lab08-Revised-Class
pdf
keyboard_arrow_up
School
University of North Georgia, Dahlonega *
*We aren’t endorsed by this school
Course
MATH-240
Subject
Statistics
Date
Apr 3, 2024
Type
Pages
27
Uploaded by SuperHumanKoala4250
lab08-Revised-Class
March 24, 2024
1
Lab 8: Normal Distribution and Variance of Sample Means
Welcome to Lab 8!
In today’s lab, we will learn about
the variance of sample means
as well as
the normal distribution
.
[1]:
# Run this cell, but please don't change it.
# These lines import the Numpy and Datascience modules.
import
numpy
as
np
from
datascience
import
*
# These lines do some fancy plotting magic.
import
matplotlib
%
matplotlib
inline
import
matplotlib.pyplot
as
plt
plt
.
style
.
use(
'fivethirtyeight'
)
import
scipy.stats
as
stats
import
warnings
warnings
.
simplefilter(
'ignore'
,
FutureWarning
)
2
1. Normal Distributions
When we visualize the distribution of a sample, we are often interested in the mean and the standard
deviation of the sample (for the rest of this lab, we will abbreviate “standard deviation” as “SD”).
These two summary statistics can give us a bird’s eye view of the distribution - by letting us know
where the distribution sits on the number line and how spread out it is, respectively.
We want to check if the data is linearly related, so we should look at the data.
Question 1.1.
The next cell loads the table
births
from lecture, which is a large random sample
of US births and includes information about mother-child pairs.
Plot the distribution of mother’s ages from the table. Don’t change the last line, which will plot
the mean of the sample on the distribution itself.
[2]:
births
=
Table
.
read_table(
'baby.csv'
)
# Add your plot code here
1
births
.
hist(
"Maternal Age"
)
# Do not change these lines
plt
.
ylim(
-.002
,
.07
)
plt
.
scatter(np
.
mean(births
.
column(
"Maternal Age"
)),
0
, color
=
'red'
, s
=50
, zorder
=4
);
From the plot above, we can see that the mean is the center of gravity or balance point of the
distribution. If you cut the distribution out of cardboard, and then placed your finger at the mean,
the distribution would perfectly balance on your finger. Since the distribution above is right skewed
(which means it has a long right tail), we know that the mean of the distribution is larger than
the median, which is the “halfway” point of the data. Conversely, if the distribution had been left
skewed, we know the mean would be smaller than the median.
Question 1.2.
Run the following cell to compare the mean (red) and median (green) of the
distribution of mothers ages.
[3]:
#
Do not change or delete any of these lines of code
births
.
hist(
"Maternal Age"
)
plt
.
ylim(
-.002
,
.07
)
plt
.
scatter(np
.
mean(births
.
column(
"Maternal Age"
)),
0
, color
=
'red'
, s
=50
,
␣
,
→
zorder
=4
);
2
plt
.
scatter(np
.
median(births
.
column(
"Maternal Age"
)),
0
, color
=
'green'
, s
=50
,
␣
,
→
zorder
=5
);
We are also interested in the standard deviation of mother’s ages. The SD gives us a sense of how
variable mothers’ ages are around the average mothers’ age. If the SD is large, then the mothers’
heights should spread over a large range from the mean.
If the SD is small, then the mothers’
heights should be tightly clustered around the average mother height.
The SD of an array is defined as the root mean square of deviations (differences) from
average
.
Fun fact! (Greek letter sigma) is used to represent the SD and (Greek letter mu) is used for the
mean.
Question 1.3.
Run the cell below to see the width of one SD (blue) from the sample mean (red)
plotted on the histogram of maternal ages.
[4]:
#
calculate the mean and standard devuiation of ages
age_mean
=
np
.
mean(births
.
column(
"Maternal Age"
))
age_sd
=
np
.
std(births
.
column(
"Maternal Age"
))
#
Do not change or delete any of the following lines of code
births
.
hist(
"Maternal Age"
)
plt
.
ylim(
-.002
,
.07
)
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
plt
.
scatter(age_mean,
0
, color
=
'red'
, s
=50
, zorder
= 3
);
plt
.
scatter(age_mean
+
age_sd,
0
, marker
=
'^'
, color
=
'blue'
, s
=50
, zorder
= 4
);
plt
.
scatter(age_mean
-
age_sd,
0
, marker
=
'^'
, color
=
'blue'
, s
=50
, zorder
= 5
);
In this histogram, the standard deviation is not easy to identify just by looking at the graph.
However, the distributions of some variables allow us to easily spot the standard deviation on the
plot. For example, if a sample follows a
normal distribution
, the standard deviation is easily spotted
at the point of inflection (the point where the curve begins to change the direction of its curvature)
of the distribution.
Question 1.4.
Fill in the following code to examine the distribution of maternal heights, which
is roughly normally distributed. We’ll plot the standard deviation on the histogram, as before -
notice where one standard deviation (blue) away from the mean (red) falls on the plot.
[5]:
#
calculate the mean and standard devuiation of heights
height_mean
=
np
.
mean(births
.
column(
"Maternal Height"
))
height_sd
=
np
.
std(births
.
column(
"Maternal Height"
))
#
Do not change or delete any of the following lines of code
births
.
hist(
"Maternal Height"
, bins
=
np
.
arange(
55
,
75
,
1
))
plt
.
ylim(
-0.003
,
0.16
)
plt
.
scatter((height_mean),
0
, color
=
'red'
, s
=50
, zorder
= 3
);
4
plt
.
scatter(height_mean
+
height_sd,
0
, marker
=
'^'
, color
=
'blue'
, s
=50
, zorder
=
␣
,
→
3
);
plt
.
scatter(height_mean
-
height_sd,
0
, marker
=
'^'
, color
=
'blue'
, s
=50
, zorder
=
␣
,
→
3
);
We don’t always know how a variable will be distributed, and making assumptions about whether or
not a variable will follow a normal distribution is dangerous. However, the Central Limit Theorem
defines one distribution that always follows a normal distribution. The distribution of the
sums
and
means
of many large random samples drawn with replacement from a single distribution (regardless
of the distribution’s original shape) will be normally distributed. Remember that the Central Limit
Theorem refers to the distribution of a
statistic
calculated from a distribution, not the distribution
of the original sample or population. If this is confusing, ask a TA!
The next section will explore distributions of sample means, and you will see how the standard
deviation of these distributions depends on sample sizes.
3
2. Variability of the Sample Mean
By the
Central Limit Theorem
, the probability distribution of the mean of a large random sample
is roughly normal. The bell curve is centered at the population mean. Some of the sample means
are higher and some are lower, but the deviations from the population mean are roughly symmetric
on either side, as we have seen repeatedly.
Formally, probability theory shows that the sample
mean is an
unbiased estimate
of the population mean.
In our simulations, we also noticed that the means of larger samples tend to be more tightly
5
clustered around the population mean than means of smaller samples.
In this section, we will
quantify the
variability of the sample mean
and develop a relation between the variability and the
sample size.
Let’s take a look at the salaries of employees of the City of San Francisco in 2014. The mean salary
reported by the city government was about $75,463.92.
Note: If you get stuck on any part of this lab, please refer to
chapter 14 of the textbook
.
Read in the table
1. Read in the file ‘Georgia_Salaries_2021.csv’ and name the table ‘georgia_salaries’
2. Display all of the column names in ‘Georgia_Salaries_2021.csv’
3. Create an array named salaries that contains all of the values in the column ‘SALARY’
4. Find the mean of salaries.
[6]:
# insert your code here
georgia_salaries
=
Table
.
read_table(
'Georgia_Salaries_2021.csv'
)
georgia_salaries
georgia_salaries
.
labels
salaries
=
georgia_salaries
.
select(
"SALARY"
)
np
.
mean(salaries)
[6]:
SALARY
40883.1
[7]:
salary_mean
=
np
.
mean(salaries
.
column(
"SALARY"
))
print
(
'Mean salary of State of Georgia employees in 2022: '
,
␣
,
→
round
(salary_mean,
2
))
#
Do not change or delete any of the following lines of code
georgia_salaries
.
hist(
'SALARY'
, bins
=
np
.
arange(
0
,
300000+10000*2
,
10000
))
# georgia_salaries.hist('SALARY',bins=np.arange(0, 300000+10000*2, 10000))
Mean salary of State of Georgia employees in 2022:
40883.06
/opt/conda/lib/python3.8/site-packages/datascience/tables.py:5206: UserWarning:
FixedFormatter should only be used together with FixedLocator
axis.set_xticklabels(ticks, rotation='vertical')
6
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
[8]:
#
do not change or delete the following lines of code
georgia_salaries
.
hist(
'SALARY'
, bins
=
np
.
arange(
0
,
300000+10000*2
,
10000
))
plt
.
scatter(salary_mean,
0
, marker
=
'^'
, color
=
'red'
, s
=200
, zorder
= 3
);
plt
.
title(
'2022 salaries of State of Georgia employees'
);
7
Clearly, the population does not follow a normal distribution. Keep that in mind as we progress
through these exercises.
Let’s take random samples
with replacement
and look at the probability distribution of the sample
mean. As usual, we will use simulation to get an empirical approximation to this distribution.
Question 2.1.
The function
one_sample_mean
below takes 3 arguments:
table
(the name of a
table),
label
(the label of the column containing the variable), and
sample size
(the number of
employees in the sample). It samples with replacement from the table and returns the mean of the
label
column of the sample. Do not Delete or edit the cell below.
[9]:
# DO NOT DELETE OR EDIT THIS CELL
sample_size
= 30
def
one_sample_mean
(table, label, sample_size):
new_sample
=
table
.
sample(sample_size, with_replacement
=
True
)
new_sample_mean
=
np
.
mean(new_sample
.
column(label))
return
new_sample_mean
sample_average
=
round
(one_sample_mean(georgia_salaries,
'SALARY'
,
␣
,
→
sample_size),
2
)
8
print
(
'The average of'
,sample_size,
'randomly selected salaries is $'
,
␣
,
→
sample_average)
The average of 30 randomly selected salaries is $ 53665.82
The function
simulate_sample_mean
samples with replacement from the table and calculates the
mean of each sample. The function ’ displays an empirical histogram of the sample means.
[10]:
# DO NOT DELETE OR EDIT THIS CELL
"""Empirical distribution of random sample means"""
repetitions
= 100
def
simulate_sample_mean
(table, label, sample_size, repetitions):
means
=
make_array()
#
plt.clf()
for
i
in
np
.
arange(repetitions):
new_sample_mean
=
one_sample_mean(table, label, sample_size)
means
=
np
.
append(means, new_sample_mean)
xaxis_lo
=
min
(means)
xaxis_lo
=
np
.
trunc(xaxis_lo
/1000
)
*1000
# print('xaxis_lo',xaxis_lo)
xaxis_hi
=
max
(means)
xaxis_hi
=
np
.
ceil(xaxis_hi
/1000
)
*1000
# print('xaxis_hi = ',xaxis_hi)
print
(
"Sample size: "
,
round
(sample_size))
print
(
"Population mean:"
,
round
(np
.
mean(table
.
column(label))))
print
(
"Min of sample means"
,
round
(
min
(means)))
print
(
"Average of sample means: "
,
round
(np
.
mean(means)))
print
(
"Max of sample means"
,
round
(
max
(means)))
print
(
"Population SD:"
,
round
(np
.
std(table
.
column(label))))
print
(
"SD of sample means:"
,
round
(stats
.
tstd(means)))
return
means,xaxis_lo,xaxis_hi
def
plot_sample_means
(means,sample_size,xaxis_lo,xaxis_hi):
n, edges,patches
=
plt
.
hist(means, density
=
True
, bins
=
np
.
,
→
arange(xaxis_lo,xaxis_hi,
2500
))
plt
.
xlim(xaxis_lo, xaxis_hi)
plt
.
title(
'Sample Size '
+
str
(sample_size))
plt
.
text(xaxis_lo
+ 1000
,
max
(n)
- 0.00001
,
r'$\overline
{x}
=$'
+
␣
,
→
str
(
round
(np
.
mean(means))))
plt
.
text(xaxis_lo
+ 1000
,
max
(n)
- 0.00003
,
r'$S=$'
+
str
(
round
(stats
.
,
→
tstd(means))))
9
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
plt
.
show()
return
def
prop_in_range
(values,
range
):
return
Question 2.2.
Use the function
simulate_sample_mean
.
Set the sample size to 30, and the
number of repetitions to 100. The arguments are the name of the table, the label of the column
containing the variable, the sample size, and the number of simulations.
[11]:
sample_size
= 30
repetitions
= 100
means, xlo, xhi
=
simulate_sample_mean(georgia_salaries,
"SALARY"
, sample_size,
␣
,
→
repetitions)
#
do not change or delete the following lines of code
plot_sample_means(means, sample_size, xlo, xhi)
xhi
Sample size:
30
Population mean: 40883
Min of sample means 24918
Average of sample means:
41025
Max of sample means 57948
Population SD: 37652
SD of sample means: 6675
10
[11]:
58000.0
Question 2.2.1
Use the function
simulate_sample_mean
.
Set the sample size to 100, and the
number of repetitions to 100. The arguments are the name of the table, the label of the column
containing the variable, the sample size, and the number of simulations.
[12]:
sample_size
= 100
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
"SALARY"
, sample_size
␣
,
→
,repetitions)
plot_sample_means(means, sample_size, xlo, xhi)
Sample size:
100
Population mean: 40883
Min of sample means 32389
Average of sample means:
40776
Max of sample means 50716
Population SD: 37652
SD of sample means: 3816
11
Verify with your neighbor or TA that you’ve implemented the function above correctly.
If you
haven’t implemented it correctly, the rest of the lab won’t work properly, so this step is crucial.
In the following cell, we will create a sample of size 100 from
salaries
and graph it using our new
simulate_sample_mean
function.
Hint: You should see a distribution similar to something we’ve been talking about.
If not, check
your function
[13]:
#
do not change or delete the following lines of code
sample_size
= 200
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
,
␣
,
→
sample_size,repetitions)
plot_sample_means(means, sample_size, xlo, xhi)
Sample size:
200
Population mean: 40883
Min of sample means 33875
Average of sample means:
41219
Max of sample means 46986
Population SD: 37652
SD of sample means: 2514
12
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Question 2.3.
Simulate two sample means, one for a sample of 400 salaries and one for a sample
of 625 salaries. In each case, perform 10,000 repetitions. Don’t worry about the
plots.xlim
line
– it just makes sure that all of the plots have the same x-axis.
[14]:
sample_size
= 625
repetitions
= 10000
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
,
␣
,
→
sample_size,repetitions)
plot_sample_means(means, sample_size, xlo, xhi)
sample_size
= 400
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
,
␣
,
→
sample_size,repetitions)
plot_sample_means(means, sample_size, xlo, xhi)
Sample size:
625
Population mean: 40883
Min of sample means 35657
Average of sample means:
40905
Max of sample means 54508
Population SD: 37652
SD of sample means: 1551
13
Sample size:
400
Population mean: 40883
Min of sample means 34608
Average of sample means:
40896
Max of sample means 60887
Population SD: 37652
SD of sample means: 1871
14
Question 2.4.
Assign
q2_4
to an array of numbers corresponding to true statement(s) about the
plots from 2.3.
1. We see the Central Limit Theorem (CLT) in action because the distributions of the sample
means are bell-shaped.
2. We see the Law of Averages in action because the distributions of the sample means look like
the distribution of the population.
3. One of the conditions for CLT is that we have to draw a small random sample with replacement
from the population.
4. One of the conditions for CLT is that we have to draw a large random sample with replacement
from the population.
5. One of the conditions for CLT is that the population must be normally distributed.
6. Both plots in 2.3 are roughly centered around the population mean.
7. Both plots in 2.3 are roughly centered around the mean of a particular sample.
8. The distribution of sample means for sample size 625 has less variability than the distribution
of sample means for sample size 400.
9. The distribution of sample means for sample size 625 has more variability than the distribution
of sample means for sample size 400.
[15]:
q2_4
=
make_array(
1
,
4
,
6
,
8
)
Below, we’ll look at what happens when we take an increasing number of resamples of a fixed
sample size. Notice what number in the code changes, and what stays the same. How does the
distribution of the resampled means change?
15
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
[16]:
# do not chage or delete the following lines of code
sample_size
= 100
num_reps
= 500
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
# plt.xlim(30000, 100000);
Sample size:
100
Population mean: 40883
Min of sample means 31370
Average of sample means:
40643
Max of sample means 50761
Population SD: 37652
SD of sample means: 3481
[17]:
# Do not change or delete the following lines of code
num_reps
= 1000
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
# plt.xlim(50000, 100000);
Sample size:
100
Population mean: 40883
16
Min of sample means 29644
Average of sample means:
41071
Max of sample means 131166
Population SD: 37652
SD of sample means: 4685
[18]:
num_reps
= 5000
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
# plt.xlim(50000, 100000);
Sample size:
100
Population mean: 40883
Min of sample means 29202
Average of sample means:
40987
Max of sample means 110933
Population SD: 37652
SD of sample means: 3894
17
[19]:
num_reps
= 10000
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
# plt.xlim(50000, 100000);
Sample size:
100
Population mean: 40883
Min of sample means 29401
Average of sample means:
40856
Max of sample means 71724
Population SD: 37652
SD of sample means: 3565
18
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
What did you notice about the distributions of sample means in the four histograms above? Discuss
with your neighbors. If you’re unsure of your conclusion, ask your TA.
Question 2.5.
Assign the variable
SD_of_sample_means
to the integer corresponding to your
answer to the following question:
When I increase the number of resamples that I take, for a fixed sample size, the SD of my sample
means will…
1. Increase
2. Decrease
3. Stay about the same
4. Vary wildly
[20]:
SD_of_sample_means
= 3
Question 2.6.
Let’s think about how the relationships between population SD, sample SD, and
SD of sample means change with varying sample size. Which of the following is true? Assign the
variable
pop_vs_sample
to an array of integer(s) that correspond to true statement(s).
1. Sample SD gets smaller with increasing sample size.
2. Sample SD gets larger with increasing sample size.
3. Sample SD becomes more consistent with population SD with increasing sample size.
4. SD of sample means gets smaller with increasing sample size.
5. SD of sample means gets larger with increasing sample size.
6. SD of sample means stays the same with increasing sample size.
19
[21]:
pop_vs_sample
=
make_array(
4
,
3
)
Run the following six cells multiple times and examine how the sample SD and the SD of sample
means change with sample size.
The first histogram is of the sample; the second histogram is the distribution of sample means with
that particular sample size. Adjust the bins as necessary.
[22]:
sample_size
= 10
sample_10
=
georgia_salaries
.
sample(sample_size)
sample_10
.
hist(
"SALARY"
)
plt
.
title(
'10 Sampled Salaries'
)
# print("Sample SD: ", np.std(sample_10.column("SALARY")))
# simulate_sample_mean(georgia_salaries, 'SALARY', 10, 1000)
# plt.xlim(5,120000);
# plt.ylim(0, .0001);
# plt.title('Distribution of sample means for sample size 10');
[22]:
Text(0.5, 1.0, '10 Sampled Salaries')
Distribution of Sample Means
[23]:
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
20
Sample size:
10
Population mean: 40883
Min of sample means 11623
Average of sample means:
40811
Max of sample means 737767
Population SD: 37652
SD of sample means: 13235
[24]:
sample_size
= 200
sample_200
=
georgia_salaries
.
sample(sample_size)
sample_200
.
hist(
"SALARY"
)
plt
.
title(
'200 Salaries'
)
[24]:
Text(0.5, 1.0, '200 Salaries')
21
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Distribution of Sample Means
[25]:
print
(
"Sample SD: "
, np
.
std(sample_200
.
column(
"SALARY"
)))
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
# plt.title('Distribution of sample means for sample size 200');
Sample SD:
35181.29601530076
Sample size:
200
Population mean: 40883
Min of sample means 31536
Average of sample means:
40792
Max of sample means 77182
Population SD: 37652
SD of sample means: 2593
22
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
[26]:
sample_size
= 1000
sample_1000
=
georgia_salaries
.
sample(
1000
)
sample_1000
.
hist(
"SALARY"
)
plt
.
title(
'1000 Salaries'
)
[26]:
Text(0.5, 1.0, '1000 Salaries')
23
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
[27]:
print
(
"Sample SD: "
, np
.
std(sample_200
.
column(
"SALARY"
)))
means, _lo, _hi
=
simulate_sample_mean(georgia_salaries,
'SALARY'
, sample_size,
␣
,
→
num_reps)
plot_sample_means(means, sample_size, xlo, xhi)
Sample SD:
35181.29601530076
Sample size:
1000
Population mean: 40883
Min of sample means 36653
Average of sample means:
40881
Max of sample means 50722
Population SD: 37652
SD of sample means: 1184
24
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
You should notice that the distribution of means gets narrower and spikier, and that the distribution
of the sample increasingly looks like the distribution of the population as we get to larger sample
sizes.
Let’s illustrate these trends. Below, you will see how the sample SD changes with respect to sample
size (N). The blue line is the population SD.
The next cell shows how the SD of the sample means changes relative to the sample size (N).
[28]:
# Don't change this cell, just run it!
def
sample_means
(sample_size):
means
=
make_array()
for
i
in
np
.
arange(
1000
):
sample
=
georgia_salaries
.
sample(sample_size)
.
column(
'SALARY'
)
means
=
np
.
append(means, np
.
mean(sample))
return
np
.
std(means)
sample_mean_SDs
=
make_array()
for
i
in
np
.
arange(
50
,
1000
,
100
):
sample_mean_SDs
=
np
.
append(sample_mean_SDs, sample_means(i))
Table()
.
with_columns(
"SD of sample means"
, sample_mean_SDs,
"Sample Size"
, np
.
,
→
arange(
50
,
1000
,
100
))\
.
plot(
"Sample Size"
,
"SD of sample means"
)
25
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
From these two plots, we can see that the SD of our
sample
approaches the SD of our population
as our sample size increases, but the SD of our
sample means
(in other words, the variability of the
sample mean) decreases as our sample size increases.
Question 2.7.
Is there a relationship between the sample size and the standard deviation of
the sample mean? Assign
q2_7
to the number corresponding to the statement that answers this
question.
1. The SD of the sample means is inversely proportional to the square root of sample size.
2. The SD of the sample means is directly proportional to the square root of sample size.
[29]:
q2_7
= 1
Throughout this lab, we have been taking many random samples from a population. However, all
of these principles hold for bootstrapped resamples from a single sample. If your original sample
is relatively large, all of your re-samples will also be relatively large, and so the SD of resampled
means will be relatively small.
26
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
In order to change the variability of your sample mean, you’d have to change the size of the original
sample from which you are taking bootstrapped resamples.
[ ]:
27
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Documents
Recommended textbooks for you

Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill

Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL

Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
Recommended textbooks for you
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt

Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill

Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL

Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt