Copy of - 4A3 Problems 1D Collis - 9837146.3 Practice It _ Problems - Collisions

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4A.3 Practice It | Problems - Collisions ` Learning Target : Use mathematical representations to support the claim that the total momentum of a system of objects is conserved when there is no net force on the system (HS-PS2-2). Elastic Collision (Conservation of Momentum) Problems Success Criteria: 4A.3a I can explain how momentum is conserved in both elastic and inelastic collisions using calculations to support my explanation. 1. Jeanne rolls a 7.0 kg bowling ball down the alley for the league championship. One pin is still standing, and Jeanne hits it head-on with a velocity of 9.0 m/s. The 2.0-kg pin acquires a forward velocity of 14.0 m/s. What is the new velocity of the bowling ball? (5 m/s) 7 kg * 9m/s = 63 kgm/s - 2kg*14m/s = 35 kgm/s/ 7 kg = 5 m/s 2. Running at 2.0 m/s, Bruce, the 45.0 kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision, Biff continues to travel forward at 1.0 m/s. How fast is Bruce knocked backwards? (-10 m/s) (90 kg * 7 m/s - 45 kg * 2 m/s - 90 kg * 1 m/s) / 45 kg = 10 m/s 3. Mason throws his 0.20 kg football in the living room and knocks over his mother’s 0.80 kg antique vase. After the collision, the football bounces straight back with a speed of 3.9 m/s, while the vase is moving at 2.6 m/s in the opposite direction. How fast did Mason throw the football? (6.5 m/s) (2.6 m/s * 0.8 kg - 3.9 m/s * 0.2 kg) / 0.2 kg = 6.5 m/s 4. Two billiard balls of equal mass undergo a perfectly elastic head-on collision. If the speed of one ball was initially 2 m/s, and the other was 3 m/s in the opposite direction, what will be their speeds after the collision if the billiard ball that was moving 2m/s bounces back with a speed of 3m/s? (+2 m/s; -3 m/s) (2 m/s * x kg + 3 m/s * x kg - 3 m/s * x kg)/x kg = 2 m/s 5. A 0.05 kg tennis ball travels at a velocity of 15 m/s, hits a basketball with a mass of 0.60 kg that is stationary on a frictionless surface and then rebounds back in the opposite direction with a velocity of -6.0 m/s. How fast will the basketball be moving after the collision? (1.75 m/s) (0.05 kg * 15 m/s + 0.05 kg * 6 m/s)/0.6 kg = 1.75 m/s

4A.3 Practice It | Problems - Collisions Inelastic Collision (Conservation of Momentum) Problems Success Criteria: 4A.3a I can explain how momentum is conserved in both elastic and inelastic collisions using calculations to support my explanation. 1. Suppose that you have a mass of 45.7 kg and are standing on frictionless roller skates. Someone then throws you a 2.50 kg mass with a velocity of 14.5 m/s and you catch it. What will be your resultant velocity? (0.75 m/s) 2.5 kg * 14.5 m/s = 36.25 kgm/s 36.25 kgm/s = (45.7 kg + 2.5 kg) * x m/s x = 0.75 m/s 2. Darcy who has a mass of 65 kg is ice skating and traveling at 4 m/s to the north. Traveling in the opposite direction of Adele, Darcy suddenly grabs the hand of Adele, who has a mass of 56 kg and is traveling at 12 m/s. While holding hands, the two girls continue skating together with joined hands. What is the final velocity of the two skaters? (-3.4 m/s) (56 kg * 12 m/s - 65 kg * 4 m/s) / 121 kg = 3.4 m/s south 3. During practice, a student kicks a 0.40 kg soccer ball with a velocity of 8.5 m/s to the south into a 0.15 kg bucket lying on its side. The bucket travels with the ball after the collision. What is the final velocity of the objects? (-6.2 m/s) (0.4 kg * 8.5 m/s) / 0.55 kg = 6.18 m/s south 4. In an American football game, a 90.0-kg fullback running east with a speed of 5.00 m/s is tackled by a 95.0-kg opponent running west with a speed of 3.00 m/s. a. Explain why the successful tackle constitutes a perfectly inelastic collision. A successful tackle is perfectly inelastic because the objective of a tackle is to stop motion, which is the same as getting rid of all KE. b. Calculate the velocity of the players immediately after the tackle. (0.89 m/s) (90 kg * 5 m/s - 95 kg * 3 m/s) / 185 kg = 0.89 m/s c. Think back to Unit 3-Energy and Work: Determine the mechanical energy that is lost by the football players as a result of the collision. Account for the missing energy. (1479 J) 0.5 * (90 * 5 2 + 95 * 3 2 - 185 * 0.89 2 ) = 1479 J Tackling is an inelastic collision, so kinetic energy is not conserved. This energy could be lost due to kinetic energy being converted into different forms of energy, such as sound, thermal, and internal energy

4A.3 Practice It | Problems - Collisions

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