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e B . 2021 ZheZhangd | © | nsmmn:ssm Homework: Week 3: Unit 5 Score: 14 of 14 pts 4 (14 complete) w | p HW Score: 100%, 136 of 136 p ) 5.1.1-T Question Help w { Given the probability distributions shown to the right, complete the following parts. Distribution A Distribution B o a. Compute the expected value for each distribution. i P(X=x)) Xi P(X=x) b. Compute the standard deviation for each distribution. 0 0.06 0 0.49 ¢. Whatis the probability that x will be at least 3 in Distribution A and Distribution B? g 0.10 u 020 d. Compare the results of distributions A and B. 2 0.15 2 0.15 3 0.20 3 0.10 4 0.49 4 0.06 . What is the probability that x will be at least 3 in Distribution A? P(x23)= 0.69 : (Type an integer or a decimal. Do not round.) What is the probability that x will be at least 3 in Distribution B? P(x23)= 0.16 (Type an integer or a decimal. Do not round.) d. Use these results to compare distribution A and distribution B. X Distribution A is symmetric, distribution B is symmetric. Distribution A is symmetric, distribution B is left-skewed. -4 Distribution A is left-skewed, distribution B is right-skewed. Distribution A is right-skewed, distrib;nion B is symmetric. Distribution A is right-skewed, distribution B is left-skewed. Question is complete. All parts showing (D oo e [@ Discrete Proba X | @ VoiceThread - | X | G it##8-Googl X gy DoHomework X | @ YouAreTrying X | 3 solved: YouAr x | ar o & (e R mathxl.comlstuden\/P!ayerHomewurk.aspx?homeworkld=596104073&questionld:g&flushed:fsls... S oare On-line MgtOp215-Business Statistics: Summer2021 ZheZhang & | © | 05/29/2111:55 AM Homework: Week 3: Unit 5 3 Score: 8 of 8 pts 4 20f 14 (14 complete) w |I] HW Score: 100%, 136 of 136 pts ¥)5.1.3-T Question Help w fi Aregional automobile dealership sent out fiers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $23,000, a $75 gas card, or a $5 shopping card. To claim his or her prize, a prospective customer needed to present the flier at the dealership's showroom. The fine print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,829, the chance of winning the gas card was 1 out of 31,829, and the chance of winning the shopping card was 31,827 out of 31,829. Complete parts (a) through (d). a. How many fliers do you think the automobile dealership sent out? Assume there is one car and one gas card available. 31829 fliers b. Using your answer to (a) and the probabilities listed on the flier, what is the expected value of the prize won by a prospective customer receiving a flier? 1=$5.72 (Round to the nearest cent as needed.) c. Using ybur answer to (a) and the probabilities listed on the flier, what is the standard deviation of the value of the prize v.Ln by a prospective customer receiving a flier? ©0=$128.89 (Round to the nearest cent as needed.) d. Do you think this is an effective promotion? Why or why not? v Yes. The promotion will turn a profit if the customers redeeming fliers make an average purchase greater than the expected value of the prize won, which is likely. B. No. The promotion will only turn a profit if the customers redeeming fliers make an average purchase less than the expected value of the prize won, which is unlikely. C. Yes. The promotion will turn a profit if any of the customers redeeming fliers make a purchase, which is likely. D. No. The promotion will not turn a profit regardless of how many customers redeeming fliers make a purchase. Question is complete. All parts showing (NSRS el « > L)

o e ] e > C 'R matthAcom/Student/P|ayerHomework.aspx?homeworkId:596‘l04073&quesfionld:g&flushed:fals... ¥ On-line MgtOp215-Business Statistics: Summer2021 ] ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 Score: 6 of 6 pts )5.1.5-T The number of arrivals per minute at a bank located in the central business district of a large. city was recorded over a period of 200 minutes, with the results shown in the table below. Complete (a) through (c) to the right. Arrivals Frequency o 2 DN A ©N = O S Question is complete. All parts showing (NS Q) = T D Discrete Prob: X | @ VoiceThread - = x | 5 = G HHH - Gooy & S On-line MgtOp215-Business Statistics: Summer2021 4 | 30f 14 (14 complete) w B ® & 8. mathxl.com/Student/PlayerHomework.aspx?homeworkid=596104073&questionld=9&flushed=fals.. & ¢ HW Score: 100%, 136 of 136 P Question Help w ‘ a. Compute the expected number of arrivals per minute. 1= 2595 (Type an integer or decimal rounded to three decimal places as needed.) b. Compute the standard deviation. o= 1.789 (Type an integer or decimal rounded to three decimal places as needed.) c. What is the probability that there will be fewer than 2 arrivals in a given minute? P(x<2)=0.325 (Type an integer or decimal rounded to three decimal places as needed.) %@ “V‘Q@‘ [ ,_ @ YouareTryina x | [ Solved: You A x | + @ Do Homework x ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 Score: 10 of 10 pts &) 51.7-T below. a. Compute the expected return for stock X and for stock Y. The expected return for stock X is 87 . (Type an integer or a decimal. Do not round.) The expected return for stock Y is 109 . (Type an integer or a decimal. Do not round.) b. Compute the standard deviation for stock X and for stock Y. The standard deviation for stock X is 86.38 . (Round to two decimal places as needed.) The standard deviation for stock Y is 1114.23 . (Round to two decimal places as needed.) . Would you invest in stock X or stock Y? Explain. Choose the correct answer below. Question is complete. All parts showing (IS 4 | 40f14 (14 complete) w D You are trying to develnp a strategy for investing in two different stocks. The anticipated annual return fora $1,000 investment in each stock under four different economic conditions has the probability distribution shown to the right. Complete parts (a) through (c) HW Score: 100%, 136 of 136 pts. Question Help w 'fl Retuns o Economic ProbabilityCondition Stock X Stock Y 0.1 Recession =120 -190 0.2 Slow growth 20 40 04 Moderate growth 110 150 03 Fast growth 170 200 Based on the expected value, stock X should be chosen. However, stock X has a larger standard deviation, resulting in a higher risk, which should be taken into consideration. ¥ . Based on the expected value, stock Y should be chosen. However, stock Y has a larger standard deviation, resulting in a higher risk, which should be taken into consideration. ® EERGIFERED T [ TELE P R I

L R Ry Voicerrread | x | G 1@ v H "‘ ete Prob: X | @ VoiceThread - | x | G it#8-Googl X @ DoHomewark X @ YouAreTrying X | @ sowed:Your: x | + F = a_ ma(hxl.com/Student/PtayerHomewark.aspx?homeworkld:596104073&quesfionld:Q&flushed:faIs,.. L3 e I On-line MgtOp215-Business Statistics: Summer2021 ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 Score: 8 of 8 pts 4 | 70f14 (14 complete) w D HW Score: 100%, 136 of 136 pts @ 5.2.13-T Question Help w ¢ Astudent is @king a mul(tplg»chuice exam in which each question has two choices. Assuming that she has no knowledge of the correct answers to any of the questions, she has decided ona snfa(egy in which she will plac_e two balls (marked A and B) into a box. She randomly selects one ball for each question and replaces the ball in the box. The marking on the ball will determine her answer to the question. There are eight multiple-choice questions on the exam. Complete parts (a) through (d) below. a. What is the probability that she will get eight questions correct? 0.0039 (Round to four decimal places as needed.) b. What is the probability that she will get at least seven questions correct? 0.0351 (Round to four decimal places as needed.) 5 c. What s the probabilty that she will get no questions correct? 0.0039 (Round to four decimal places as needed.) d. What is the probability that she will get no more than two questions correct? 0.1445 (Round to four decimal places as needed.) Question is complete. Similar Question All parts showing (EEEEED : - - o i I = Discrete Prob: X | @ VoiceThread - G itH88 -Googl X @ DoHomework X & @ x | [3 soived: Yourr x | + i :— =i e a8 mathxlAcom/Student/PIayerHomework.aspx?homeworkld=596104073&queslionId:Q&flushed:fals... I v & X On-line MgtOp215-Business Statistics: Summer2021 ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 S Score: 10 of 10 pts 4 | 80f 14 (14 complete) w IZ] HW Score: 100%, 136 of 136 ¢ @ 5.2.15-T QuestionHelpw | { Past records i.ndicale .thal the probability of online retail orders that tun out to be fraudulent is 0.06. Suppose that, on a given day, 19 online retail orders are placed. Assume that the number of online retail orders that turn out to be fraudulent is distributed as a binomial random variable. Complete parts (a) through (d) below. a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent? The mean number of online retail orders that turn out to be fraudulent is 1.1400 . (Type an integer or a decimal. Round to four decimal places as needed.) The standard deviation of the number of fraudulent retail orders is 1.035 . (Type an integer or a decimal. Round to three decimal places as needed.) o b. What is the probability that zero online retail orders will turn out to be fraudulent? 0.3086 (‘i’ype an integer or a decimal. Round to four decimal places as needed.) c. Whatvis the probability that one online retail order will tum out to be fraudulent? 0.3743 (Type an integer or a decimal. Round to four decimal places as needed.) d. What is the probability that two or more online retail orders will turn out to be fraudulent? 0.3171 (Type an integer or a decimal. Round to four decimal places as needed.) Question is complete. All narte chowina IS

On-line MgtOp215-Business Statistics: Summer2021 ZheZhanga | @ 05/29/21 11 Homework: Week 3: Unit 5 Score: 20 of 20 pts 4 | 90f 14 (14 complete) w D HW Score: 100%, 136 ( 5.2.16-T 1 Question Help Suppose that you and two friends go to a restaurant, which last month filled approximately 90.2% of the orders correctly. Complete parts (a) through (e) below. B Click the icon to view the order-filling data for two other restaurants. Y T T G T TG IG 11 11T S e TG S Ty T The probability is 0.0009 . (Round to four decimal places as needed.) c. What is the probability that at least two of the three orders will be filled correctly? The probability is 0.973 . (Round to four decimal places as needed.) d. What are the mean and standard deviation of the binomial distribution used in (a) through (c)? Interpret these values. The mean is 2.706 . (Round to four decimal places as needed.) The standard deviation is 0.515 . (Round to four decimal places as needed.) Interpret the mean and standard deviation. L3 On average, 2.706 orders are correctly filled, while there is an approximate variation of 0.515 from the average number of orders correctly filled. (Round to four decimal places as needed.) e. Compare the results of (a) through (d) win:| those of the two restaurants given in the popup tables. Restaurant C has a slightly higher probability of filling orders correctly. Question is complete. tion l All parts showing (D Similar Quesf B:00=" GBBBCOFFALTONG « #[ o < S C & mathxl,com/Sludem/PIayerHomework.aspx?homeworkld:596104073&ques!ionld=9&(Iushed=fals... RE Sy o N On-line MgtOp215-Business Statistics: Summer2021 ZheZhang& | © | 0512 Homework: Week 3: Unit 5 Score: 10 of 10 pts 4 | 100f 14 (14 complete) w B HW Score: 100% ¢)5.3.19 Quest Assume a Poisson distribution. Find the following probabilities. a.Let2=3.0, find P(X22). d.LetA=3.5, find P(X 22). e. LetA=523, find P(X<3). a. When A=3.0, P(X22) = 0.801 (Round to three decimal places as needed.) . b. When 1=0.3, P(Xs1)= 0.963 (Round to three decimal places as needed.) c. When A=6.0, P(X<3)= 0.151 (Round to three decimal places as needed.) d. When 2=3.5, P(X22)= 0.864 (Round to three decimal places as needed.) e. When A=5.3, P(X<3)= 0.225 N (Round to three decimal places as needed.) Question is complete. All parts showing (D

P Somwmsmrevwes A gvUIGeINEad =X |Gl FTRES = Googl X | @ DoHomework X | @) You'Are Trying X! SO C & solved: You A 'R mathxl.com/studenthIayerHomewcrk.aspx?homewcrkld:596104073&ques!ionId:e&flushed:fa!s... S On-line MgtOp215-Business Statistics: Summer2021 ZheZhangas | © | 05/29/21 11:57 AM ‘Homework: Week 3: Unit 5 Ea fcom: 8 of 8 pts 4 | 130f14 (14 complete) w HW Score: 100%, 136 of 136 pts ¢)5.3.26-T Question Hopw | £ A consumer response team hears directly from consumers about the challenges they face in the marketplace, brings their concerns to the attention of financial institutions, and assists in addressing their complaints. The consumer r team accepts ints related to mortgages, bank accounts and services, private student loans, other consumer loans, and credit reporting. An analysis of complaints over time indicates that the mean number of credit reporting complaints registered by consumers is 1.85 per day. Assume that the number of credit reporting complaints registered by consumers is distributed as a Poisson random variable. Complete parts (a) through (d) below. a. What is the probability that on a given day, no credit reporting complaints will be registered by consumers? The probability that no complaints will be registered is 0.1572 . (Round to four decimal places as needed.) b. What is the probability that on a given day, exactly one credit reporting complaint will be registered by consumers? The pr ility that exactly one int will be regis is 0.2909 . (Round to four decimal places as needed.) ¢. What is the probability that on a given day, more than one credit reporting complaint will be registered by consumers? The probability that more than one complaint will be registered is 0.5519 . (Round to four decimal places as needed.) d. What is the probability that on a given day, fewer than two credit reporting complaints will be registered by consumers? The probability that fewer than two complaints will be registered is 0.4481 . (Round to four decimal places as needed.) Question is complete. All parts showing 5 o= awn | & o (6 & mathxI.com/S(udem/PIayerHomework.aspx?homeworkld:596104073&questicnld=9&f|ushed:(als.A, L4 5ag On-line MgtOp215-Business Statistics: Summer2021 ZheZhang& | © | 05/29/2111:57AM Homework: Week 3: Unit 5 Score: 10 of 10 pts Pl 14 of 14 (14 complete) w = ) HW Score: 100%, 136 of 136 pt ) 5.3.27-T QuestionHep v | £ A company publishes statistics concerning car quality. The initial quali | A quality score measures the number of problems per new car sold. For one year, Car A had 1.48 problems per car. Let the random variable X be equal to the number of problems with a newly purchased model A car. Complete parts (a) through (d). £ a. What assumptions must be made in order for X to be distributed as a Poisson random variable? Select all the assumptions for a Poisson distribution. ¥ 5. The probabilty of a problem is the same for each period of time. At least 30 model A cars are sold. v The number of problems in a given period is independent of the number of problems in any other period. v The probability of a problem in a time period approaches zero as the length of the time period becomes smaller. b. Making the assumptions as in (a), if you purchased a model A car, what is the probabilfy that the new car will have zero problems? The probability that the new model A car will have zero problems is 0.2276 . (Round to four decimal places as needed.) I ¢. Making the assumptions s in (a), if you purchased a model A car, what is the probabilty that the new car will have two or fewer problems? The probability that a new model A car will have twa o fewer problems is (0.8139 . (Round to four decimal places as needed.) d. Give an operational definition for "problem." A problem is when parts of the vehicle wear out or break sooner than anticipated, or the vehicle requires more maintenance than expected for its age. o4 A problem is when a vehicle has a complete break down or malfunction, or when controls or features are difficult to use or understand. Question is complete. All parts showing (NI

T 7 G m_matnxi i 1z cum[s!udenthIayerHomework.aspx?homeworkld=596104073&questlonld=9&flushed=fa|s.,. ¥ v & N @ On-line MgtOp215-Business Statistics: Summer2021 ZheZhang& | © | 05/29/2111:57 AM Homework: Week 3: Unit 5 Score: 10 of 10 pts 4 ) 5.3.27-T Savi 14 of 14 (14 complete) w HW Score: 100%, 136 of 136 p Question Help w { A company publishes statistics concerning car quality. The initial quality score measures the number of problems per new car sold. For one year, Car A had 1.48 problems per car. Let the random variable X be equal to the number of problems with a newly purchased model A car. Complete parts (a) through (d). The probability that the new model A car will have zero problems is 02276 . (Round to four decimal places as needed.) €. Making the assumptions as in (a), if you purchased a model A car, what is the probability that the new car will have two or fewer problems? The probability that a new model A car will have two or fewer problems is 0.8139 . (Round to four decimal places as needed.) d. Give an operational definition for "problem.” A problem is when parts of the vehicle wear out or break sooner than anticipated, or the vehicle requires more maintenance than expected for its age. ¥ & Aproblem is when a vehicle has a complete break down or malfunction, or when controls o features are difficult to use or understand. A problem is when a vehicle gets into a traffic violation, an accident, or an owner is injured while driving the vehicle. A problem is when an owner files a complaint or becomes dissatisfied with a vehicle's performance, usability, or reliability. Why is the operational definition important in interpreting the initial quality score? The operational definition helps manufacturers learn what cars to stop making. 4 The operational definition determines what incidents the initial quality score describes. The operational definition determines. if the initial quality score is significant or not. The operational definition helps owners lean of what kinds of problems their car has. Question is complete. i . similar Question |} Al parts showing (EEEED * @Eww) (@ D) On-line MgtOp215-Business Statistics: Summer2021 ZheZhangd | © | 05/29/21 | 11:55 AM Homework: Week 3: Unit 5 Eae Score: 14 of 14 pts 10114 (14 complete) w | p HW Score: 100%, 136 of 136 pts— 5.1.1-T Question Helpw = ¥ Given the probability distributions shown to the right, complete the following parts. Distribution A Distribution B o a. Compute the expected value for each distribution. L BXEX) X PX=x) b. Compute the standard deviation for each distribution. 0.06 0.49 . What s the probability that x will be at least 3 in Distribution A and Distribution B? 010 020 d. Compare the results of distributions A and B. 0.15 0.15 0.20 0.10 049 0.06 awN o s wN O a. What is the expected value for distribution A? = 2.960 (Type an integer or decimal rounded to three decimal places as needed.) What is the expected value for distribution B? n= 1.040 (Type an integer or decimal rounded to three decimal places as needed.) b. What s the standard deviation for distribution A? L3 o= 1.256 (Type an integer or decimal rounded to three decimal places as needed.) What is the standard deviation for distribution B? 0= 1.256 ; (Type an integer or decimal rounded to three decimal places as needed.) . What is tha probabilitv that x will be at least 3 in Distribution A? Question is complete. G All parts showing (IS ez >