Assignment 2 Complete - QUA0003

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Algonquin College *

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0003

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Statistics

Date

Apr 3, 2024

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docx

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4

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Assignment #2 (6%) This assignment relates to the Course Learning Requirements: CLR2 Calculate Summary Measures Objective of this Assignment : Evaluate the calculation and interpretation of measures of central tendency (averages) and measures of dispersion. Instructions: Use Word or Excel to solve the following eight exercises, evaluated out of 37 points. Please show all your work. Exercises 1) Consider the following sample values: 1.3, 7.0, 3.6, 4.1, 5.0. (a)Compute the mean; (b) Calculate ( X X ) . Round off to nearest 10 th . (4 points) a) mean: 1.3 + 7.0 + 3.6 + 4.1 + 5.0 = 21 21/5 = 4.2 b) X X ( X X ) 1.3 4.2 -2.9 7.0 4.2 2.8 3.6 4.2 -0.6 4.1 4.2 -0.1 5.0 4.2 0.8 2) The Bookstall Inc. is a specialty bookstore concentrating on used books sold via the Internet. Paperbacks are $1 each, and hardcover books are $3.50. Of the 50 books sold last Tuesday morning, 40 were paperback, and the rest were hardcover.   What was the weighted mean price of a book? Round to nearest 100-th. Round to nearest 100 th (2 points) 3.50 × 10 = 35 X = 40 + 35 50 = $1.50
3) Listed below is the number of hours that a sample of students spent travelling to college each week. Round off to nearest 100 th (4 points)   9.0 8.5 8.0 9.1 10.3 11.0 11.5 10.3 10.5 9.8 9.3 8.2 8.2 8.5   a) What is the median number of hours spent travelling per week? (9.0 + 8.5 + 8.0 + 9.1 + 10.3 + 11.0 + 11.5 + 10.3 + 10.5 + 9.8 + 9.3 + 8.2 + 8.2 + 8.5)/14 = 10.05 b) What is the mode? mode: 8.2, 8.5, 10.3 4) Gas prices in St. John’s, Newfoundland, have increased from 64.1 cents per litre for regular unleaded in 1990 to 129.6 cents per litre in 2013. What was the geometric mean annual increase for the period? (2 points) 64.1 × 129.6 = 91.1 5) The Business School at a local college offers eight sections of basic statistics. Following are the number of students enrolled in these sections: 34, 46, 52, 29, 41, 38, 36, and 28. Find (a) the range, (b) the arithmetic mean, (c) the mean deviation; (d) interpret the range and the mean deviation. (5 points) a) range: 52 – 28 = 24 b) mean: (34 + 46 + 52 + 29 + 41 + 38 + 36 + 28)/8 = 38 c) mean deviation 28 – 38 = 10 29 – 38 = 9 34 – 38 = 4 36 – 38 = 2 X = 50 8 = 6.25 38 – 38 = 0 41 – 38 = 3 46 – 38 = 8 52 – 38 = 14 Total = 50 6) A consumer watchdog organization is concerned about credit card debt. A survey of 10 young adults with credit card debt of more than $2000 showed they paid an average of just over $100 per month against their balances. Listed below are the amounts ($) each young adult paid last month:   100, 126, 103, 93, 99, 113, 87, 101, 109, 100.
Compute the variance and the standard deviation. (4 points) X X X X ( X X ) 2 100 103.1 -3.1 9.61 126 103.1 22.9 524.41 103 103.1 -0.1 0.01 93 103.1 -10.1 102.01 99 103.1 -4.1 16.81 113 103.1 9.9 98.01 87 103.1 -16.1 259.21 101 103.1 -2.1 4.41 109 103.1 5.9 34.8l 100 103.1 -3.1 9.61 1031 1058.9 S = 1058.9 9 variance = 117.66 deviation = 10.85 7) Consider the salaries, in thousands of dollars, for a sample of 15 chief financial officers in the electronics industry. Round off to nearest 100 th (6 points)  Salaries $516.0 548.0 566.0 534.0 586.0 529.0 546.0 523.0 538.0 523.0 551.0 552.0 486.0 558.0 574.0         a) Determine the mean, the median, and the standard deviation b) Determine the coefficient of skewness $516.00 548 566 534 586 529 546 523 538 523 551 552 486 558 574 Mean $542.00 Median $546.00 Deviation 27.47 Skewness -0.38
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8) The masses (in kilograms) of a sample of five boxes being sent by United Parcel Service (UPS) are: 12, 6, 7, 3, and 10. Round to nearest 100 th (10 points) a) Obtain the range. b) Get the mean deviation. c) Find the standard deviation. 3 4.6 6 1.6 7 0.6 10 2.4 12 4.4 13.6 Range 9 Mean 7.6 Mean deviation 2.72 Standard deviation 3.51 d) Using Chebyshev’s theorem, at least what percentage of the observations must be within 2.5 standard deviations of the mean? 1 1 2.5 2 = 84 % e) Using the Empirical Rule, about 68 percent of the values would occur between what values?   7.6 + 2.72 = 10.32 7.6 2.72 = 4.88 The values that would occur between 4.88 and 10.32 is 7.6.