unit 6 assessment for statistics

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Herzing University, Brookfield *

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MA320-7A

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Statistics

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Feb 20, 2024

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Unit 6 assessment-testing hypotheses: Shari Samson Herzing University MA320-Statistics Professor Dr. Fernandez December 10, 2023

In this unit, we are to decide whether the variances in resting heart rates between males and females differ significantly. The male resting heart rate mean is 79.0, and the mean resting heart rate for females is 80.5. Between the means, there are 1.4 mean differences. I ran a 2- sample t-test assuming that the variances were not equal. My null hypothesis is that the mean heart rate for males is equal to the female's mean heart rate. The alternative hypothesis is that the male mean heart rate is not equal to the female. Once I reviewed my data, my p-value was greater than 0.05, so my null hypotheses can’t be rejected. “A p-value that is higher than 0.5 is not significantly different it supports my null hypotheses” (Beers, 2023). Also, the difference between the male and female resting heart rate is not significantly different. t-Test: Two-Sample Assuming Unequal Variances Variable 1 Variable 2 Mean 80.38519 81.76957 Variance 49.73716 39.29796 Observations 108 92 Hypothesized Mean Difference 0 df 198 t Stat -1.46936 P(T<=t) one-tail 0.071662 t Critical one-tail 1.652586 P(T<=t) two-tail 0.143324 t Critical two-tail 1.972017

References: Beers, B. (2023, March 28). P-value: What it is, how to calculate it, and why it matters. Investopedia. https://www.investopedia.com/terms/p/p-value.asp#:~:text=A%20p%2Dvalue %20measures%20the,significance%20of%20the%20observed%20difference.&text=p%2Dvalue %20can%20serve%20as,confidence%20levels%20for%20hypotheses%20testing.

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t-Test: Two-Sample Assuming Unequal Variances Variable 1 Variable 2 Mean 80.38519 81.76957 Variance 49.73716 39.29796 Observations 108 92 Hypothesized Mean Difference 0 df 198 t Stat -1.46936 P(T<=t) one-tail 0.071662 t Critical one-tail 1.652586 P(T<=t) two-tail 0.143324 t Critical two-tail 1.972017