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. 9.) a multipurpose transformer has a secondary coil that gives output voltages of 5.60V, 12.0V; 480V. The input voltage is 240V to a of 280 turns. and primary Coil a.) Find the number of torns in each part of the Secondary coil to produce each voltage. :) ve Np 2 Vs N₂ N = 280 V=240V 5.60 -2400 1200 Imax = S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each. part if used alone.

. 9.) a multipurpose transformer has a secondary coil that gives output voltages of 5.60V, 12.0V; 480V. The input voltage is 240V to a of 280 turns. and primary Coil a.) Find the number of torns in each part of the Secondary coil to produce each voltage. :) ve Np 2 Vs N₂ N = 280 V=240V 5.60 -2400 1200 Imax = S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each. part if used alone.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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9.) a multipurpose transformer has a secondary coll that gives output voltages of 5.60V, 1200V, and 480V. the input voltage is 240V to a primary Coil of 280 Turns. a.) Find the number of torns in each part of the Secondary coil to produce each voltagel. :) up Np 2 2 Vs N₂ 240V 28 Otures N₂ = 76.53 turns 240V 280 240V 280 = 12.0V. NS Ns = 114 turns 5.6V Ns = = 480V Ns in 5.6V in 12.0V N = 280 V=240V N₁ = 560 turns in 480v NS Imax=S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each part if used alone. 5.60 - Imax=214.29 Ā -240 V $12000 Ip Vp = I₂ Vs (5.0A) (240V) = Is (5.6v) (5.0A) (240v) = Is (12.0v) Imax 100A (5.04) (240v) = Is (480V) Fmax =22.5A/
Transcribed Image Text:9.) a multipurpose transformer has a secondary coll that gives output voltages of 5.60V, 1200V, and 480V. the input voltage is 240V to a primary Coil of 280 Turns. a.) Find the number of torns in each part of the Secondary coil to produce each voltagel. :) up Np 2 2 Vs N₂ 240V 28 Otures N₂ = 76.53 turns 240V 280 240V 280 = 12.0V. NS Ns = 114 turns 5.6V Ns = = 480V Ns in 5.6V in 12.0V N = 280 V=240V N₁ = 560 turns in 480v NS Imax=S.OA b.) If the max input current is 5.00 Amps, what are the Imax of each part if used alone. 5.60 - Imax=214.29 Ā -240 V $12000 Ip Vp = I₂ Vs (5.0A) (240V) = Is (5.6v) (5.0A) (240v) = Is (12.0v) Imax 100A (5.04) (240v) = Is (480V) Fmax =22.5A/
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