. Give the complete electron flow of the Sy2 reaction, be sure to clearly show the electrons that are flowing. LOK Br CH3CH2CH,CH,OH + KBr . Give the complete electron flow of the E2 reaction, be sure to clearly show the electrons that are flowing. Br LOK + CH3CH2CH2CH2OH + KBr HO

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter12: Chirality
Section: Chapter Questions
Problem 23CTQ
icon
Related questions
Question
**1. SN2 Reaction:**

- **Description:** The first reaction is an SN2 (bimolecular nucleophilic substitution) reaction. 
- **Reactants:** 
  - A linear molecule with an -OK (potassium alkoxide) group.
  - A molecule with a bromine (Br) atom attached to it, represented by "CH3CH2CH2CH2OH".
- **Products:**
  - A new linear molecule with an oxygen bridge (ether) formed by replacing the bromine atom.
  - Potassium bromide (KBr).

- **Electron Flow:** 
  - The nucleophile (-OK) attacks the carbon atom bonded to the bromine from the opposite direction of the Br group, leading to the displacement of the bromine atom and formation of the new C-O bond.

**2. E2 Reaction:**

- **Description:** The second reaction is an E2 (bimolecular elimination) reaction.
- **Reactants:** 
  - A linear molecule with an -OK group.
  - A molecule with a bromine (Br) atom attached in a branching structure.
- **Products:**
  - An alkene formed by the elimination of a hydrogen and bromine to create a double bond.
  - A new alcohol with the structure "CH3CH2CH2CH2OH".
  - Potassium bromide (KBr).

- **Electron Flow:**
  - The base (-OK) abstracts a proton (H) adjacent to the brominated carbon, facilitating the elimination of the bromine atom and the formation of a carbon-carbon double bond (alkene).

Both examples illustrate fundamental organic chemistry mechanisms involving the flow of electrons that lead to substitution and elimination reactions.
Transcribed Image Text:**1. SN2 Reaction:** - **Description:** The first reaction is an SN2 (bimolecular nucleophilic substitution) reaction. - **Reactants:** - A linear molecule with an -OK (potassium alkoxide) group. - A molecule with a bromine (Br) atom attached to it, represented by "CH3CH2CH2CH2OH". - **Products:** - A new linear molecule with an oxygen bridge (ether) formed by replacing the bromine atom. - Potassium bromide (KBr). - **Electron Flow:** - The nucleophile (-OK) attacks the carbon atom bonded to the bromine from the opposite direction of the Br group, leading to the displacement of the bromine atom and formation of the new C-O bond. **2. E2 Reaction:** - **Description:** The second reaction is an E2 (bimolecular elimination) reaction. - **Reactants:** - A linear molecule with an -OK group. - A molecule with a bromine (Br) atom attached in a branching structure. - **Products:** - An alkene formed by the elimination of a hydrogen and bromine to create a double bond. - A new alcohol with the structure "CH3CH2CH2CH2OH". - Potassium bromide (KBr). - **Electron Flow:** - The base (-OK) abstracts a proton (H) adjacent to the brominated carbon, facilitating the elimination of the bromine atom and the formation of a carbon-carbon double bond (alkene). Both examples illustrate fundamental organic chemistry mechanisms involving the flow of electrons that lead to substitution and elimination reactions.
Expert Solution
Step 1

SN2 reaction is a single step nucleophilic substitution reaction. The rate of reaction is dependent on nucleophile and reactant.

E2 elimination is a single step elimination reaction. The rate of reaction is dependent on reactant as well as base.

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning