Lab 4. Free Fall Motion (1) (2)

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Dec 6, 2023

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Physics 201 (General Physics-1) LAB #4 Free Fall Motion Your name: Olivia Beall Student ID: 7966485 Date: 6/16/2022 Lab partners name: Lab Instructor’s name: _____ Aiden Pereira ________ Prof. Stephen Kamanda _____ Mohammad Nawal ________ SAMPLE Formal Laboratory Report Objectives: The objective of this experiment was to determine the gravitational force that was acting upon a picket fence in free fall. However, when an object is in free-fall near the surface of the Earth, the gravitational force on it is nearly constant. Therefore, an object in free fall accelerates downward at a constant rate. Theory: About 300 years ago it was discovered that objects in free fall motion descend at the same rate, independent of their mass, as long as the effects of air resistance can be neglected. Meaning that under free fall all objects have the same constant acceleration, which in the metric system is 9.8 m/s^2 at sea level, directed towards the center of the Earth. Materials and Methods: A Photogate was placed on a ring stand so that the arms extend horizontally so the picket fence could be dropped through the sensor, and the velocity could be measured. The photogate was connected to a DIG port of the Vernier computer interface, which displayed a velocity vs. time graph. For each trial, the picket fence was held to the same height and dropped, with no sort of downward force. The slope of the graph would then be analyzed to find the acceleration. Data Tables
1. Compare your measurement to the generally accepted value of g (it is 9.8 m/s 2 ). Does the accepted value fall within the range of your values? If so, your experiment agrees with the accepted value. a. The accepted value falls within the range of experimental values which is 8.48 to 11. **Show your calculations below (% uncertainty, Ave, etc) Average g= (9.7399+9.7452+9.8218+9.8565+9.6052+9.6863)/6=9.74248 % uncertainty= (9.8565-9.6052)/2= 0.126 (0.126/9.74) * 100= 1.29% Post analyses Questions: 1. Describe in words the shape of the position vs . time graph for the free fall. a. The position vs. time graph is a downward curved line. It starts slow and then as time increases it becomes steeper, finishing with a larger downward velocity since the motion is accelerated. 1. Describe in words the shape of the velocity vs. time graph. How is this related to the shape of the position vs . time graph?
a. The velocity vs. time graph followed a positive, linear relationship. As the time increased, so did the velocity. This is related to the position vs. time graph, because as the position changes over time the velocity increases. 1. Inspect your velocity graph. How would the associated acceleration vs . time graph look? Sketch your prediction on paper. Now change the upper graph to acceleration vs. time. To do this, click the y-axis label and select Acceleration. Comment on any differences . You may want to rescale the graphs so that the acceleration axis begins at zero. a. I originally sketched the acceleration vs. time graph to look like a horizontal straight line, since acceleration on the object is constant over time. This prediction was confirmed after running the experiment again after changing the y-axis to acceleration, and the graph displayed a horizontal straight line at about 9.8 m/s^2, the accepted value of acceleration of an object in free fall. 1. Use the Statistics tool and the acceleration graph to find the average acceleration. How does this compare with the acceleration value for the same drop, determined from the slope of the velocity graph? a. An average acceleration of 9.68 was obtained, which corresponds to the acceleration obtained on the velocity vs. time graph. In fact, it is the same value as the 6th trial in our experiment. 1. Use the position vs . time graph and a parabolic fit to determine g. How close is this value of g to the one calculated g Ave ? a. When the parabolic fit was applied an equation of 4.8466x^2+1.4153x+-1.5874*10^-5, was obtained. i. f’(x)= (96932x+14153)/10000 ii. f’’(x)= 24233/2500= 9.69 b. When taking the second derivative of this equation we derived an acceleration of 9.69m/s^2, which is very similar to the values obtained in the experiment. 1. Would dropping the Picket Fence from higher above the Photogate change any of the parameters you measured? Try it. a. No, no matter where the fence was dropped from the acceleration remains constant on the object at around 9.8 m/s^2. Results and Discussion: It was found after conducting six trials that the average acceleration of the picket fence was about 9.74248 m/s^2, which is supported by the accepted value of acceleration which is 9.8 m/s^2. There was a 1.29% uncertainty, and the accepted value of acceleration (9.8 m/s^2) fell within the range of experimental values which was 8.48 to 11. Conclusions: It was determined that acceleration on an object in free fall is constant at about 9.8 m/s^2, and does not depend on the height at which the object was dropped.
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