. The space between the plates of a parallel-plate capacitor is filled with two slabs of linear dielectric material. Each slab has thickness 2a, so the total distance between the plates is 4a. Slab 1 has a dielectric constant of 2, and slab 2 has a dielectric constant of 1.5. The free charge density on the top plate is o and on the bottom plate -a. a. Find the electric displacement D in each slab. b. Find the clectric field E in each slab. Find the polarization P in each slab. Find the potential difference between the plates. Find the location and amount of all bound charge. f. Now that you know all the charge (free and bound), recalculate the field in each slab, and confirm your answer to (b).
. The space between the plates of a parallel-plate capacitor is filled with two slabs of linear dielectric material. Each slab has thickness 2a, so the total distance between the plates is 4a. Slab 1 has a dielectric constant of 2, and slab 2 has a dielectric constant of 1.5. The free charge density on the top plate is o and on the bottom plate -a. a. Find the electric displacement D in each slab. b. Find the clectric field E in each slab. Find the polarization P in each slab. Find the potential difference between the plates. Find the location and amount of all bound charge. f. Now that you know all the charge (free and bound), recalculate the field in each slab, and confirm your answer to (b).
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![. The space between the plates of a parallel-plate capacitor is filled with two slabs of linear
dielectric material. Each slab has thickness 2a, so the total distance between the plates is 4a.
Slab 1 has a dielectric constant of 2, and slab 2 has a diclectric constant of 1.5. The free charge
density on the top plate is o and on the bottom plate -o.
a. Find the electric displacement D in each slab.
b. Find the electric field E in each slab.
Find the polarization P in each slab.
Find the potential difference between the plates.
Find the location and amount of all bound charge.
f. Now that you know all the charge (free and bound), recalculate the field in each slab,
and confirm your answer to (b).
2a
Slab |
Slab 2
2a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90ef91e4-d2e8-4f96-bc2e-3c5843895647%2F99981bc2-a1e7-425c-b310-a97cefe00eaa%2F6jiiqqq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:. The space between the plates of a parallel-plate capacitor is filled with two slabs of linear
dielectric material. Each slab has thickness 2a, so the total distance between the plates is 4a.
Slab 1 has a dielectric constant of 2, and slab 2 has a diclectric constant of 1.5. The free charge
density on the top plate is o and on the bottom plate -o.
a. Find the electric displacement D in each slab.
b. Find the electric field E in each slab.
Find the polarization P in each slab.
Find the potential difference between the plates.
Find the location and amount of all bound charge.
f. Now that you know all the charge (free and bound), recalculate the field in each slab,
and confirm your answer to (b).
2a
Slab |
Slab 2
2a
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