. Let a > 0 be a (fixed) real number. (a) Using lower and upper Riemann sums for n≥ 1, we have 1° +2° +...+(n-1) < ["ha (b) Using part (a), or otherwise, prove that 1a + 2a +. na+1 on S xadx, prove that for any integer 0 lim n→∞ xadx ≤ 1ª + 2ª +...+na. + na 1 a + 1

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