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. Bronze pipe (1) has an elastic modulus of E1 16,000 ksi, a cross-sectional area of A1 2.68 in m alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.08 in. nserted in the flanges and tightened so that the gap at B is closed, determine: produced in each of the members. flange B with respect to support A. %3D

. Bronze pipe (1) has an elastic modulus of E1 16,000 ksi, a cross-sectional area of A1 2.68 in m alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.08 in. nserted in the flanges and tightened so that the gap at B is closed, determine: produced in each of the members. flange B with respect to support A. %3D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.20 in. exists between the two pipes. Bronze pipe (1) has an elastic modulus of E1 = 16,000 ksi, a cross-sectional area of A1 = 2.68 in.2, and a length of L1 = 6.8 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.08 in.2, and a length of L2 = 9.2 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses produced in each of the members. (b) the final position of flange B with respect to support A. %3D %3D %3D L1 L2 В Cl (2) (1) Answer: (a) 01= ksi ksi 02= (b) бв/А - in.
Transcribed Image Text:A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.20 in. exists between the two pipes. Bronze pipe (1) has an elastic modulus of E1 = 16,000 ksi, a cross-sectional area of A1 = 2.68 in.2, and a length of L1 = 6.8 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.08 in.2, and a length of L2 = 9.2 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses produced in each of the members. (b) the final position of flange B with respect to support A. %3D %3D %3D L1 L2 В Cl (2) (1) Answer: (a) 01= ksi ksi 02= (b) бв/А - in.
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