. 9.) a multipurpose transformer has a secondary coil that gives output voltages of 5.60V, 12.0V; 480V. The input voltage is 240V to a of 280 turns. and primary Coil a.) Find the number of torns in each part of the Secondary coil to produce each voltage. :) ve Np 2 Vs N₂ N = 280 V=240V 5.60 -2400 1200 Imax = S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each. part if used alone.
. 9.) a multipurpose transformer has a secondary coil that gives output voltages of 5.60V, 12.0V; 480V. The input voltage is 240V to a of 280 turns. and primary Coil a.) Find the number of torns in each part of the Secondary coil to produce each voltage. :) ve Np 2 Vs N₂ N = 280 V=240V 5.60 -2400 1200 Imax = S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each. part if used alone.
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Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:9.) a multipurpose transformer has a secondary coll
that gives output voltages of 5.60V, 1200V,
and
480V. the input voltage is 240V to a primary Coil
of 280 Turns.
a.) Find the
number of torns in
each part of the
Secondary coil to produce
each voltagel.
:) up
Np
2
2
Vs
N₂
240V
28 Otures
N₂ = 76.53 turns
240V
280
240V
280
=
12.0V.
NS
Ns = 114 turns
5.6V
Ns
=
=
480V
Ns
in 5.6V
in 12.0V
N = 280
V=240V
N₁ = 560 turns in 480v
NS
Imax=S.OA
b.) If the max input current is
5.00 Amps, what are the Imax of each
part if used alone.
5.60
-
Imax=214.29 Ā
-240 V
$12000
Ip Vp = I₂ Vs
(5.0A) (240V) = Is (5.6v)
(5.0A) (240v) = Is (12.0v)
Imax 100A
(5.04) (240v) = Is (480V)
Fmax =22.5A/
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