. A 95% confidence interval for P1 - P2 given that P1 = 0.25 with n1 = 40 and P2 = 0.40 with n2 = 120. Give the best estimate for the margin or error, and confidence interval. 2.Test whether there is a difference between two groups in the proportion who voted, if 45 out of random sample of 71 in group 1 votes and 56 out of a random sample of 100 in Group 2 voted. Give the test statistic and p-value.

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A: a)

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A: Given problem Given that   In a survey of 3117 ​adults, 1473 say they have started paying bills…

Q: Suppose that the sample size had been​ 240, with x bar=4.1 and s=3.1. Use technology to find a​ 95%…

A: Sample mean = x̅ = 4.1 Sample size = n = 240 Sample S.D = s = 3.1 Standard Error = s/√n  =…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

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Q: Suppose in a recent poll of 1250 randomly selected Californians who took vacations, 132 of them…

A:

Q: Find the 95% confidence interval for the difference in the two population means X1 = 12, s1 = 2.2,…

A: The sample mean of group 1 is The sample standard deviation of group 1 is The sample size of group 1…

Q: truct the 80% confidence interval for the difference p₁-P2 when x₁ = 40, n₁ = 80, x₂=20, and n₂ =…

A: For population 1:The number of successes is .The sample size is .For population 2:The number of…

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

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Q: A random sample of 320 medical doctors showed that 162 had a solo practice. Let p represent the…

A: Given,

Q: na survey of 2587 adults in a recent year, 1365 say they have made a New Year's resolution.…

A: Given that  Sample size n =2587 Favorable cases x =1365 Sample proportion p^=x/n  =1365/2587 =0.5276

Q: Jane

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Q: A national media outlet conducted a poll which estimated that 82% of all voters believed global…

A: Given, p=0.82 Margin of error = 0.02 Confidence level = 90% q=1-p =1-0.82 =0.18

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Q: Most married couples have two or three personality preferences in common. A random sample of 368…

A: Given Data n1 = 368 x1 = 136 n2 = 574 x2 = 232

Q: Out of 600 people sampled, 528 had kids. 1. The best point estimate for p is  2. The margin of…

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Q: Suppose in 2011 a survey of 954 workers in the city of Ottawa found that 206 used public transport…

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A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Find the 2-decimal answers for the  95% confidence interval if 97 out of 550 samples are found to be…

A: Given: n = 550 X = 97 Formula Used: Margin of error E = Z*p(1-p)n Confidence interval = p ± E

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: GIVEN DATA,margin of error =1%=0.01CI=0.95α=1-0.95=0.05Zc=Zα/2=Z0.05/2=Z0.025=1.96 [ from excel…

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A: Given data, Sample size, n1 = 67 Mean, x1 = 27 Sample size, n2 = 72 Mean, x2 = 27 95% Confidence…

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Q: If a sample has has a 94% confidence interval of (4.68,5.43), what is the 2-decimal margin of error?

A: Given information- We have given the confidence interval is- C.I = (4.68, 5.43) Lower limit = 4.68…

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Q: Several years​ ago, 43 43​% of parents who had children in grades​ K-12 were satisfied with the…

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Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

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Q: Use the Student's t distribution to find tc for a 0.99 confidence level when the sample is 21.

A: We find it's Value from t table at n-1= (21-1)= 20 d.f. and 0.99 confidence level.

Q: of 100 people sampled, 50 had kids. The best point estimate for p is. The margin of error for a 90%…

A:

Q: In a recent survey of 500 teenagers, 18.6% indicated that they had eaten junk food while watching TV…

A: Given Data: p^=0.186n=500

Q: the difference P-P2 when x 40, n, = 80, x, = 20, and n, nce in 60. Round the answer to at least…

A: Given : n1 = 80 x1 = 40 n2 = 60 x2 = 20 confidence level,c=0.8

Q: 7. A recent survey of 500 women indicated that 29% of women over age 55 in the study were widows.…

A: Givensample size(n)=500p^=29%=0.29confidence level=90%

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Q: National statistics show that 23% of men (sample 1) smoke and 18.5% of women (sample 2) do. A random…

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Q: Find a 95% confidence interval for the true population proportion.19)In a survey of 227 adults, 28%…

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