PHY 151 Lab M1

Here is the data of slope s, intercept b, uncertainty of slope and uncertainty of intercept which calculating from Excel using LINEST function: slope s 0.387 uncertainty of slope 𝜎 ? 0.014654 intercept b -17.0233 uncertainty of intercept 𝜎 ? 6.576206 Since the slope s of the plot m s vs. m t Teflon Bottom is 𝜇 𝑘 base on the formula of ? ? = 𝜇 𝑘 ? ? and 𝜇 𝑘 = 𝑚 ? 𝑚 ? . Then 𝜇 𝑘 = ? = 0.387 , 𝜎 𝜇 𝑘 = 𝜎 ? = 0.014654. So 𝜇 𝑘 ± 𝜎 𝜇 𝑘 = 0.4 ± 0.02 . VI-3 -Pan with Teflon bottom: Mass of pan with Teflon bottom : m p = 105.3g, L = 58 cm, d = 16.5 cm. -data table m(g) mt(g) H(cm) y(cm) 200 305.3 29.5 13 12.95 0.22995 400 505.3 33 16.5 16.53 0.2968 600 705.3 32 15.5 15.5 0.2773 800 905.3 34 17.5 17.56 0.3165 1000 1105.3 33.3 16.8 16.84 0.3027 -calculation: 1) m t = m p + m, for example, m = 200g, and m p is constant at 105.3g m t = m p + m =105.3g +200g =305.3g 2) y = H – d, for example, H=29.5cm, d =16.5cm, y = H – d = 29.5cm – 16.5 cm = 13cm. 3) 𝜃 = sin −1 𝑦 𝐿 = sin −1 𝐻−? 𝐿 , for example, H=29.5cm, d =16.5cm, L=58 cm, 𝜃 = sin −1 𝐻−? 𝐿 = sin −1 29.5?𝑚−16.5?𝑚 58?𝑚 = 12.95° . 4) 𝜇 ? = ?𝑎?𝜃, for example, 𝜃 = 12.95°,𝜇 ? = ?𝑎?𝜃 = tan(12.95°) = 0.22995 5) 𝜇 ? ̅̅̅ = ∑ 𝜇 ? 5 = 0.22995+0.2968+0.2773+0.3165+0.3027 5 = 0.28465 y = 0.387x - 17.023 0 50 100 150 200 250 300 0 100 200 300 400 500 600 700 m s (gram) m t (gram) m s vs. m t Rubbrt Bottom 𝜃 (deg) 𝜇 ?