Electric Field Lab

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University of Nebraska, Omaha *

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1054

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Physics

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Dec 6, 2023

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Electric Field Lab Go to the following site: https://phet.colorado.edu/sims/html/charges-and-fields/latest/charges-and-fields_en.html 1.) Place one charge in the middle of the screen as shown below. 2.) Use physics to determine the electric field at a distance of 1 m from the charge. E= kq/r 2  r= 1m (9x10 9 N*m 2 /C 2 ) (1x10 -9 C)/ (1m) 2 = 9N/c  9 V/m 3.) Check the following settings. 4.) Use sensors to measure the electric field at a distance of 1 m away. How close did you come? (Remember, 1 N/C is equivalent to V/m) I came pretty close the actual number was 7 V/M. A.) Use proportional reasoning to determine the electric field at a distance of 2 m from the charge. Measure to see how close you came. E= kq/r2  r= 2m

(9x10 9 N*m 2 /C 2 ) (1x10 -9 C)/ (2m) 2 = 2.25 V/m  4.5 V B.) Use proportional reasoning to determine the electric field at a distance of 3 m from the charge. Measure to see how close you came. Proportional reasoning: 14 v/m I thought it was going to double but that’s not the case because they aren’t proportional like that. 4.) Put one charge in the middle of the screen as shown below. Use the following settings: A.) Describe the direction of the electric field. The direction of the field is everything is pointing away from the positive nC. B.) How do the arrows show the magnitude of the electric field? Explain. The arrows point in the direction of the electric field and their length is proportional to the strength of its location. 5.) Use the following settings:

A.) Place 3 charges as shown below: Predict the magnitude (size of the arrow) and direction of the electric field at the location of the yellow dot. The arrow is going to be smaller and maybe pointing away from all the charges. Use the sensor button to measure the electric field at this point and compare it to your results. We are only interested the size and direction of the arrow rather than the actual value. While I didn’t predict the number I did predict the direction and that the value was going to be smaller and I got the correct location for the vector. 6.) Place the following three charges on the screen as shown below:

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A.) Use physics to find the magnitude (actual value) of the electric field at the location of the yellow dot. E= kq/r 2  r= 1m (9x10 9 N*m 2 /C 2 ) (1x10 -9 C)/ (1m) 2 = 9 V/m (9x10 9 N*m 2 /C 2 ) (-1x10 -9 C)/ (1m) 2 = 9 V/m (9x10 9 N*m 2 /C 2 ) (1x10 -9 C)/ (2m) 2 = 2.25 V/m Adding it all together: 15.75 B.) Set the following. C.) Use the sensors to measure the electric field at the location of the yellow dot. How close did you come? The actual value looks like its around 16.5 V/m. I predicted around this area with a guess of 15.75. D.) Check the Electric Field Box under settings. E.) Give a few observations of the direction of the electric field. Check a few of the arrows for accuracy. Were they correct? The positive charges caused the

arrows to face away while the negative charges caused the arrows to attract towards them. F.) Move around the sensors button to find out where the electric field is strongest. Explain conceptually why this is the strongest location. They are the strongest when they are nearest at the charges at a 90 degrees. It is the strongest because it based on how the charged object

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