PHYS 125L Simulation Lab # S2

3 Σ τ cw = 1*5*9.8=49 Nm Σ τ ccw =1*10*9.8*.5=49 Nm Σ τ = Σ τ cw + Σ τ ccw = -49+98=0Nm Case 2. 5 kg & 10 kg on right of the pivot, 15 kg on left of the pivot Σ τ cw = (5*1+10*.5)*9.8 = 147 Nm Σ τ ccw =1*15*9.8= 147 Nm Σ τ = Σ τ cw + Σ τ ccw = -147 + 147 = 0 Nm Case 3. 5 kg & 20 kg on right of the pivot, 10 kg & 15 kg on left of the pivot Σ τ cw = (5*2+1*20)*9.8 = 294 Nm Σ τ ccw = (1.5*10+1*15)*9.8 = 294 Nm Σ τ = Σ τ cw + Σ τ ccw = -294 + 294 = 0 Nm Case 4. 5 kg, 10 kg & 15 kg on right of the pivot, 20 kg on left of the pivot Σ τ cw = (15*2+5*1+10*.5)*9.8= -392 Nm Σ τ ccw = 2*20*9.8 = 392 Nm Σ τ = Σ τ cw + Σ τ ccw = -392 +392 =0 Case 5. 5 kg , 15 kg & 20 kg on right of the pivot, 10 & 15 kg on left of the pivot Σ τ cw = (15*2+5*1+20*.25)*9.8 = -392 Nm Σ τ ccw = (15*2+10*1)*9.8 = 392 Nm Σ τ = Σ τ cw + Σ τ ccw = -392+392 = 0 PART 2: Finding unknown masses Choose “Balance Lab” tab. Select the following options in right corner of the screen: Mass Labels, Level, Rulers In the “Bricks” section on the right of the screen, click on the right arrow. Keep on clicking to the right until you see “Mystery Objects”.

6 Mystery Object “G” Screenshot of balanced seesaw: Calculations: Mystery Object “H” Screenshot of balanced seesaw:

9 your reasoning clearly.