Chapter 5 (NEW)
docx
keyboard_arrow_up
School
Monroe College, New Rochelle *
*We aren’t endorsed by this school
Course
131
Subject
Statistics
Date
Jan 9, 2024
Type
docx
Pages
28
Uploaded by BarristerPencil12934
Chapter 5 - Probability
TEACHER:
Mr. Gottschalk
SUBJECT:
AP Statistics
DAY
CLASSWORK
HOMEWORK
0
Chapter 4 Test
W&TN Video #1 [Simulations]
1
Quiz 5.1 Worksheet (pg. 5 – 6)
W&TN Video #2 [Probability Models]
2
p. 297 (#31 – 36) + p. 309 (#43, 46)
W&TN Video #3 – part 1 [General Addition Rule]
3
p. 309 (#49b, 50b, 51, 57, 58, 60)
W&TN Video #3 – part 2 [General Addition Rule]
4
Quiz 5.2 Worksheet (pg. 11 – 13)
W&TN Video #4 [Conditional Prob. + Indep. Events]
5
p. 329 (#64, 66, 67, 69, 72, 106)
W&TN Video #5 – part 1 [Gen. Multiplication Rule]
6
p. 330 (#83, 85, 92, 99)
W&TN Video #5 – part 2 [Gen. Multiplication Rule]
7
Quiz 5.3 Worksheet (pg. 18 – 20)
FRAPPY Day Tomorrow!!!
8
FRAPPY DAY
Work on Semester Project or Practice WS A/B/C
on pg. 21 – 23 with answers on pg. 24
9
Probability Review – Day #1
(MC)
Look @ p. 334-335 in your book for extra problems
Watch BONUS MULTIPLE CHOICE REVIEW VIDEO!!!
10
Probability Review – Day #2
(FR)
Look @ p. 334-335 in your book for extra problems
Watch BONUS MULTIPLE CHOICE REVIEW VIDEO!!!
11
Chapter 5 Test
W&TN Video #1 of Ch.6 (Discrete Random Variables)
W&TN =
W
atch
&
T
ake
N
otes
Lesson Objectives:
Throughout this chapter we will focus on learning the
rules of probability
and how to use them to calculate
the probability of various types of events.
We will also learn the terminology of probability, such as,
independent
and
dependent
events,
mutually exclusive
(or
disjoint
) events,
union
,
intersection
, and
joint
probabilities
.
Probability calculations can be difficult for many students, so we will do many practice problems
to gain more experience and in turn a better understanding of how to approach probability problems.
1
Chapter 5 Topics
Page Number
5.1 - Simulations
......................................................................................................
3
5.2 – Probability Models
..........................................................................................
7
5.2 – The General Addition Rule, Venn Diagrams, Two-Way Tables, etc
................
9
5.3 – Conditional Probability and Independence
...................................................
14
5.3 – The General Multiplication Rule and Tree Diagrams
....................................
16
2
Chapter 5:
[Video #1]
– Probability with Simulations
I am the father of three daughters.
I frequently get asked, “what are the odds…three girls?!?”
Def
:
probability = _____________________________________________________________________
_____________________________________________________________________________________
When one does not know how to properly calculate probability formally with mathematical rules,
then one could use a ____________________________ to
closely
estimate the probability of the event.
Assumptions
:
each child is _______________________________ of each other.
the probability of a boy = the probability of a girl = ___________.
To do our simulation, we need an object that works with our assumptions so we can devise a plan!
Using a deck of playing cards, let…
girl = ___________________________ ; boy = ________________________________
girl = ___________________________ ; boy = ________________________________
Replace card and shuffle before re-drawing a 2
nd
and 3
rd
time to mimic three children.
Using a random number generator, let…
girl = ___________________________ ; boy = ________________________________
girl = ___________________________ ; boy = ________________________________
Generate ________ single digit numbers 0-9; ____________________ numbers are OK!
Using a fair coin, let…
girl = ___________________________ ; boy = ________________________________
Flip the coin ______ times.
Using a six-sided die, let…
girl = ___________________________ ; boy = ________________________________
girl = ___________________________ ; boy = ________________________________
Roll the die ______ times.
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
I used random.org’s random number generator to come up with 100 sets of three numbers, either 0 or 1.
_______________ times, the simulation showed 3 girls.
The _______________ the series of repetitions, the closer we get to the actual probability of the event.
So, the probability of having three girls out of three children is ____________________ to 11%!
This idea is referred to as the
LAW OF _____________________
_____________________________.
Ex
:
A basketball player has made 82% of his shots this season.
What is the probability that he makes
10 out of 10 shots in the next game?
Assumptions: each shot is independepent & P(make one shot) =
0.82.
The plan to carry out this simulation:
Randomly generate __________ numbers between 1-100 to represent the ten free-throw attempts.
Let _________________ =
made shot
and __________________ =
missed shot
.
Repeat _____________ times and calculate the proportion of times that all 10 shots are made.
In ten separate trials of 1000 games each, the probability of making all 10 shots is:
0.139, 0.121, 0.152, 0.131, 0.145, 0.145, 0.156, 0.142, 0.131, and 0.145.
Conclusion
:
If our 82% free-throw shooter attempts 10 free-throws ___________, ___________
__________, the probability that he makes all 10 shots is close to ____________.
************************************************************************************
******
Imagine 50% of people like vanilla, 30% like chocolate, and 20% like both ice cream flavors.
Describe a simulation plan to choose TWO people’s favorite ice cream flavor.
(Don’t worry, you won’t actually carry out the simulation, just plan it!)
4
Quiz 5.1
AP
Statistics
1.
The probability that a randomly selected person in the United States is left-
handed is about 0.14.
(a)Interpret this probability.
(b)
Among the 28 students in Mr. Millar’s Calculus BC class, 8 are left-
handed. Could this
have happened by chance alone? Describe how you would use a random
number table to
simulate the proportion of left-handers in a class of 28 students if they
were chosen
randomly from a population that is 14% left-handed.
Do not perform
the simulation.
Below are the number of left-handers in 100 simulated classes of 28 students
each, assuming that students are selected randomly from a population in which
14% of individuals are left-handed.
5
Remember, this is
how many
actual
lefties are in Mr.
Millar’s class!
(c)
Based on this simulation of 100 different classes of 28 students each,
estimate the average
number of lefties in a class of 28 students.
(d)
What do these results suggest about the proportion of lefties in Mr.
Millar’s class?
2.
You are playing a board game with some friends in which each turn begins with
rolling two
dice. In this game, rolling “doubles”—the same number on both dice—is
especially
beneficial. You’ve rolled doubles on your last three turns, and one of your
friends says, “No
way you’ll roll doubles this time, it would be nearly impossible.” Explain to your
friend
what he doesn’t seem to understand about probability.
3.
A school’s debate club has 10 members, 6 females and 4 males. If the team
decides to pick
two members randomly to participate in a debate, what is the probability that
both of the
chosen members are female?
We will use a simulation to estimate this
probability!
Describe the simulation procedure below
and then use the portion of the
random number table
given to carry out
10 trials
of your simulation to
estimate the probability.
Line
141
96767
35964
23822
96012
94591
65194
50842
53372
142
72829
50232
97892
63408
77919
44575
24870
04178
143
88565
42628
17797
49376
61762
16953
88604
12724
144
62964
88145
83083
69453
46109
59505
69680
00900
6
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Chapter 5:
[Video #2]
– Probability Models
To help us organize events and their probabilities, we can create a
probability model
.
Probability model =
__________________________________________________________
__________________________________________________________
A
probability model
is made up of two parts:
Sample space
: _________________________________________________________
_________________________________________________________
Probability per outcome
The
sample space
can have categorical or quantitative variables:
Coin flip: { _____________ , ______________ }
Rolling a die: { _____ , _____ , _____ , _____ , _____ , _____ }
Suit of playing card: { ____________ , ____________ , ___________ , ____________ }
Sum of two dice: { ___ , ___ , ___ , ___ , ___ , ____ , ____ , ____ , ____ , ____ , ____ }
7
Probability models
are commonly set up with a table with the sample space of events in one
row and the associated probabilities beneath each event.
Ex
: Rolling a single six-sided die.
Ex
:
Benford’s Law
states that in many naturally occurring collections of numbers,
the leading significant digit is likely to be small.
What if we did not know the
probability
of the first number being a 9?
8
Probability Model RULES!!!
1)
2)
What is the probability that the first number is at least 3?
***************************************************************************************************************
Calculate the probability of randomly selecting a person that is or has been
married at some point in their life.
Chapter 5:
[Video #3]
– Probability Rules (Part 1 of 3)
In a standard deck of cards, let’s consider three separate events…
Event #1: Jack ( J )
o
P( J ) = ________
Event #2: Red Ace ( RA )
o
P( RA ) = _______
Event #3: Jack or Red Ace ( J or RA )
o
P( J or RA ) = _______
*******************************************************************************************************************
What connection can we make from these three separate events?
*******************************************************************************************************************
Let’s try this again, but with slightly different events…
Event #1: Jack ( J )
o
P( J ) = ________
9
The Complement Rule
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Event #2: Spade ( S )
o
P( S ) = _______
Event #3: Jack or Spade ( J or S )
o
P( J or S ) = _______
*******************************************************************************************************************
Does the same pattern from before still hold true? _______
What makes these three events different than before???
_____________________________________________________________
***General Addition Rule***
_______________________________________________________________________
If two (or more) events have nothing in
common, then these events are called
_____________ or __________________
_________________________.
Therefore, if events “A” and “B” are disjoint, then P(A and B) =
________
*******************************************************************************************************************
Using two-way tables of probabilities to answer the same questions as before…
…
using disjoint events…
or
…using non-disjoint events.
*******************************************************************************************************************
Chapter 5:
[Video #3 – continued!]
– Probability Rules (Part 1 of 3)
Alternate way of writing the GENERAL ADDITION RULE using logic symbols…
10
P( __________ ) = P(A) + P(B) – P( ____________ )
Ex
:
Elsa and Anna auditioned to be a part of the school play. No one auditioned for a specific spot yet.
Elsa believes she has a 0.4 chance of making it. Anna believes she has a 0.6 chance of making it.
They believe they both have a 0.3 chance of making it.
Make a Venn diagram that shows all the events and probabilities.
*********************************************************
1) What is the probability that only Anna is selected to be in the play?
2) What is the probability that at least one of the two girls are selected?
Quiz 5.2
AP
Statistics
1.
The table below is a probability model for the number of cars in a randomly-
selected
household in the United States. (Based on U.S. Census 2000 data).
(a) What is the probability that a randomly selected household has three cars?
(That is, fill in
the space marked with a “?”)
Show your work.
(b) What is the probability that a randomly-selected household has at least 2 cars?
Show your work.
11
2.
Last Saturday at Pasquale’s Pizzas and Wings, 60 customers were served over
the course of
the evening. Fifty-two customers ordered pizza and 16 ordered buffalo wings.
Twelve of
these customers ordered both pizza and wings. Suppose we select a customer
from last
Saturday at random.
(a)
Fill in the Venn diagram below so that it describes the chance process involved
here.
Let
P
= the event “ordered pizza” and
W
= the event “ordered wings.”
(b)
What is the probability that a randomly-chosen customer ordered
neither
?
Justify you answer with appropriate calculations.
3.
The table below gives the counts (in thousands) of earned degrees in the
United States in a
recent year, classified by level and by the gender of the degree recipient.
12
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
(a)What is the probability that a person selected randomly earned a Professional
or
Doctoral degree?
(b) What type of events are “Professional” and “Doctoral”?
How do you know?
(c) What is the probability that a person selected randomly is female
or
earned a
Master’s degree?
(d)
What type of events are “female” and “Master’s”?
How do you know?
4.
Consolidated Builders has bid on two large construction contracts. The company
president
believes that the probability of winning the first contract (event
A
) is 0.6, that
the probability
of winning a second (event
B
) is 0.3, and that the probability of winning both
jobs is 0.1.
(a) Construct
BOTH
a Venn diagram
AND
a two-way table that summarizes events
A and B.
A
A
C
B
13
B
C
(b) Write each of the following events in terms of
A
,
B
,
A
C
, and
B
C
, and use the
information
above to calculate the probability of each.
i.
Consolidated wins both jobs.
ii.
Consolidated wins the first job but not the second.
iii.
Consolidated wins at least one of the jobs.
iv
. Either Consolidated does not win the first job or wins the second job.
Chapter 5:
[Video #4]
– Probability Rules (Part 2 of 3)
I collected data from my students about if they had a part-time job and whether they pay for their own car insurance.
o
P( Yes pays own ins. ) =
o
P( Yes pays own ins. | Yes Job) = …
wait a second
…
14
Conditional probability
: ______________________________________________________________________
___________________________________________________________________________________________
___________________________________________________________________________________________
P( A | B )
is to be read as:
______________________________________________________________________
______________________________________________________________________
o
P( Yes pays own ins. | Yes Job) =
There
IS
a formula for conditional probability on the AP Stats official formula sheet, too!
P (A | B )
=
Let’s use the above formula to re-answer the previous probability question
?
o
P( Yes pays own ins. | Yes Job) =
o
Is this the same as the previous question???
P( Yes Job | Yes pays own ins.) =
Does having a job affect the probability that a student will have to pay their own insurance??
o
P( Yes pays own ins. ) =
o
P( Yes pays own ins. | Yes Job) =
o
P( Yes pays own ins. | No Job) =
Ans:
________, if a student has a job, then they were __________
____________ to pay for their own insurance.
15
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
We can say that having a job and paying his/her own insurance are _______________________________ events
all because mathematically…
___________________________________________________________________.
**************************************************************************************************
If your parent was a student athlete, does that affect whether you would be a student athlete, too???
o
P( Yes student ) =
o
P( Yes student | Yes parent ) =
o
P( Yes student | No parent ) =
Ans:
_______, if the parent was an athlete or not ______
______ affect the probability the student is an athlete.
We can conclude your parent’s decision to be a student athlete and your decision to be a student athlete are
_________________________________________ events all because mathematically …
________________________________________________________________________________________.
**************************************************************************************************
In conclusion…
Conditional probability formula:
Check for independent events:
**************************************************************************************************
1)
What is the probability that Anna is selected to be in the play,
given Elsa is selected to be in the play?
2)
Are the events “Anna is selected” and “Elsa is selected”
independent from one another?
Chapter 5:
[Video #5]
– Probability Rules (Part 3 of 3)
We have been using Venn diagrams and two-way tables to organize our data to answer probability questions,
but those work great when discussing a single event with multiple possibilities.
Now, we move on to more complex probability questions that involve multiple events with multiple possibilities
?
******************************************************************************************
In Texas Hold’em poker, two cards are dealt to each player.
The best starting hand is two aces.
Draw a tree diagram showing all the possibilities of getting aces vs. no aces for each card dealt.
16
General Multiplication Rule
o
What’s the probability that you are dealt two aces in a hand?
o
What’s the probability that you are dealt one ace in a hand?
o
What’s the probability that you are dealt at least one ace in a hand?
Chapter 5:
[Video #5 – continued!]
– Probability Rules (Part 3 of 3)
Ex #2
:
When a football team gets the ball within the 20 yard line, the coach has three play options:
throw a long pass, throw a short pass, or run the ball.
The play will result in a touchdown or not.
P( long pass ) = 0.15
P( long pass and no touchdown ) = 0.1275
P( touchdown | short pass ) = 0.12
P( run and touchdown ) = 0.02
P( no touchdown | run ) = 0.96
17
(1)
P( R ) =
(2)
P( LP ∩ TD
C
) =
(3)
P( TD | R) =
(4)
P( TD
C
| LP ) =
(5)
P( TD ) =
(6)
P( R | TD ) =
(7)
P( LP
U
SP ) =
(8)
P( R
U
TD ) =
*************************************************************************************************
P( SP | TD
C
) =
P( R
C
∩ TD ) =
Quiz 5.3
AP
Statistics
1.
What age groups use social networking sites? A recent study produced the
following data
about 768 individuals who were asked their age and which of three social
networking sites
they used most often. (People who did not use such sites were excluded from
the study).
18
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Suppose one subject from this study was selected at random.
(a) Calculate the probability that the selected subject preferred Twitter.
(b) Calculate the probability that the selected subject preferred Facebook & was in
the 25-44 age group.
(c) Calculate the probability that the selected subject preferred LinkedIn or was in
the 0-24 age group.
(d)
Calculate the probability that the selected subject preferred Twitter, given that
he or she was in
the 45 – 64 age group.
(e) Are the events “preferred Twitter” and “age group 45 – 64” independent?
Provide mathematical evidence.
(f) Are the events “preferred Twitter” and “age group 45 – 64” mutually exclusive?
Explain.
19
2.
Some days, Ramon drives to work. The rest of the time he rides his bike.
Suppose we
choose a random work day. The following table gives the probabilities of several
events.
(a)
Draw a complete tree diagram with all events and their probabilities.
(b) Calculate the probability that Ramon is not late for work given that he bikes.
(c)
Calculate the probability that Ramon is late for work given that he drives.
(d)
Calculate the probability that Ramon drives given that he is late.
(e)
Calculate the probability that Ramon bikes and he is not late.
20
3.
Suppose a person was having two surgeries performed at the same time by
different
operating teams.
Assume (
unrealistically
) that the two operations are
independent.
If the
chances of success for surgery A are 85%, and the chances of success for
surgery B are 90%,
what is the probability that both will fail?
Show your work.
4.
Parking for students at Central High School is very limited, and those who arrive
late have to
park illegally and take their chances at getting a ticket. Joey has determined that
the
probability that he has to park illegally and that he gets a parking ticket is 0.07.
He recorded
data last year and found that because of his perpetual tardiness, the probability
that he will
have to park illegally is 0.25. Suppose that Joey arrived late once again this
morning and had
to park in a no-parking zone. Calculate the probability that Joey will get a
parking ticket.
Show your work.
21
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Practice Worksheet A
A couple plans to have three children.
Find the probability that the children are:
1.
all boys
2.
all girls
3.
two boys or two girls
4.
at least one child of each sex.
In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females, and 12 of the juniors are
males.
If a student is selected at random, find the probability of selecting
5.
a junior or a female
22
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
6.
a senior or a female
7.
a junior or a senior
Practice Worksheet B
Handyman Hank has one of three jobs to choose from today: paint a house, drywall a room, or fix a tractor.
At
the end of the day, Hank may or may not finish the job.
The probability that Hank finishes on time given that he
drywalls today is 0.6, he does not finish on time given that he fixes the tractor is 0.8, he fixes the tractor and
finishes on time is 0.06, he drywalls is 0.6, and he paints and does not finish on time is 0.08.
To answer the
following probabilities, I would recommend creating/completing a full tree diagram first in the box below.
1)
P(chooses painting) =
2)
P(chooses painting | finishes on time) =
3)
P(does not finish on time | chooses painting) =
4)
P(chooses painting and finishes on time) =
5)
P(chooses drywalling | does not finish on time) =
23
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
6)
P(chooses drywalling or fixes the tractor) =
7)
P(chooses painting or does not finish on time) =
8)
P(chooses working on the tractor and chooses painting) =
9)
P(chooses drywalling and does not finish on time) =
10) P(chooses working on the tractor | finishes on time) =
Practice Worksheet C
Here are the counts (in thousands) of earned degrees in the United States in a recent year, classified by level
and by the sex of the degree recipient:
Bachelor’s
Master’s
Professional
Doctorate
Total
Female
616
194
30
16
856
Male
529
171
44
26
770
Total
1145
365
74
42
1626
1.
If you choose a degree recipient at random, what is the probability that the person you choose is a woman?
2.
What is the probability that a randomly chosen degree recipient is a man?
3.
What is the conditional probability that you choose a woman given that the person chosen received a
professional degree?
4.
What is the conditional probability that the person chosen received a bachelor’s degree given that he is a
man?
5.
Are the events “choose a woman” and “choose a professional degree recipient”
independent
?
Provide mathematical evidence.
24
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
6.
Calculate the probability of choosing a male who is also a bachelor’s degree recipient.
7.
Confirm your answer to #6 by finding the probability of choosing a male bachelor’s degree recipient directly
from the table of counts above.
Practice Worksheet
A
Answers
:
1.
1/8
Note:
The sample space is:
BBB,
2.
1/8
BGG, GBG, GGB
3.
3/4
GBB, BGB, BBG
4.
3/4
GGG
5.
24/28 which reduces to 6/7
6.
16/28 which reduces to 4/7
7.
28/28 which is 1 or 100% chance.
Note:
There are 18 Juniors, 12 of which are male, so 6 are female.
There are 10 Seniors, 4 of which are male, because 6 are female.
Practice Worksheet
B
Answers
:
1)
0.1
6)
0.9
2)
0.04545
7)
0.58
3)
0.8
8)
0
4)
0.02
9)
0.24
5)
0.4286
10)
0.1364
Practice Worksheet
C
Answers
:
1.
856 / 1626 = 52.64%
2.
770 / 1626 = 47.36%
(or you can subtract the previous answer from 100%)
3.
30 / 74 = 40.54%
4.
529 / 770 = 68.70%
5.
Let A = Choose a woman and B = Choose a professional degree recipient.
If they are independent
then
they would satisfy the multiplication rule for independent events:
P(A and B) = P(A)
P(B)
P(A and B) = P(woman and Professional degree recipient) = 30 / 1626 = .01845
P(A) = 856 / 1626 = .5264
25
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
P(B) = 74 / 1626 = .0455
Substituting these values into the equation you get:
0.01845 = (0.5264)(0.0455)
Since
0.01845
0.024, the events are not independent
6.
Let A = male and B = Bachelor Degree.
We are asked to find P(A and B) with the following rule.
P(A and B) = P(A) P(B | A) = (770 / 1626) (529 / 770) = 0.3253 = 32.53%
7.
To find the probability of choose a male bachelor degree recipient directly from the table I divide the
number of male bachelor recipients (529) by the table total (1626) to get 32.53%.
Preparing for Your Chapter 5 Test
For the Chapter 5 Test You Should Know:
The definition and examples of disjoint, independent, dependent, and complementary events.
How to verify if a probability distribution is legitimate by seeing if 0
P(A)
1 and P(
S
) = 1
How to answer various probability questions using the general multiplication rule for
independent and dependent events.
How to answer various probability questions using the general addition rule (for disjoint events
as well as for non-disjoint events).
How to assign probabilities to equally likely events and unequally likely events.
How to mathematically determine if two events are independent by seeing if P(A) = P(A | B).
How to construct and label a Venn Diagram and/or two-way table in terms of events
A
,
B
,
A
c
,
and
B
c
, and also how to answer probability questions based upon your Venn Diagram and/or
two-way table.
That
P(at least one _____) = 1 – P(No _____).
For example, P(at least one girl among 4 kids)
= 1 – P (no girls among 4 kids)
How to draw a tree diagram and calculate probabilities from it.
How to calculate conditional probabilities.
26
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Chapter 5 – Important Terms
1.
Probability
2.
Probability Model
3.
Sample Space
4.
Tree Diagram
5.
5 Probability Rules
a.
0
P(A)
1
Probabilities must fall between 0 and 1
b.
P(S) = 1
The Probability of the Sample Space is 1
c.
P(A
c
) = 1 - P(A)
Complement Rule
d.
P(A or B) = P(A) + P(B) – P(A and B)
General Addition Rule
e.
P(A and B) = P(A)
P(B | A)
General Multiplication Rule
6.
Independent Events
7.
Dependent Events
8.
Disjoint/Mutually Exclusive Events
9.
Complementary Events
27
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
10.
Intersection
11.
Union
28
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Documents
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage

Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill

Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL

College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Recommended textbooks for you
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
- College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage

Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill

Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL

College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning