2

e B . 2021 ZheZhangd | © | nsmmn:ssm Homework: Week 3: Unit 5 Score: 14 of 14 pts 4 (14 complete) w | p HW Score: 100%, 136 of 136 p ) 5.1.1-T Question Help w { Given the probability distributions shown to the right, complete the following parts. Distribution A Distribution B o a. Compute the expected value for each distribution. i P(X=x)) Xi P(X=x) b. Compute the standard deviation for each distribution. 0 0.06 0 0.49 ¢. Whatis the probability that x will be at least 3 in Distribution A and Distribution B? g 0.10 u 020 d. Compare the results of distributions A and B. 2 0.15 2 0.15 3 0.20 3 0.10 4 0.49 4 0.06 . What is the probability that x will be at least 3 in Distribution A? P(x23)= 0.69 : (Type an integer or a decimal. Do not round.) What is the probability that x will be at least 3 in Distribution B? P(x23)= 0.16 (Type an integer or a decimal. Do not round.) d. Use these results to compare distribution A and distribution B. X Distribution A is symmetric, distribution B is symmetric. Distribution A is symmetric, distribution B is left-skewed. -4 Distribution A is left-skewed, distribution B is right-skewed. Distribution A is right-skewed, distrib;nion B is symmetric. Distribution A is right-skewed, distribution B is left-skewed. Question is complete. All parts showing (D oo e [@ Discrete Proba X | @ VoiceThread - | X | G it##8-Googl X gy DoHomework X | @ YouAreTrying X | 3 solved: YouAr x | ar o & (e R mathxl.comlstuden\/P!ayerHomewurk.aspx?homeworkld=596104073&questionld:g&flushed:fsls... S oare On-line MgtOp215-Business Statistics: Summer2021 ZheZhang & | © | 05/29/2111:55 AM Homework: Week 3: Unit 5 3 Score: 8 of 8 pts 4 20f 14 (14 complete) w |I] HW Score: 100%, 136 of 136 pts ¥)5.1.3-T Question Help w fi Aregional automobile dealership sent out fiers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $23,000, a $75 gas card, or a $5 shopping card. To claim his or her prize, a prospective customer needed to present the flier at the dealership's showroom. The fine print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,829, the chance of winning the gas card was 1 out of 31,829, and the chance of winning the shopping card was 31,827 out of 31,829. Complete parts (a) through (d). a. How many fliers do you think the automobile dealership sent out? Assume there is one car and one gas card available. 31829 fliers b. Using your answer to (a) and the probabilities listed on the flier, what is the expected value of the prize won by a prospective customer receiving a flier? 1=$5.72 (Round to the nearest cent as needed.) c. Using ybur answer to (a) and the probabilities listed on the flier, what is the standard deviation of the value of the prize v.Ln by a prospective customer receiving a flier? ©0=$128.89 (Round to the nearest cent as needed.) d. Do you think this is an effective promotion? Why or why not? v Yes. The promotion will turn a profit if the customers redeeming fliers make an average purchase greater than the expected value of the prize won, which is likely. B. No. The promotion will only turn a profit if the customers redeeming fliers make an average purchase less than the expected value of the prize won, which is unlikely. C. Yes. The promotion will turn a profit if any of the customers redeeming fliers make a purchase, which is likely. D. No. The promotion will not turn a profit regardless of how many customers redeeming fliers make a purchase. Question is complete. All parts showing (NSRS el « > L)

o e ] e > C 'R matthAcom/Student/P|ayerHomework.aspx?homeworkId:596‘l04073&quesfionld:g&flushed:fals... ¥ On-line MgtOp215-Business Statistics: Summer2021 ] ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 Score: 6 of 6 pts )5.1.5-T The number of arrivals per minute at a bank located in the central business district of a large. city was recorded over a period of 200 minutes, with the results shown in the table below. Complete (a) through (c) to the right. Arrivals Frequency o 2 DN A ©N = O S Question is complete. All parts showing (NS Q) = T D Discrete Prob: X | @ VoiceThread - = x | 5 = G HHH - Gooy & S On-line MgtOp215-Business Statistics: Summer2021 4 | 30f 14 (14 complete) w B ® & 8. mathxl.com/Student/PlayerHomework.aspx?homeworkid=596104073&questionld=9&flushed=fals.. & ¢ HW Score: 100%, 136 of 136 P Question Help w ‘ a. Compute the expected number of arrivals per minute. 1= 2595 (Type an integer or decimal rounded to three decimal places as needed.) b. Compute the standard deviation. o= 1.789 (Type an integer or decimal rounded to three decimal places as needed.) c. What is the probability that there will be fewer than 2 arrivals in a given minute? P(x<2)=0.325 (Type an integer or decimal rounded to three decimal places as needed.) %@ “V‘Q@‘ [ ,_ @ YouareTryina x | [ Solved: You A x | + @ Do Homework x ZheZhang& | © | 05/29/2111:56 AM Homework: Week 3: Unit 5 Score: 10 of 10 pts &) 51.7-T below. a. Compute the expected return for stock X and for stock Y. The expected return for stock X is 87 . (Type an integer or a decimal. Do not round.) The expected return for stock Y is 109 . (Type an integer or a decimal. Do not round.) b. Compute the standard deviation for stock X and for stock Y. The standard deviation for stock X is 86.38 . (Round to two decimal places as needed.) The standard deviation for stock Y is 1114.23 . (Round to two decimal places as needed.) . Would you invest in stock X or stock Y? Explain. Choose the correct answer below. Question is complete. All parts showing (IS 4 | 40f14 (14 complete) w D You are trying to develnp a strategy for investing in two different stocks. The anticipated annual return fora $1,000 investment in each stock under four different economic conditions has the probability distribution shown to the right. Complete parts (a) through (c) HW Score: 100%, 136 of 136 pts. Question Help w 'fl Retuns o Economic ProbabilityCondition Stock X Stock Y 0.1 Recession =120 -190 0.2 Slow growth 20 40 04 Moderate growth 110 150 03 Fast growth 170 200 Based on the expected value, stock X should be chosen. However, stock X has a larger standard deviation, resulting in a higher risk, which should be taken into consideration. ¥ . Based on the expected value, stock Y should be chosen. However, stock Y has a larger standard deviation, resulting in a higher risk, which should be taken into consideration. ® EERGIFERED T [ TELE P R I