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Subject
Statistics
Date
Apr 3, 2024
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21
Uploaded by CoachTeamWasp34
Introductory Statistics Explained (1.11)
Exercises
Inference for Two Means
©
2022, 2023, 2024 Jeremy Balka
Comparing Two Means v1.11 W24 Draft
J.B.’s strongly suggested exercises:
4
,
6
,
7
,
9
,
10
,
11
,
17
,
23
,
26
,
27
,
30
,
31
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33
NB The section titles and numbers are not yet synced up with the text.
1
Introduction
2
The Sampling Distribution of the Di
ff
erence in Sample Means
1. Suppose we draw a random sample from Population 1, which has a mean of
15
and a standard
deviation of
2
, and we draw a random sample from Population 2, which has a mean of
8
and a
standard deviation of
6
, and the two samples can be considered independent.
(a) If
n
1
=
n
2
= 4
, what is the mean of the sampling distribution of
¯
X
1
-
¯
X
2
?
(b) If
n
1
=
n
2
= 4
, what is the standard deviation of the sampling distribution of
¯
X
1
-
¯
X
2
?
(c) If
n
1
=
n
2
= 4
, what is the shape of sampling distribution of
¯
X
1
-
¯
X
2
?
(d) If
n
1
=
n
2
= 400
, what is the mean of the sampling distribution of
¯
X
1
-
¯
X
2
?
(e) If
n
1
=
n
2
= 400
, what is the standard deviation of the sampling distribution of
¯
X
1
-
¯
X
2
?
(f) If
n
1
=
n
2
= 400
, what is the shape of sampling distribution of
¯
X
1
-
¯
X
2
?
2. Tom and Pete are two NFL prospects at the NFL combine, where players eligible for the NFL draft
show their skills in a variety of di
ff
erent exercises. Tom and Pete are about to have three attempts at
the 40 yard dash. Suppose that (theoretically) Tom’s times in this event are approximately normally
distributed with a mean of 4.612 seconds and a standard deviation of 0.048 seconds. Pete’s times
are approximately normally distributed with a mean of 4.528 seconds and a standard deviation of
0.044 seconds. Suppose it is reasonable to assume independence between runs. (The runs may not
be truly independent, but this assumption provides a reasonable approximate model.)
(a) In their first attempt, what is the probability that Tom’s time is greater than Pete’s time?
(b) What is the probability that Tom’s average time in the three attempts is greater than Pete’s
average time in the three attempts?
1
3
Hypothesis Tests and Confidence Intervals for Two Indepen-
dent Samples (When
σ
1
and
σ
2
are known)
4
Hypothesis Tests and Confidence Intervals for
μ
1
-
μ
2
(When
σ
1
and
σ
2
are unknown)
4.1
Pooled-Variance
t
Tests and Confidence Intervals
3. Table
1
illustrates the results of a two-sample study. The samples were drawn independently from
normally distributed populations.
Group 1
Group 2
Sample mean
8.8
17.2
Sample standard deviation
1.42
2.61
Sample size
10
5
Table 1: Results of a two-sample study.
For the pooled-variance
t
procedure, calculate:
(a) The point estimate of
μ
1
-
μ
2
.
(b) The pooled variance
s
2
p
.
(c)
SE
(
¯
X
1
-
¯
X
2
)
.
(d) A 95% confidence interval for
μ
1
-
μ
2
.
(e) Test the null hypothesis that the population means are equal. Give the appropriate hypotheses,
standard error, value of the test statistic,
p
-value, and conclusion at
↵
= 0
.
05
.
4. Does a vitamin D supplement have an e
ff
ect on parathyroid hormone (PTH) levels in the blood? An
experiment
1
investigated the e
ff
ect of a vitamin D supplement on several biological factors in study
participants. One of the variables was the change in PTH in the blood.
In the experiment, 26 individuals were randomly assigned to one of two groups. Each group consumed
240 mL of orange juice per day for 12 weeks. The orange juice of the treatment group was fortified
with 1000 IU vitamin D
3
, whereas the control group’s orange juice had no vitamin D
3
added. After
12 weeks, the change in PTH level in the blood (pg/mL) was recorded. Table
4
illustrate the results.
Fortified with vitamin D
¯
X
1
=
-
9
.
0
s
1
= 37
.
5
n
1
= 14
Not fortified with vitamin D
¯
X
2
=
-
1
.
6
s
2
= 34
.
6
n
2
= 12
Table 2: Change in blood PTH levels after 12 weeks.
Suppose that normal quantile-quantile plots showed that the values were approximately normally
distributed.
Use the pooled-variance
t
procedure to answer the following questions.
(Since the
observations are approximately normally distributed, and the sample standard deviations are similar,
the pooled-variance
t
procedure is a reasonable method of analysis.)
1
Tangpricha et al. (2003). Fortification of orange juice with vitamin D: a novel approach for enhancing vitamin D nutritional
health.
The American journal of clinical nutrition
, 77(6): 1478-1483.
Ho
M M
Ha
u
do
(a) Test the hypothesis that vitamin D has no e
ff
ect against a two-sided alternative.
Give the
appropriate hypotheses in words and symbols, value of the test statistic,
p
-value, and conclusion.
(Hint to ease the calculation burden:
s
2
p
= 1310
.
417
,
SE
(
¯
X
1
-
¯
X
2
) = 14
.
24088
.)
(b) Calculate a 95% confidence interval for the di
ff
erence in population mean PTH level. Give a
proper interpretation of the interval.
(c) Give an overall summary of the results of the analysis.
4.2
Welch (Unpooled Variance)
t
Tests and Confidence Intervals
5. Table
3
illustrates the results of a two-sample study. The samples were drawn independently from
normally distributed populations.
Group 1
Group 2
Sample mean
8.8
17.2
Sample standard deviation
1.42
2.61
Sample size
10
5
Table 3: Results of a two-sample study.
For the Welch procedure, calculate:
(a) The point estimate of
μ
1
-
μ
2
.
(b)
SE
W
(
¯
X
1
-
¯
X
2
)
.
(c) A 95% confidence interval for
μ
1
-
μ
2
. (Hint to ease the calculation burden: DF
= 5
.
221
.)
(d) Test the null hypothesis that the population means are equal. Give the appropriate hypotheses,
standard error, value of the test statistic,
p
-value, and a conclusion at
↵
= 0
.
05
. (Hint to ease
the calculation burden: DF
= 5
.
221
.)
6. Consider again the study discussed in Question
4
.
(In this experiment, some individuals received
orange juice fortified with vitamin D, others received unfortified orange juice.) Does the vitamin D
supplement a
ff
ect phosphorous levels in the blood? The change in phosphorous levels over the course
of the study are found in the following table.
Fortified with vitamin D
¯
X
1
=
-
6
.
3
s
1
= 18
.
7
n
1
= 14
Not fortified with vitamin D
¯
X
2
=
-
0
.
2
s
2
= 1
.
7
n
2
= 12
Table 4: Change in blood phosphorous levels (mg/dL) after 12 weeks.
Note that the standard deviations are vastly di
ff
erent here (so much so that it makes one wonder if
there might be a typo in the article). Since the standard deviations are vastly di
ff
erent, the pooled-
variance procedure would start to break down and would not be appropriate. The Welch procedure
would be a better method of analysis, so use the Welch procedure to answer the following questions.
(a) What is the value of
SE
W
(
¯
X
1
-
¯
X
2
)
?
(b) If we wish to test the null hypothesis that, on average, vitamin D has no e
ff
ect on phosphorous
levels, what is the value of the appropriate test statistic?
(c) The R output for the Welch procedure is:
x
̅
tak
SE
x
̅
91.6
0.5196
5.022
µ
O
jet
1
1.215
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Welch Two Sample t-test
data:
vitaminD and novitaminD
t = -1.2156, df = 13.215, p-value = 0.2454
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-16.923691
4.723691
sample estimates:
mean of x mean of y
-6.3
-0.2
Give a summary of the results of the analysis.
4.3
Guidelines for Choosing the Appropriate Two-Sample
t
Procedure
7. What factors influence the choice between the Welch procedure and the pooled-variance
t
procedure?
When is the Welch procedure a better choice?
When is the pooled-variance
t
procedure a better
choice?
8. Suppose we are interested in assessing the e
ff
ect of two fuel additives on fuel e
ffi
ciency. We intend
to use a
t
procedure to carry out an appropriate hypothesis test.
Under which of the following
situations would it be most appropriate to use Welch’s approximation instead of the pooled-variance
procedure?
(a) The sample sizes of the two groups are similar, and the sample standard deviations are similar.
(b) The sample sizes of the two groups are similar, and the sample standard deviations are very
di
ff
erent.
(c) The sample sizes of the two groups are very di
ff
erent, and the sample standard deviations are
similar.
(d) The sample sizes of the two groups are very di
ff
erent, and the sample standard deviations are
very di
ff
erent.
5
Paired-Di
ff
erence Procedures
5.1
Paired-Di
ff
erence
t
Tests and Confidence Intervals
9.
O
ff
erman et al.
(
2009
) conducted an experiment on pigs to investigate the e
ff
ect of an antivenom
after an injection of rattlesnake venom. In one aspect of the study, the researchers investigated the
change in volume of the right hind leg before and after being subjected to a dose of venom and
treatment with an antivenom. The volume of the right hind leg was measured in 9 pigs before being
injected with the venom, then the pigs were injected with a dose of venom and treated intravenously
with an antivenom, and after 8 hours the volume of the leg was measured again. The results are
illustrated in Table
5
. (The volume was measured using a water displacement method; the units are
mL.)
(a) Suppose we are interested in estimating the true mean amount of swelling for pigs of this type
under the conditions of this experiment.
Would we use a paired-di
ff
erence procedure or an
independent sample procedure? Justify your response.
(b) What are the 9 di
ff
erences? (Take the di
ff
erences as After
-
Before.)
(c) What is the sample mean di
ff
erence? What is the standard deviation of the di
ff
erences?
(d) What is the standard error of the sample mean di
ff
erence?
large
p
rake
so
no
strong
evidenc
errett
of
diff
variances
when
sample
size
r
diff
so
pooled
not
good
paired
diff
bic2
samples
on
same
unit
before
after
Not
indep
x
̅
say
203.3
IN
R
data
pig
SE
5
8
18.7268
mean
pig
7203.333
sd
pig
i
56.180s
Before
After
Di
ff
erence
685
935
545
700
480
770
475
640
680
800
685
955
590
780
600
790
630
830
Table 5: Volume (mL) of the right hind leg before and 8 hours after injection with a dose of rattlesnake
venom and an antivenom.
(e) The boxplot and normal quantile-quantile plot of the di
ff
erences are given in Figure
1
. Do these
plots give any indication that the
t
procedures should not be used?
0
50
150
250
Change in Volume (ml)
(a) The line represents the hypothesized value of 0.
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5
150
200
250
Theoretical Quantiles
Sample Quantiles
(b) Normal quantile-quantile plot.
Figure 1: Changes in volume (mL) of the right hind leg before and 8 hours after injection with a dose of
rattlesnake venom and an antivenom.
(f) Construct a 95% confidence interval for the true mean amount of swelling under the conditions
of this experiment.
Give an interpretation of the confidence interval in the context of the
problem at hand.
(g) Carry out a test of the null hypothesis that there is no swelling on average (after 8 hours),
against the appropriate one-sided alternative hypothesis.
Give the hypotheses in words and
symbols, value of the test statistic,
p
-value, and conclusion.
10.
Porter et al.
(
2010
) investigated the e
ff
ect of a brief training program on the ability of health care
professionals to detect deception. In part of the study, 26 health care workers were shown videos in
which individuals sometimes showed a genuine smile, and sometimes showed a fake smile. Individuals
completed this task before and after completing a 3 hour session designed to help them recognize
deception. The participants’ responses were evaluated and they were given a
discrimination accuracy
score (high positive scores indicate a person is correctly discriminating between a genuine smile and
a fake smile, values near 0 indicate the individual is not discriminating between a genuine smile and
a fake smile, and negative values indicate that the individual is misclassifying genuine smiles as fake
and fake smiles as genuine). The results of the study are given in Table
6
.
The researchers were interested in testing whether the training program had an e
ff
ect, and in esti-
290
16s
190
190
200
Looksnormal
as
t.i.it
p
2.2sse
o
Very
small
p
very
strong
evidence
again
Mean
SD
Before
0.192
0.770
After
0.810
1.173
Di
ff
erence (After
-
Before)
0.618
1.412
Table 6: Discrimination accuracy scores for 26 health care professionals before and after a training program.
mating the size of the e
ff
ect with a confidence interval.
(a) What should be done before using software to carry out the
t
procedures?
(b) When the calculations are carried out in R, the default output is:
One Sample t-test
data:
expressions
t = 2.2317, df = 25, p-value = 0.0348
alternative hypothesis: true mean is not equal to 0
95 percent confidence interval:
0.04768086 1.18831914
sample estimates:
mean of x
0.618
The
p
-value given in the output is for a two-sided alternative hypothesis. But suppose that the
researchers felt a one-sided alternative hypothesis was more appropriate, since they felt that,
if anything, the training session would improve a participant’s ability to discriminate between
genuine and fake smiles. What would be the appropriate one-sided alternative? What would
the
p
-value be for this test?
(c) Give a summary of the results of the analysis. Use a significance level of 0.05.
6
Investigating the Normality Assumption
7
Chapter Exercises
7.1
Basic Calculations
7.2
Concepts
11. In words, what is the meaning of
SE
(
¯
X
1
-
¯
X
2
)
?
12. Would it make sense to test the hypothesis
H
0
:
¯
X
1
=
¯
X
2
? Why or why not?
13. A 95% confidence interval for
μ
1
-
μ
2
is found to be
(2
,
28)
.
(a) Give an example of a null hypothesis that would be rejected at
↵
= 0
.
05
.
(b) Give an example of a null hypothesis that would not be rejected at
↵
= 0
.
05
.
14. Consider the following output for a two-sample problem.
HoM
O
HA
b
O
p
Plotting
if
normality
point
evidence
of
x
̅
Han
o
p
rave
half
the
2
sided
0.0348
2
0onu
p
a so
statistically
significant
evidence
that
training
improved
discrimination
L
fi
nftipteo
ugg
8
gg
associated
w
̅
95
estimate
or soof
samp
dist
of
x
̅
no
my
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Two Sample t-test
t = -0.5692, df = 18, p-value = 0.5763
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.9817025
0.5631646
sample estimates:
mean of x
mean of y
-0.12739020
0.08187872
Does this output yield strong evidence that
¯
X
1
does not equal
¯
X
2
?
15. Suppose we wish to test the null hypothesis that
μ
1
-
μ
2
= 0
against a two-sided alternative hypoth-
esis.
(a) All else being equal, what will happen to the power of the test as the true di
ff
erence
μ
1
-
μ
2
gets closer to 0?
(b) All else being equal, what will happen to the power of the test as the sample sizes increase?
16. Consider a two-sample
t
test of the null hypothesis of equal population means against a two-sided
alternative.
(a) Under what conditions would the test statistic be equal to 0?
(b) Under what conditions would the
p
-value be equal to 1?
(c) Under what conditions would the
p
-value be equal to 0?
17. Consider the three boxplots in Figure
2
, which represent samples of size 40 from 3 di
ff
erent popula-
tions. Consider the following 3 null hypotheses (with two-sided alternatives in all cases).
A
B
C
-5
0
5
Figure 2
I.
H
0
:
μ
A
=
μ
B
II.
H
0
:
μ
A
=
μ
C
III.
H
0
:
μ
B
=
μ
C
(a) Which test would result in the smallest
p
-value?
(b) Which test would result in the largest
p
-value?
18. Consider the following output for a two-sample inference procedure, and the corresponding boxplots
in Figure
3
.
TPyt
p
Imy
To
to
even
lies
close
to
a
live
it
does
w
̅
B
II
s
as
tw
Ygi
iit
A
B
2
4
6
8
Figure 3
Two Sample t-test
t = -1.0655, df = 43, p-value = 0.2926
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-1.6882973
0.5209971
sample estimates:
mean of x mean of y
4.367041
4.950691
(a) Do the boxplots give any indication that this
t
procedure should not be used?
(b) Is there strong evidence that the populations have di
ff
erent means?
(c) Based on the confidence interval in the output, is there strong evidence that
μ
1
-
μ
2
6
= 10
?
(d) What is the sum of the two sample sizes?
19. Suppose we draw two independent samples of sizes
n
1
= 100
and
n
2
= 50
, and wish to test the null
hypothesis that the population means are equal. The output for the two procedures (Welch and the
pooled-variance
t
) are:
Output 1:
data:
sample1 and sample2
t = -1.3734, df = 98.659, p-value = 0.1727
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.5677384
0.1032975
sample estimates:
mean of x
mean of y
-0.1298456
0.1023749
Output 2:
data: sample1 and sample2
t = -1.3705, df = 148, p-value = 0.1726
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.5670558
0.1026149
sample estimates:
mean of x
mean of y
-0.1298456
0.1023749
(a) Which output is from the pooled-variance procedure? Which output is from the Welch proce-
dure?
(b) Which procedure would be more appropriate here?
20. Forty patients with high blood pressure volunteer for a study. The participants are given an injection
of a placebo (a saline solution with no pharmacological e
ff
ect), and an hour later their drop in blood
pressure is measured. Two days later the same 40 patients are given an injection of an experimental
new drug, and an hour later the drop in blood pressure is recorded. Researchers want to investigate
the e
ff
ect of the drug on blood pressure. They wish to compare the drop in blood pressure after the
injection of the drug to the drop in blood pressure after injection of the placebo.
(a) What
t
procedure would be the most appropriate procedure to use here (Welch’s, pooled-
variance, or paired di
ff
erence)? Suppose that it is reasonable to assume normality where neces-
sary.
(b) Suppose we observe a significant di
ff
erence between the drop in blood pressure observed after
the placebo injection, and the drop in blood pressure after the drug injection.
Other than a
possible e
ff
ect of the drug, are there any features of this study design that may possibly be the
cause of this di
ff
erence?
21. A research experiment was designed to assess the e
ff
ectiveness of two memory training programs.
The experiment involved 25 sets of identical twins. One twin in each pair was randomly assigned
to Program A, the other to Program B. Upon completion of the program, everyone took a memory
test and obtained a score between 0 and 100. If we want to carry out a hypothesis test to see if one
of the programs tends to result in a better score on the memory test, what is the most appropriate
test to use? Assume normality where necessary.
22. (Challenge! We haven’t worked through a problem like this—you need to think it through.) Suppose
we wish to draw independent random samples from two populations.
Suppose that it is known
that
σ
1
=
σ
2
= 3
, but the population means are unknown. We intend to draw equal sample sizes
n
1
=
n
2
=
n
from both populations. If we wish to estimate
μ
1
-
μ
2
within 0.5 with 95% confidence,
what sample size would be required?
23. Test your conceptual understanding: Which of the following statements are true?
You should be
able to explain
why
a statement is true or
why
a statement is false.
(a) When we use the pooled-variance
t
procedure, it is because we
know
the populations have the
same variance.
(b) The pooled-variance
t
procedure works well, even when the population variances are a little
di
ff
erent. This is especially true if the sample sizes are similar.
(c) It would be most appropriate to use the Welch procedure instead of the pooled-variance
t
procedure if the sample variances are very di
ff
erent and the sample sizes are very di
ff
erent.
(d) If the conclusions from the Welch procedure and the pooled-variance
t
procedure are very
similar, then it does not matter much which procedure is used.
(e) The Welch procedure is an exact procedure, as long as
¯
X
1
=
¯
X
2
.
F
we
assume
b
c
true
var
unknown
T
T
T
F
approximate
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24. Test your conceptual understanding: Which of the following statements are true?
You should be
able to explain
why
a statement is true or
why
a statement is false.
(a) If
μ
1
=
μ
2
, the sampling distribution of
¯
X
1
-
¯
X
2
is approximately symmetric about 0 for large
sample sizes.
(b) If
¯
X
1
=
¯
X
2
, the sampling distribution of
μ
1
-
μ
2
is approximately symmetric about 0 for large
sample sizes.
(c)
SE
(
¯
X
1
-
¯
X
2
)
is the true standard deviation of the sampling distribution of
¯
X
1
-
¯
X
2
.
(d) The pooled-variance
t
procedures work well, even when the variances for the two populations
are very di
ff
erent, as long as the sample sizes are very di
ff
erent as well.
(e) Suppose we are about to test the null hypothesis
μ
1
=
μ
2
against a two-sided alternative. All
else being equal, the greater the di
ff
erence between
μ
1
and
μ
2
, the greater the power of the test.
25. Test your conceptual understanding: Which of the following statements are true?
You should be
able to explain
why
a statement is true or
why
a statement is false.
(a) Suppose we are constructing a confidence interval for
μ
1
-
μ
2
. All else being equal, the greater
the di
ff
erence between
μ
1
and
μ
2
, the wider the interval.
(b) Suppose we are constructing a confidence interval for
μ
1
-
μ
2
. All else being equal, the greater
the di
ff
erence between
¯
X
1
and
¯
X
2
, the wider the interval.
(c) Suppose we are constructing a confidence interval for
μ
1
-
μ
2
. All else being equal, the greater
the sample sizes, the narrower the interval.
(d) Suppose we wish to test
H
0
:
μ
1
=
μ
2
.
We obtain random samples from the respective pop-
ulations, run the appropriate test, and find that the
p
-value is 0.00000032.
We can be very
confident that our results have important practical implications.
(e) If we test
H
0
:
μ
1
=
μ
2
against a two-sided alternative and find a
p
-value of 0.32, then we know
that
μ
1
=
μ
2
.
7.3
Applications
26. A study
2
investigated various aspects of tandem running in ants.
Tandem running is a form of
recruitment in which one ant with knowledge of the location of a food source or new nest site
leads another ant to that location. (Optional:
Watch an example of tandem running here: (1:53)
(
http://www.youtube.com/watch?v=X2C7Sy2oPik
)) Tandem running can be thought of as a form
of teaching and learning.
The study investigated various factors associated with tandem running, and investigated whether the
age of the ant and the experience of the ant had any e
ff
ect on tandem running. Ants (
Temnothorax
albipennis
) were categorized into 4 categories: Young and Inexperienced (YI), Young and Experienced
(YE), Old and Inexperienced (OI), Old and Experienced (OE). One aspect of the study investigated
the speed of tandem running when leading a YI ant. The mean speed of the run was recorded for
51 tandem runs in which the leader was YE, and 15 pairs of runs in which the leader was OE. The
researchers were interested in a possible di
ff
erence in the mean speed of tandem running in these two
situations.
Figures
4
and
5
and Table
7
illustrate the data.
(a) Do the plots give any indication that the
t
procedure should not be used?
(b) Which version of the
t
procedure (pooled or unpooled) is more appropriate here?
2
Franklin et al. (2012). Do ants need to be old and experienced to teach?
The Journal of Experimental Biology
, 215:1287–1292
The data used here is simulated data based on their Figure 2, with similar results and conclusions.
No
roughly symmetric
very
diff
SD
so
unpooled
whelch
is best
OE
YE
0.5
1.0
1.5
2.0
2.5
Speed (mm/s)
Figure 4: Speed of tandem running for ant pairs led by an old experienced (OE) ant, and ant paris led by
a young experienced (YE) ant.
-1
0
1
0.4
0.6
0.8
1.0
1.2
1.4
1.6
Normal Q-Q Plot
Theoretical Quantiles
Sample Quantiles
(a) OE ants.
-2
-1
0
1
2
0.5
1.0
1.5
2.0
2.5
Normal Q-Q Plot
Theoretical Quantiles
Sample Quantiles
(b) YE ants.
Figure 5: Normal QQ plots for OE and YE ants.
(c) Using the Welch procedure, construct a 95% confidence interval for the di
ff
erence in true
mean tandem running speed between OE and YE ants. (Hint to ease the calculation burden:
SE
W
(
¯
X
1
-
¯
X
2
) = 0
.
1272
, DF
= 37
.
714
.)
(d) The researchers were interested in investigating a possible di
ff
erence in the true mean run-
ning speeds for the two types of ant. In words and symbols, what are the hypotheses of the
appropriate hypothesis test?
(e) What is the value of the appropriate test statistic?
(f) What is the
p
-value of the test? Is there strong evidence against the null hypothesis?
(g) The output from the statistical software R for the Welch procedure is:
possible
left
skew
2.0249
0.1272
1.14
1.8 oasis
www.as
ff
f
o.m
u
ha
Ha
o.it
5189
an
2
1
1
5.18937.7141
7.487
10
6
OE
¯
X
1
= 1
.
14
s
1
= 0
.
37
n
1
= 15
YE
¯
X
2
= 1
.
80
s
2
= 0
.
60
n
2
= 51
Table 7: Means and standard deviations for the tandem running study.
Welch Two Sample t-test
data:
OE and YE
t = -5.1878, df = 37.714, p-value = 7.516e-06
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.9176121 -0.4023879
sample estimates:
mean of x mean of y
1.14
1.80
Give a summary of the results of the analysis (including the results of the hypothesis test and
the confidence interval). To what population do your conclusions apply?
27. A study
3
investigated several aspects of the ratio of the lengths of the index finger to the ring finger
in women who visited a sexual health clinic in Manchester, UK. (The ratio of the lengths of these
fingers is called the 2D:4D ratio.) The distribution of the 2D:4D ratio depends on several factors,
including the ethnic background of the individuals. The following table summarizes the results of
the measurements of the 2D:4D ratio on the left hand for white and black women in the study.
White women
¯
X
1
= 0
.
994
s
1
= 0
.
035
n
1
= 246
Black women
¯
X
2
= 0
.
963
s
2
= 0
.
034
n
2
= 46
(a) What plots should be created before carrying out any inference procedures?
(b) Which version of the
t
procedure (pooled or unpooled) is more appropriate here?
(c) Using the pooled-variance
t
procedure, construct a 95% confidence interval for the di
ff
erence in
the means of the 2D:4D ratio. (Hint to ease the calculation burden:
SE
(
¯
X
1
-
¯
X
2
) = 0
.
005598
.)
(d) Suppose we wish to test whether there is strong evidence of a di
ff
erence between the true means
of the 2D:4D ratio for white and black women. In words and symbols, what are the hypotheses
of the appropriate hypothesis test?
(e) What is the value of the appropriate test statistic?
(f) What is the
p
-value of the test? Is there strong evidence against the null hypothesis?
(g) The output from the statistical software R for the pooled-variance procedure is:
Two Sample t-test
data:
white and black
t = 5.538, df = 290, p-value = 6.859e-08
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
0.01998280 0.04201720
sample estimates:
mean of x mean of y
0.994
0.963
3
Brabin et al. (2008). The second to fourth digit ratio (2d:4d) in women with and without human papillomavirus and cervical
dysplasia.
American Journal of Human Biology
, 20:337–341.
sina.rs
I
it
i
ii
i
i
Hosni
I
o.aay.is
6
s.sma
ftp.iiisiiii
2ao
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Give a summary of the results of the analysis (including the results of the hypothesis test and
the confidence interval). To what population do your conclusions apply?
28. Researchers used an experiment to investigate whether prolonged food restriction might lead to a
relapse of drug abuse.
4
Rats were randomly assigned to a sated (well fed) group or a prolonged
food restriction group (the rats were under food restriction for 10 days, and their weight fell to
approximately 80% of the weight of the sated rats). Before the food deprivation period, all rats were
trained to use a lever to self-administer heroin. Access to heroin was removed for all rats during the
10 day food deprivation period. Rats were then given access to the heroin lever, and the number of
active lever presses in a 3 hour period was measured. The following table summarizes the results.
Food restriction
¯
X
1
= 48
.
9
s
1
= 25
.
4
n
1
= 8
Sated (control)
¯
X
2
= 23
.
8
s
2
= 7
.
9
n
2
= 7
(a) What plots should be created before carrying out any statistical inference?
(b) Plots of the data (not shown) show some right skewness in both groups, and so the use of the
t
procedures is a bit dubious. But if the skewness is similar in both groups, the
t
procedure may
still perform reasonably well. Assuming that we choose to use the
t
procedures, which version
of the
t
procedure (pooled or unpooled) is more appropriate here?
(c) Using the Welch (unpooled variance)
t
procedure, construct a 95% confidence interval for the dif-
ference in the means between the groups. (Hint to ease the calculation burden:
SE
W
(
¯
X
1
-
¯
X
2
) = 9
.
4637
,
DF
= 8
.
512
.)
(d) Suppose we wish to test whether there is strong evidence of a treatment e
ff
ect (a di
ff
erence
between the true means of the two groups). In words and symbols, what are the hypotheses of
the appropriate hypothesis test?
(e) What is the value of the appropriate test statistic?
(f) What is the
p
-value of the test? Is there strong evidence against the null hypothesis?
(g) The output from the statistical software R for the pooled-variance procedure is:
Welch Two Sample t-test
data: Restricted and Sated
t = 2.6523, df = 8.512, p-value = 0.02764
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
3.50315 46.69685
sample estimates:
mean of x mean of y
48.9
23.8
Give a summary of the results of the analysis (including the results of the hypothesis test and
the confidence interval). To what population do your conclusions apply?
29. A study
5
investigated several physical characteristics of the ears of Italian Caucasians. In one part of
the study, 3D symmetry (a measure of the symmetry between the left and right ears) was measured
on men and women between 31 and 40 years of age.
Men
¯
X
1
= 95
.
71
s
1
= 1
.
50
n
1
= 66
Women
¯
X
2
= 95
.
41
s
2
= 1
.
64
n
2
= 28
4
Shalev (2011). Chronic food restriction augments the reinstatement of extinguished heroin-seeking behavior in rats.
Addiction
Biology
, 17:691–693.
5
Sforza et al. (2009). Age- and sex-related changes in the normal human ear.
Forensic Science International
, 187:110.e1–
110.e7.
(a) What plots should be created before carrying out any inference procedures?
(b) Which version of the
t
procedure (pooled or unpooled) is more appropriate here?
(c) Using the pooled-variance
t
procedure, construct a 95% confidence interval for the di
ff
erence in
the means of the 3D symmetry index. (Hint to ease the calculation burden:
SE
(
¯
X
1
-
¯
X
2
) = 0
.
3479
.)
(d) Suppose we wish to test whether there is strong evidence of a di
ff
erence between the true mean
3D symmetry in men and women.
In words and symbols, what are the hypotheses of the
appropriate hypothesis test?
(e) What is the value of the appropriate test statistic?
(f) What is the
p
-value of the test? Is there strong evidence against the null hypothesis?
(g) The output from the statistical software R for the pooled-variance procedure is:
Two Sample t-test
data: men and women
t = 0.8624, df = 92, p-value = 0.3907
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.3908909
0.9908909
sample estimates:
mean of x mean of y
95.71
95.41
Give a summary of the results of the analysis (including the results of the hypothesis test and
the confidence interval). To what population do your conclusions apply?
30. A study
6
investigated several characteristics of psychopathic and nonpsychopathic male patients in a
Dutch inpatient psychiatric treatment centre. In one part of the study, the BEST index (a measure
of risk behaviours of psychiatric patients) was measured after several months of treatment.
The
higher the score on the BEST index, the better (less risky) the patient scored. The following table
summarizes the results.
Nonpsychopaths
¯
X
1
= 256
.
12
s
1
= 33
.
53
n
1
= 47
Psychopaths
¯
X
2
= 245
.
82
s
2
= 37
.
55
n
2
= 27
(a) What plots should be created before carrying out any inference procedures?
(b) Which version of the
t
procedure (pooled or unpooled) is more appropriate here?
(c) Using the pooled-variance
t
procedure, construct a 95% confidence interval for the di
ff
erence in
the means of the BEST index. (Hint to ease the calculation burden:
SE
(
¯
X
1
-
¯
X
2
) = 8
.
4603
.)
(d) Suppose we wish to test whether there is strong evidence of a di
ff
erence between the true means
of the BEST index for psychopaths and nonpsychopaths. In words and symbols, what are the
hypotheses of the appropriate hypothesis test?
(e) What is the value of the appropriate test statistic?
(f) What is the
p
-value of the test? Is there strong evidence against the null hypothesis?
(g) The output from the statistical software R for the pooled-variance procedure is:
Two Sample t-test
data: psychopaths and non psychopaths
t = 1.2174, df = 72, p-value = 0.2274
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-6.565314 27.165314
sample estimates:
mean of x mean of y
256.12
245.82
6
Chakhssi et al. (2010). Change during forensic treatment in psychopathic versus nonpsychopathic o
ff
enders. 21:660–682.
i
I
8
803
1.217
2
1
pt
1.217,72
0.225
Give a summary of the results of the analysis (including the results of the hypothesis test and
the confidence interval). To what population do your conclusions apply?
31. What e
ff
ect does a shock with a Taser have on the components of blood?
Jauchem et al.
(
2013
)
investigated this in an experiment on 11 wild boar (
Sus scrofa
) by measuring characteristics of blood
before and after a Taser shock. One measured characteristic was the mean corpuscular volume (the
average volume of red blood cells, measured in femtolitres (
10
-
15
L)).
Mean
SD
Before
54.5
2.4
After
57.8
2.6
Di
ff
erence (After
-
Before)
3.3
3.7
Table 8: Summary statistics of the mean corpuscular volume (fL) for 11 wild boar before and after a Taser
shock.
Suppose that the changes in mean corpuscular volume are approximately normally distributed.
(a) Construct a 95% confidence interval for the true mean change in mean corpuscular volume, and
give an interpretation of the interval.
(b) Carry out a test of the null hypothesis that, on average, there is no change in mean corpuscular
volume, against a two-sided alternative hypothesis. Give the hypotheses in words and symbols,
value of the test statistic,
p
-value, and conclusion.
7.4
Extra Practice Questions
32. In an observational study involving 42 new mothers, the women were classified according to whether
or not they had used marijuana in their pregnancy. The point of interest was comparing the birth
weight of the babies born to the two groups.
Did not use marijuana
¯
X
1
= 3468
s
1
= 680
n
1
= 32
Used marijuana
¯
X
2
= 3200
s
2
= 610
n
2
= 10
The researchers wanted to use a reasonable statistical analysis to investigate if there is a di
ff
erence
in mean birth weight between the two groups of mothers.
The researchers felt it was reasonable
to assume normality and to assume the two population variances are equal. Using the appropriate
procedure under these conditions, they researchers found an output of:
Two Sample t-test
data: marijuana and nomarijuana
t = 1.1126, df = 40, p-value = 0.2725
alternative hypothesis: true difference in means is not equal to 0
90 percent confidence interval:
****** ******
sample estimates:
mean of x mean of y
3468
3200
(a) The 90% confidence interval has been omitted from the output.
What is the appropriate
interval? (Hint to ease the calculation burden:
SE
(
¯
X
1
-
¯
X
2
) = 240
.
8803
.)
iii
iii
iii
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(b) Which one of the following is the most appropriate conclusion?
i. There is very strong evidence that the population mean weight of babies born to mothers
who used marijuana is equal to that of babies born to mothers who did not use marijuana.
ii. There is not strong evidence of a di
ff
erence in population mean birth weight between the
two groups.
iii. There is strong evidence that the population mean birth weights for the two groups are
equal.
iv. There is not strong evidence that the sample mean birth weights are di
ff
erent.
v. There is very strong evidence that marijuana causes a reduction in birth weight.
33. An experiment was designed to investigate the e
ff
ect of exercise on the size of tumours in rats. Thirty
rats were injected with cancerous cells. These rats were then randomly assigned to two groups. Ten
mice were kept in cages with exercise wheels, and 20 were kept in cages with no wheels. After six
weeks, the diameter of the tumour (cm) was recorded. The following table summarizes the results:
Exercise Wheels
No Wheels
Sample mean
1.2
1.5
Sample variance
0.08
0.12
(a) Is this an observational study or an experiment?
(b) The researcher wanted to test whether the exercise wheels reduced the size of tumours in rats.
Carry out the appropriate hypothesis test. Give appropriate hypotheses, the value of the test
statistic,
p
-value, and an appropriate conclusion. (Assume equal population variances, and that
the tumour sizes are normally distributed.) (Hint to ease the calculation burden:
s
2
p
= 0
.
10714
,
SE
(
¯
X
1
-
¯
X
2
) = 0
.
12677
)
(c) Suppose we found a
p
-value of .00000067 in the previous question.
Would this give strong
evidence of a causal link between exercise and size of tumour in this type of experiment?
(d) Calculate a 90% confidence interval for the di
ff
erence in mean tumour size (for the pooled
variance case).
(e) Now,
not
assuming equal population variances, carry out the appropriate test. Give appropriate
hypotheses, value of the test statistic,
p
-value, and an appropriate conclusion. (Hint to ease the
calculation burden: DF = 21.764.)
(f) Calculate a 90% confidence interval for the di
ff
erence in mean tumour size. (Not assuming equal
population variances.) (Hint to ease the calculation burden: DF = 21.764.)
(g) Which procedure (pooled-variance or Welch) is more appropriate in this case?
34. Researchers investigated the total cholesterol levels in the blood of male and female students at a large
university.
Total cholesterol (mg/dl) was measured on 26 male and 22 female student volunteers,
with the following results.
Males
Females
Sample mean
171.4
173.8
Sample standard deviation
32.9
34.1
Sample size
26
22
Although the people in the study are volunteers, for the purposes of these questions assume they can
be thought of as random samples from the populations.
(a) The researchers wanted to test the null hypothesis that the population mean total cholesterol
level is the same for both males and females, against a two-sided alternative hypothesis. The
following output represents the results of the pooled variance two-sample
t
procedure.
experiment
20
Him
u
Ha
I
i
test
Dont
havea
butstill
strong
evidence
wheel
group
have
lower
tumour
men
size
ftp.t
f
ffm
sqtl.o.es
287 1
t.ms
nonlo.iaon
iiiii
iii
Nota
significant
difference
so
up
to
preference
I
Two Sample t-test
data:
males and females
t = -0.2477, df = 46, p-value = 0.8055
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-21.90658
17.10658
sample estimates:
mean of x mean of y
171.4
173.8
Of the following options, which one is the most appropriate conclusion at
↵
=
.
05
?
i. There is strong evidence of a di
ff
erence in population means.
ii. There is significant evidence that females have a higher population mean total cholesterol
level.
iii. The observed di
ff
erence in sample mean cholesterol levels is significant.
iv. There is not significant evidence that the sample mean cholesterol levels are di
ff
erent.
v. There is not significant evidence that the population mean cholesterol levels are di
ff
erent.
(b) Give an appropriate interpretation of the confidence interval found in the output.
35. In an investigation into the e
ff
ectiveness of two processes that reduce contaminants in used motor
oil, 18 batches of used motor oil were randomly assigned to the two processes. 12 were randomly
assigned to process A, and 6 to process B. The contaminant level after processing was measured for
both processes. The results are given in Table
9
.
A
B
Sample size
12
6
Sample variance
16
9
Sample mean
63
57
Table 9: Summary of information for the motor oil question.
Suppose that the normality assumption of the
t
procedures is in fact reasonable, and that the
population variance of the contaminants is the same for both processing methods.
(a) Calculate a 95% confidence interval for the di
ff
erence in the population mean contaminant levels
(
μ
A
-
μ
B
). Give an appropriate interpretation of the interval.
(b) Carry out a test of the null hypothesis that the true mean contaminant level is the same for both
processes, against the alternative hypothesis that it is di
ff
erent. Give appropriate hypotheses
in words and symbols, value of the test statistic, and
p
-value.
(c) Summarize the results of the analysis.
36. Many studies have investigated a connection between “fear of negative evaluation” and bulimia.
Suppose that researchers at a large university are interested in carrying out their own investigation.
Eleven female students with bulimia completed a questionnaire and were assigned a “fear of negative
evaluation” score, with a resulting sample mean of 19.7. Fourteen female students with normal eating
habits were given the same questionnaire, with a resulting sample mean “fear of negative evaluation”
score of 14.9. The researchers ran a pooled-variance two-sample
t
procedure on the data, with the
following results.
Two Sample t-test
data:
bulimic and notbulimic
t = 2.5621, df = 23, p-value = 0.01742
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
0.9380235 8.8022362
sample estimates:
mean of x mean of y
19.72727
14.85714
Assume that the students can be thought of as random samples from the populations of female stu-
dents at the university, and the other assumptions of the pooled-variance
t
-procedures are reasonable
in this case.
(a) In words and symbols, what are the hypotheses of the
t
test given in the output?
(b) Give an appropriate conclusion at
↵
=
.
05
.
(c) Give a proper interpretation of the confidence interval found in the output.
37. As part of a production process, a company needs a certain type of resistor to have a resistance of
12 ohms. The company obtains resistors from 2 di
ff
erent suppliers and tests their resistance. The
results are given in the table below. Although it would not be perfectly justified in this case, assume
the resistors can be thought of an independent random samples from their respective populations.
Manufacturer
Sample size
Sample mean
Sample standard deviation
Manufacturer A
12
11.60
0.65
Manufacturer B
16
12.20
0.42
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5
11.0
11.5
12.0
12.5
Theoretical Quantiles
Sample Quantiles
(a) Manufacturer A
-2
-1
0
1
2
11.6
11.8
12.0
12.2
12.4
12.6
12.8
Theoretical Quantiles
Sample Quantiles
(b) Manufacturer B
Figure 6: Normal quantile-quantile plots of the resistance.
The researchers want to investigate several properties of these resistors. As part of their first investi-
gation, they want to estimate the di
ff
erence in the mean resistance between the two types of resistor,
and test the null hypothesis that the resistors have the same resistance on average. They wish to use
the
t
procedures, but realize that they should first investigate the normality assumption. Figure
6
illustrates the normal quantile-quantile plots in this scenario.
(a) Do these plots give any indication that the normality assumption is violated?
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(b) As part of their analysis into the di
ff
erences between the resistors, the researchers want to test
the null hypothesis that the population mean resistance is the same for both types of resistor,
against the alternative hypothesis that the mean resistance is di
ff
erent.
They also wish to
calculate a 95% confidence interval for the di
ff
erence in the mean resistance. They decide to use
the
pooled-variance
t
procedure
. The Welch procedure would have also been a reasonable
choice (the output for the Welch procedure is included farther below). What is the value of the
pooled sample variance (
s
2
p
)?
(c) What are the appropriate hypotheses in words and symbols?
(d) What is the value of the appropriate
t
statistic?
(e) Give an appropriate conclusion at the 5% significance level.
(f) What is a 95% confidence interval calculated using the pooled-variance
t
procedure?
(g) The following output represents the results of the Welch procedure on the data above, using
the alternative hypothesis that the population mean resistance for the two types of resistors is
di
ff
erent.
Welch Two Sample t-test
data:
resistors
t = -2.7904, df = 17.695, p-value = 0.01222
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-1.0522974 -0.1477026
sample estimates:
mean of x mean of y
11.6
12.2
Based on the confidence interval in the output, what can be said about possible di
ff
erences in
the mean resistance?
(h) Refer again to the output from the Welch procedure. Note that the output gives the
p
-value for
a two-sided alternative. Had the researchers felt that
H
a
:
μ
A
< μ
B
was the more appropriate
alternative (before looking at the data), what would the
p
-value of that test be?
38. A company is interested in investigating properties of a new aluminum alloy that is produced by a
new experimental process. They wish to compare the yield strength of this new alloy to the yield
strength of a standard alloy that is commonly used.
The following table gives a summary of the
yield strength (MPa) for independent samples of each type of alloy.
Alloy type
Sample size
Sample mean
Sample standard deviation
New alloy
80
664.2
23.3
Standard alloy
75
624.3
19.8
Suppose it is reasonable to assume that the alloy strengths are approximately normally distributed,
and we wish to carry out inference procedures to investigate possible di
ff
erences between the alloys.
There is little di
ff
erence between the sample standard deviations, so the use of the pooled-variance
t
procedure is reasonable here. Use the pooled-variance
t
procedure to answer the following questions.
(a) Calculate a 95% confidence interval for the di
ff
erence in true mean yield strength.
Give a
proper interpretation of the interval.
(Hint to ease the calculation burden:
s
2
p
= 469
.
9299
,
SE
(
¯
X
1
-
¯
X
2
) = 3
.
4842
.)
(b) Carry out a test of the null hypothesis that the population means are equal, against a two-sided
alternative hypothesis.
Give appropriate hypotheses (in words and symbols), test statistic,
p
-value, and conclusion.
39. A person suspects that a certain grocery store is overstating the weight of fresh chickens, and are
thus overcharging their customers. He randomly samples five chicken packages, records the weight
stated on the package (in grams) and the true weight of the chicken. The results are illustrated in
Table
10
.
Chicken
Stated weight
Actual weight
1
908
866
2
1120
1087
3
795
783
4
912
890
5
1402
1397
Table 10: Stated weight and actual weight for a sample of five chickens.
Even though it is somewhat dubious to use the
t
procedures for such a small sample size, the person
conducting the investigation feels the normality assumption is reasonable, and goes ahead with the
t
procedures. He find the output:
Paired t-test
data:
stated and actual
t = 3.3861, df = 4, p-value = 0.02763
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
4.104811 41.495189
sample estimates:
mean of the differences
22.8
(a) Give a summary of the results of the analysis.
(b) If the normality assumption is not in fact reasonable, what are the consequences?
40. Researchers are investigating whether a new experimental method of measuring viscosity in gases is
as e
ff
ective as an older method. They take measurements of viscosity on 6 samples of gas, using both
the new method and the older method. The results are given in Table
11
. The researchers want to
test whether there is a di
ff
erence between the two methods, and estimate the size of the di
ff
erence
with a confidence interval.
Gas Sample
Old Method
New Method
1
2.74
2.71
2
3.11
3.01
3
2.99
3.11
4
2.99
2.94
5
2.88
2.96
6
3.29
3.21
Table 11: Measures of viscosity in gases.
(a) Explain why a paired-di
ff
erence procedure should be used in this situation.
(b) If we want to use a
t
inference procedure, how could we assess if the normality assumption is
reasonable?
For the following questions, suppose that the normality assumption is reasonable.
(c) Calculate a 95% confidence interval for the population mean di
ff
erence, and give a proper
interpretation of the interval.
(d) Conduct the appropriate hypothesis test. Give appropriate hypotheses (in words and symbols),
test statistic,
p
-value, and conclusion.
41. The reaction times of 4 students are measured before and after having several alcoholic beverages.
The results are shown in Table
12
.
Suppose we wish to test the null hypothesis that alcohol has
Student
Before
After
1
0.41
0.78
2
0.38
0.63
3
0.52
0.94
4
0.41
0.47
Table 12: Before and after reaction times.
no e
ff
ect on reaction times, against the alternative that it slows reaction times.
Assume that the
di
ff
erences in the times are normally distributed, and use the appropriate
t
procedure. (But keep in
mind that the use of a
t
procedure is questionable for such a small sample size.)
(a) Carry out the hypothesis test. Give appropriate hypotheses,
p
-value, test statistic and conclu-
sion at the 5% significance level.
(b) Calculate a 95% confidence interval for the mean change in reaction times.
Give a proper
interpretation of the interval.
(c) What are the advantages to setting up an experiment this way, instead of splitting up the
students into 2 independent groups?
(d) What are the disadvantages to setting up an experiment in this way?
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21:660–682.
Franklin et al. (2012). Do ants need to be old and experienced to teach?
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Jauchem et al. (2013).
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