STAT-431-EX-18_merged
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School
University of Illinois, Urbana Champaign *
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Course
431
Subject
Statistics
Date
Apr 3, 2024
Type
Pages
8
Uploaded by rohaanraheja11
STAT 431 EX 18
2023-12-07
Question 1
a)
library
(rjags)
## Loading required package: coda
## Linked to JAGS 4.3.2
## Loaded modules: basemod,bugs
# Data and initial values
data
<-
list
(
x =
c
(
1997
,
1998
,
1999
,
2000
,
2001
,
2002
,
2003
,
2004
,
2005
,
2006
,
2007
,
2008
,
2009
,
2010
),
y =
c
(
2.2952
,
2.3435
,
2.5512
,
2.5531
,
2.3918
,
2.1546
,
2.3596
,
2.2431
,
2.1725
,
2.3162
,
2.3504
,
2.1926
,
N =
14
)
inits
<-
list
(
list
(
beta0 =
0
,
beta1 =
0
,
tausq =
1
),
list
(
beta0 =
1
,
beta1 =
-
1
,
tausq =
0.5
),
list
(
beta0 =
-
1
,
beta1 =
1
,
tausq =
2
)
)
# Write the model in a string
model_string
<-
"
model {
for (i in 1:N) {
mu[i] <- beta0 + beta1 * x[i]
y[i] ~ dnorm(mu[i], tausq)
}
beta0 ~ dnorm(0, 1E-6)
beta1 ~ dnorm(0, 1E-6)
tausq ~ dgamma(0.001, 0.001)
sigma <- 1 / sqrt(tausq)
}
"
# Save the model to a file
writeLines
(model_string,
"regression_model.txt"
)
# Run the model
jags_model
<-
jags.model
(
"regression_model.txt"
,
data =
data,
inits =
inits,
n.chains =
3
,
n.adapt =
100
## Compiling model graph
##
Resolving undeclared variables
1
##
Allocating nodes
## Graph information:
##
Observed stochastic nodes: 14
##
Unobserved stochastic nodes: 3
##
Total graph size: 66
##
## Initializing model
jags_samples
<-
coda.samples
(jags_model,
c
(
"beta0"
,
"beta1"
,
"tausq"
),
n.iter =
5000
)
# Print summary and diagnostic plots
summary
(jags_samples)
##
## Iterations = 1:5000
## Thinning interval = 1
## Number of chains = 3
## Sample size per chain = 5000
##
## 1. Empirical mean and standard deviation for each variable,
##
plus standard error of the mean:
##
##
Mean
SD
Naive SE Time-series SE
## beta0 16.708529 1614.4090 13.181594
18.712826
## beta1 -0.007201
0.8058
0.006579
0.009318
## tausq 14.051884
21.9573
0.179281
0.082953
##
## 2. Quantiles for each variable:
##
##
2.5%
25%
50%
75%
97.5%
## beta0 -2.029e+03 -1.907e+03
4.942637 1948.1254 2078.425
## beta1 -1.036e+00 -9.712e-01 -0.001322
0.9529
1.014
## tausq
2.403e-02
4.842e-02
0.072412
29.9570
68.257
plot
(jags_samples)
2
0
1000
2000
3000
4000
5000
-2000
Iterations
Trace of beta0
-3000
-1000
0
1000
2000
3000
0e+00
Density of beta0
N = 5000 Bandwidth = 250.1
0
1000
2000
3000
4000
5000
-1.0
Iterations
Trace of beta1
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5
0.0
1.0
Density of beta1
N = 5000 Bandwidth = 0.1248
0
1000
2000
3000
4000
5000
0
80
Iterations
Trace of tausq
0
20
40
60
80
100
120
0.00
Density of tausq
N = 5000 Bandwidth = 3.401
a) continued
# Assuming
'
jags_model
'
is your JAGS model object
# Load the coda package
library
(coda)
# Extract the coda object from the JAGS model
coda_samples
<-
coda.samples
(jags_model,
c
(
"beta0"
,
"beta1"
,
"tausq"
),
n.iter =
5000
)
# Check Gelman-Rubin diagnostic
gelman.diag
(coda_samples)
## Potential scale reduction factors:
##
##
Point est. Upper C.I.
## beta0
78.64
198.5
## beta1
78.65
198.6
## tausq
3.96
23.5
##
## Multivariate psrf
##
## 60.9
# Plot trace plots for each parameter
traceplot
(coda_samples)
3
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5000
6000
7000
8000
9000
10000
-2000
-1000
0
1000
2000
Iterations
Trace of beta0
5000
6000
-1.0
-0.5
0.0
0.5
1.0
5000
6000
7000
8000
9000
10000
0
20
40
60
80
100
120
Iterations
Trace of tausq
It converges.
b)
# Frequentist (lm) model
lm_model
<-
lm
(y
~
x,
data =
data)
summary
(lm_model)
4
##
## Call:
## lm(formula = y ~ x, data = data)
##
## Residuals:
##
Min
1Q
Median
3Q
Max
## -0.20180 -0.08265
0.02306
0.07616
0.18042
##
## Coefficients:
##
Estimate Std. Error t value Pr(>|t|)
## (Intercept) 48.38982
17.03075
2.841
0.0149 *
## x
-0.02301
0.00850
-2.707
0.0191 *
## ---
## Signif. codes:
0
'
***
'
0.001
'
**
'
0.01
'
*
'
0.05
'
.
'
0.1
' '
1
##
## Residual standard error: 0.1282 on 12 degrees of freedom
## Multiple R-squared:
0.3791, Adjusted R-squared:
0.3273
## F-statistic: 7.326 on 1 and 12 DF,
p-value: 0.01907
# Bayesian (JAGS) model
summary
(jags_samples)
##
## Iterations = 1:5000
## Thinning interval = 1
## Number of chains = 3
## Sample size per chain = 5000
##
## 1. Empirical mean and standard deviation for each variable,
##
plus standard error of the mean:
##
##
Mean
SD
Naive SE Time-series SE
## beta0 16.708529 1614.4090 13.181594
18.712826
## beta1 -0.007201
0.8058
0.006579
0.009318
## tausq 14.051884
21.9573
0.179281
0.082953
##
## 2. Quantiles for each variable:
##
##
2.5%
25%
50%
75%
97.5%
## beta0 -2.029e+03 -1.907e+03
4.942637 1948.1254 2078.425
## beta1 -1.036e+00 -9.712e-01 -0.001322
0.9529
1.014
## tausq
2.403e-02
4.842e-02
0.072412
29.9570
68.257
jags_samples
<-
coda.samples
(jags_model,
c
(
"beta0"
,
"beta1"
,
"tausq"
),
n.iter =
5000
)
# Assuming
'
jags_model
'
is the object containing the JAGS model
# Extract the relevant samples for beta1
jags_samples
<-
coda.samples
(jags_model,
c
(
"beta1"
),
n.iter =
5000
)
beta1_samples
<-
as.matrix
(jags_samples[[
1
]])
# Calculate the posterior probability that beta1 > 0
posterior_prob_beta1_positive
<-
mean
(beta1_samples
>
0
,
na.rm =
TRUE
)
# Print the result
cat
(
"Posterior probability that beta1 > 0:"
, posterior_prob_beta1_positive,
"
\n
"
)
5
## Posterior probability that beta1 > 0: 0.063
2.
library
(rjags)
# Load the data
data
<-
list
(
x =
c
(
32
,
33
,
34
,
35
,
36
,
37
,
38
,
39
,
40
,
41
),
y =
c
(
2.4
,
2.7
,
3.2
,
2.7
,
3.0
,
3.6
,
3.4
,
4.0
,
3.7
,
3.9
),
N =
10
,
prior_intercept_mean =
2
,
prior_intercept_precision =
1
/
(
0.5
ˆ
2
),
# Variance = 0.5ˆ2
prior_slope_mean =
0
,
prior_slope_precision =
1
/
(
0.5
ˆ
2
)
# Variance = 0.5ˆ2
)
# Specify the model in JAGS language
model_string
<-
"
model {
for (i in 1:N) {
mu[i] <- beta0 + beta1 * x[i]
y[i] ~ dnorm(mu[i], tau)
}
beta0 ~ dnorm(prior_intercept_mean, prior_intercept_precision)
beta1 ~ dnorm(prior_slope_mean, prior_slope_precision)
tau ~ dgamma(0.001, 0.001)
sigma <- 1 / sqrt(tau)
}
"
# Save the model to a file
writeLines
(model_string,
"informative_priors_model.txt"
)
# Set initial values for each chain
inits
<-
list
(
list
(
beta0 =
2
,
beta1 =
0
,
tau =
1
),
list
(
beta0 =
1
,
beta1 =
-
1
,
tau =
0.5
),
list
(
beta0 =
-
1
,
beta1 =
1
,
tau =
2
)
)
# Run the model
jags_model_informative_priors
<-
jags.model
(
"informative_priors_model.txt"
,
data =
data,
inits =
inits,
## Compiling model graph
##
Resolving undeclared variables
##
Allocating nodes
## Graph information:
##
Observed stochastic nodes: 10
##
Unobserved stochastic nodes: 3
##
Total graph size: 52
##
## Initializing model
6
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jags_samples_informative_priors
<-
coda.samples
(jags_model_informative_priors,
c
(
"beta0"
,
"beta1"
,
"tau"
# Print summary and diagnostic plots
summary
(jags_samples_informative_priors)
##
## Iterations = 1:5000
## Thinning interval = 1
## Number of chains = 3
## Sample size per chain = 5000
##
## 1. Empirical mean and standard deviation for each variable,
##
plus standard error of the mean:
##
##
Mean
SD
Naive SE Time-series SE
## beta0 1.64340 0.58729 0.0047952
0.0203298
## beta1 0.04501 0.01655 0.0001351
0.0005759
## tau
5.44212 2.77889 0.0226895
0.0391238
##
## 2. Quantiles for each variable:
##
##
2.5%
25%
50%
75%
97.5%
## beta0 0.65811 1.30762 1.64319 1.98811
2.62834
## beta1 0.01698 0.03528 0.04512 0.05463
0.07274
## tau
1.55397 3.46147 4.94423 6.87909 12.12741
plot
(jags_samples_informative_priors)
0
1000
2000
3000
4000
5000
-20
Iterations
Trace of beta0
-20
-10
0
10
20
0.0
0.8
Density of beta0
N = 5000 Bandwidth = 0.07867
0
1000
2000
3000
4000
5000
-0.4
Iterations
Trace of beta1
-0.6
-0.4
-0.2
0.0
0.2
0.4
0.6
0.8
0
20
Density of beta1
N = 5000 Bandwidth = 0.002237
0
1000
2000
3000
4000
5000
0
30
Iterations
Trace of tau
0
10
20
30
40
0.00
Density of tau
N = 5000 Bandwidth = 0.3951
7
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- Some analysts complain that spreadsheet models are difficult to resize. You can be the judge of this. Suppose the current product mix problem is changed so that there is an extra resource, packaging labor hours, and two additional PC models, 9 and 10. What additional input data are required? What modifications are necessary in the spreadsheet model (including range name changes)? Make up values for any extra required input data and incorporate these into a modified spreadsheet model. Then optimize with Solver. Do you conclude that it is easy to resize a spreadsheet model? (By the way, it turns out that algebraic models are typically much easier to resize.)arrow_forwardSolve with minitabarrow_forwardIf a model has inputs aligned so that x = the numberof years after 2000, what inputs would be used torepresent 2015 and 2022?arrow_forward
- The data file includes the text of three books of the Bible (Joshua, Jonah and Philippians) using the ESV translation. While these are all great books, our only interest for this project is how often each letter is used. Identify those letters whose Cls do not overlap with any the CIs of any of the other letters. (For example the CI [0.042, 0.052] overlaps with [0.050, 0.060] because the upper bound of the first CI is greater than the lower bound of the second CI.) List the letters with the non-overlapping Cis and specify how many such letters there are.arrow_forwardplace open closed pending total bronx 1121 1622 80 2823 brooklyn 1170 2706 48 3924 manhattan 744 3380 25 4149 queens 1353 2043 25 3421 staten island 83 118 0 201 total 4471 9869 178 14518arrow_forwardome File Edit View History Bookmarks Profiles Tab Window Help - Homework: Section 1.4 O NWP Assessment Player UI Ap x i education.wiley.com/was/ui/v2/assessment-player/index.html?launchld=bba0e335-3e07-493d-97c6-8f39f5c7e2c1#/question/3 Homework: Section 1.4 Question 4 of 6 -/ 20 く View Policies Current Attempt in Progress Find a formula for the given linear function, h(x). The graph of h intersects the graph of y = x2 at x = -4 and x = 10. NOTE: Enter the exact answer. h(x) = 16 étv SC 80 F2 F3 DII DD FS F7 F9 F10 F11 #3 $ 1 2 3 & 4 6. 7 8. 9 Q W E T Y U P S D F G J K C く N M .. .- エ Barrow_forward
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