm)(1500mm²)(1600mm²)A(1500mm²)(1500mm²)2m(wwODSH)B(1500 mm²)1500 mm")E = 200 GPaFOR ALL MEMBERS.200KN2m(1500 mm²)H(2500 mm²)(2500 mm ²4m4mOF EACH

Answered: Image /qna-images/answer/4ccaba95-206a-4fd1-ad89-e48b4cce1ba4.jpg

. TOTAL DEFLECTION at JOINT H OF THE TRUSS SHOWN BELOW. CROSS SECTIONAL OREGS MEMBER GRE SHOWN. E= 200 GPG AND THE SOME 200KN (2500mm²) 327KN -D (2500 mm²) A (1500mm) (1500mm²) (1600mm³) (1500mm²) (1500mm²) 2m (wmoder) B (1500 mm²) (1500 mm) E = 200 GPa FOR ALL MEMBERS. 200KN 2m (1500 mm²) H (2500 mm³) F LL (2500 mm ²) 4m 4m OF EACH

. TOTAL DEFLECTION at JOINT H OF THE TRUSS SHOWN BELOW. CROSS SECTIONAL OREGS MEMBER GRE SHOWN. E= 200 GPG AND THE SOME 200KN (2500mm²) 327KN -D (2500 mm²) A (1500mm) (1500mm²) (1600mm³) (1500mm²) (1500mm²) 2m (wmoder) B (1500 mm²) (1500 mm) E = 200 GPa FOR ALL MEMBERS. 200KN 2m (1500 mm²) H (2500 mm³) F LL (2500 mm ²) 4m 4m OF EACH

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: ACTIVITY 5- Truss Analysis Analyze the loaded truss as shown. Be guided as follows: a. Solve for the…

Q: E=160 GPa I= 65.0*106mm4 What is the slope and deflection at the end of the beam?

A: Given,

Q: For a 200 mm x 200 mm beam shown below with E = 20 GPa, select in the choices %3D the value that…

A: Given that; Size of the beam=200 mm×200 mm E=20 GPaFinding Reactions and…

Q: Determine the deflection at midpoint between the supports A and B for the beam loaded as shown in…

A: ##Calculation of deflection at Mid point of A and B support using Unit load method ####

Q: The 9m beam in figure 05 is loaded as shown. The location of maximum deflection measured from the…

A: Reaction calculation:Ra+Rb=0.5×2×9=9kNMoment about A =0Rb×9-9×23×9=09Rb=54Rb=6kNRa=3kN Rate of…

Q: = 1m = 33 KN/m = 3.3 x 108 mm4 = 200 GPa 3 -L-

Q: For the beam and loading shown in Fig.4, determine the deflection at Knowing that flexural rigidity…

Q: Part (B) Determine the deflection at the free end of the beam shown in Fig. using conjugate beam…

Q: 2 By using Conjugate BeamMethod, Determine the deflection at the free end of the beamshown 180 kN 15…

A: In conjugate beam what we do is draw conjugate beam for given real beam then we have to draw BM…

Q: beam at C. Assume a constant value of El = 29 x 106 lb-ft² for the beam; wo = 7100 lb/ft, LAB = 4.5…

Q: DETERMINE THE DEFLECTION AT POINT D OF THE BEAM SHOWN.

A: I1 = 16 ×108 mm4 I2 = 12 × 108 mm4 E = 210GPa = 2.1 × 105 N/mm2

Q: 1. Determine the deflection at joint 3 (i.e., Azv) for the following truss, assume that EA is…

A: Draw FBD:

Q: Determine the maximum deflection for the beam shown by the moment-area method

A: Draw the free-body diagram of the beam.

Q: Problem: The beam has a given cross section as shown. fc = 9.8 MPa, fs = 138 MPa, n = Determine the…

A: Given: Characteristic strength of concrete fc = 9.8 Mpa Characteristic strength of steel fst = 138…

Q: 200KN TookN 5m 10m 2I E> CONSTANT =250 GPa I> GO0(10°) mm4 %3D

Q: Structures, i need solutions it's my (H.W) Q/For the truss shown, find vertical deflection at (d) by…

A: Let,RA=vertical reaction at AHA=horizontal rection at ARB=vertical reaction at Busing equilibrium…

Q: A2=600mm? A3=200mm? A1=300mm? 2P 5P 6P 250mm 500mm 300mm

Q: beam of length 6m is supported at its ends and carries UDL 0f intensity (25+33 kN/m) as shown in…

A: Solution; Given data; The length of beam AB is given as 6 m. But the sum of AB, CD, DB is 8 m. So,…

Q: 6. A cantilever beam subjected to uniform variable load, if the beam is made of I Beam having a…

A: In cantilever beam, maximum deflection will occur at free end (point B). By using virtual work…

Q: Given E = 29000 ksi, the cross-section area of the top and bottom chord members = 1500mm^2 and o the…

Q: Use moment area for the beam Find the following: 16K (a) Deflection at C A (b) Rotation at A (c)…

Q: Shear force acting on section H in the figure Shear stress y when T = 50 kN acts Draw the…

A: Shear stress is generally created either due to the change and the bending moment or due to change…

Q: Determine the horizontal deflection at joint B of the truss shown. There's a temperature drop of 15…

Q: in mm ) Solue for the deflectiom e the miáspan using vwM lookN 20 kal /m E = 2006 Pa Cross section…

Q: Calculate the forces of the elements Ad Af and Fd of the lattice system. 100 N 100 N 2 m 50 N D F C…

A: ∑FX=050ℕ+RAX=0,RAX=-50ℕ∑MA=050×2+RB×3+100×1.5=0RB=-83.33Kn (Compressive)∑Fy=0RA=-116.67Kn…

Q: The bar composed of aluminum was sustained by the 14 mm2 cross-sectional area of the pin-connected…

A: The given data is shown below: Cross-sectional area=14 mm2E=68.9×109 Pa

Q: Derive an expression for the maximum value of deflection for the simply supported beam

A: Given:A simply supported beam carrying concentrated load at a distance 'a' from hinge support and b…

Q: For the beam shown, find () to mak. Pz. The deflection at c equal to Zuro ? P2 hinge 售山

A: In conjugate beam, Free end becomes free end free end becomes fixed end intermediate roller becomes…

Q: In the restrained beam shown, solve for the following a. end moments b. max deflection note: use…

Q: 600 N/m 600 N/m 2 m 1 m 2 m R1 R2 Find the deflection at mid-span Y = 1/EI*(3350) %3D

A: To find the deflection at mid span-

Q: 2.28 Each of the four vertical links connecting the two rigid horizontal members is made of aluminum…

Q: A rigid beam BC is suspended by links AB and CD. Determine the deflection at point E if the areas…

A: Given: The modulus of elasticity is 200 GPa. The area is 150 mm2.

Q: Determine the slope and deflection at point B of the steel beam shown. The reactions have been…

A: Consider the free body diagram of the given beam as shown below. Concentrated load, W=5 k Total…

Q: (1162) Determine the midspan deflection for the beam and I = 15 x 10² min ² GooN/m 3m 3m shown? use…

Q: Solve the maximum deflections using method of superposition and draw shear and moment diagram

Q: Q4. The load Q is gradually increased from zero to 120KN. a) Does failure occur in bars BE and BD?…

A: Question is based on the rigid bar supported by two links . Area of cross section of bars , Modulus…

Q: Both portions of rod ABC are made of aluminum for which E 70 MPa. Knowing that the magnitude of P 6…

A: Given,P=6 KNE=70 MpaL1=0.4mL2=0.5mA1=π4d2A2=π40.062Q=42 KN

Q: Calculate the value of the deflection at point B due to concentrated load P in the form Calculate…

A: Given: Required: Deflection at B due to concentrated load P Reaction at D Reaction at A Note:As…

Q: Both portions of the rod ABC are made of an aluminum for which E = 70 GPa. 0.4 m 0.5 m B C 20-mm…

A: Objective: To determine the value of load Q, such that the deflection at A is zero. Given: P = 59…

Q: Determine the maximum deflection for the beams shown in Fig. below:

A: Use double integration method

Concept explainers

British Gravitational Bg System Of Units

Measuring is the comparison of a particular physical quantity with its reference value. A unit is a fixed physical quantity. The length is a physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with. 

Question

.
TOTAL DEFLECTION at JOINT H OF THE TRUSS SHOWN BELOW. CROSS SECTIONAL AREAS
MEMBER GRE SHOWN. E 200 GPG AND THE SAME
200KN
G
(wwoosz)
327 kN D
(2500 mm²)
A
(1300 mm)
(1500mm²)
(1600mm²)
A
(1500mm²)
(1500mm²)
2m
(wwODSH)
B
(1500 mm²)
1500 mm")
E = 200 GPa
FOR ALL MEMBERS.
200KN
2m
(1500 mm²)
H
(2500 mm²)
(2500 mm ²
4m
4m
OF EACH

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Step by step

Solved in 7 steps with 7 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Determine the maximum deflection for the beam shown. 40 k 60 k B с 10 ft 10 ft 10 ft I 21 I E = constant = 29,000 ksi I = 1,000 in.*
The cantilever beam shown having a property of E= 200 gPa and I = 125 x 106 mm4. Determine the the deflection in mm when x = 4.0 m Where: w= 96 kN/m, a = 1.2 m, L = 5 m A X₂ W L B
In the restrained beam shown, solve for the following a. end moments b. max deflection note: use double integration method 3 kN /m 15KN 1m マク Im
that will limit the maximum deflection to 20 mm. Use E = 10 x 10 \Flgure P-645. A For the beam shown in Fig. P-646, determine the value of I %3D N/m?. Saut 600 N/m free end 1 m 2m 1 m Flgure P-646.
The 100 N block hits the simply supported beam at its mid span after a drop of 10mm as shown in the figure, consider flexural rigidity of the beam as 1728N-m². The dynamic deflection (in mm) at mid span is (a) 6.86 (c) 4.38 100N W 0.6m 10mm 0.6m (b) 8.86 (d) 6.34
Use AREA MOMENT METHOD to Determine the following: A central beam BD is joined at hinges to two cantilever beams AB and DE. All beams have the cross-section shown. For the loading shown, determine the largest w so that the deflection at C does not exceed 3mm. Use E=200 GPa. w 12 mm A C D E Hinge' Hinge 24 mm 0.4 m 0.4 m 0.4 m 0.4 m
The 100 N block hits the simply supported beam at its mid span after a drop of 10mm as shown in the figure, consider flexural rigidity of the beam as 1728N-m². The dynamic deflection (in mm) at mid span is 100N W 0.6m 10mm 0.6m
Determine the deflection by double integration at the middle of the simply supported beam shown. 10 kip R₁ PIE 3 ft 3 ft 1.5 kip/ft 6 ft R₂
A rigid bar AB is hinged at A and is supported by a rod CD at C. The rod is pin connected at D, as shown. Neglect deflections of the bar due to bending. Use E-200 GPa. How much will rod CD elongate due to the load at B?
Determine the deflection at joint B. Members have the same moment of inertia of 1440 x 10^4 cm^4 and E is constant at 210 GPa Using Unit load Method 100kN/m B P= 279 kN 100kN/m A 4m iP in kN 3m 5m
A load 600kN applied at point A, as shown in fig above, produces a vertical deflection at A, B and C of the beam as Ab = 10mm and Ac = 15mm respectively. What is the deflection at A when loads of 200 kN and 400kN are applied at B & C, respectively. 600KN ΕΙ + B 2L/3 A 2EI + C *4 L/3
1: Both portions of the rod ABC are made of an aluminum for which E= 70 GPa. Knowing that the magnitude of P is 4 kN and Q is 16.8 KN check the deflection at A. C 20 mm diameter 0.4 m 40 min diameter 0.5 m 199