. Evaluate each sum. You may use the following formulas: n(n + 1) η Σκ= 2 k=1 n Σκ k=1 = n(n + 1)(2n + 1) 6 n Σ( + 8)(k – 8) = k=1 36 Σ(1)* = k=0
. Evaluate each sum. You may use the following formulas: n(n + 1) η Σκ= 2 k=1 n Σκ k=1 = n(n + 1)(2n + 1) 6 n Σ( + 8)(k – 8) = k=1 36 Σ(1)* = k=0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:. Evaluate each sum. You may use the following formulas:
n(n + 1)
n
Σκ= 2
k=1
n
Σκ
k=1
=
n(n + 1)(2n + 1)
6
n
Σ( + 8)(k – 8) =
k=1
36
Σ(-1)* =
k=0
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