The Scientific Method, Measurements and the Art of Discovery (1)

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2053L

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Physics

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Feb 20, 2024

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General Physics I Laboratory (PHY2053L) The Scientific Method, Measurements, and the Art of Discovery Name: _ Date: ______________________________________________________________________________ Introduction Vernier Caliper In this laboratory, we will use different tools to measure physical quantities. One of these tools is the Vernier Caliper, which has a precision of 0.1mm. The Vernier caliper can be used to measure the inner diameter, outer diameter or length of an object. The following figures show how to read a Vernier Caliper. 0 Vernier scale Main scale 1) Take the reading on the left of this mark: 41mm 3) Add both readings: 41mm + 0.3 mm = 41.3 mm 2) Count the number of divisions on the Vernier scale until you get to the division that lines up with the main scale and multiply by 0.1mm: 3 × 0.1 mm = 0.3 mm
Volumetric Density The density, of a substance ( ρ is the lowercase Greek letter rho) is defined as its mass per unit volume: ρ = m V Where m is the mass of a sample of the substance and V is the volume. The SI unit for density is kg/m 3 . The following table show the density for different substance. Material Density ( kg / m 3 ) Air 1.00 Alcohol 0.79 × 10 3 Water 1.00 × 10 3 Mercury 13.60 × 10 3 Concrete 2.30 × 10 3 Aluminum 2.70 × 10 3 Zinc 7.00 × 10 3 Iron and Steel 7.80 × 10 3 Brass 8.30 × 10 3 Copper 8.90 × 10 3 Lead 11.30 × 10 3 Materials: Black box, probe, meter stick, cylindrical object, digital scale, Vernier caliper, drafting compass and graph paper. Method Part I: Density 1. List the precisions of your measurement tools. (5 points) _Vernier Caliper (0.1mm), Ruler/meter stick (1cm & 1in), Digital scale (0.1g). _________________________________________________________________________ ______________________________________________________________________________ 2. Use the digital scale to measure the mass and the Vernier caliper to measure the dimensions (diameter and height) of the cylindrical object. Record your results in table 1. 2
** Keep in mind that this object is not ideal, therefore diameter and height might vary. Try to pick different sides to measure the diameter and height. Part II: Black Box 1. Probe the black box by measuring the perpendicular distance from the top of the black box to its bottom over each hole in top of the box. Record the distances in table 2. 2. Determine the thickness of the walls and the texture of the inside of the black box. Record your results in table 3. 3. Determine the number of objects in the black box. Record your results in table 3. 4. Determine the object's composition and shape in the box. Record your results in table 3. 5. Measure the length, width, and height of the black box. Record your results in table 4. 6. Calculate the black box diagonal and record your answer in table 4. Remember that this is a 3-dimensional object. 7. Find ten (10) other measurements and/or observations (not listed in steps 1-6) to identify what is inside the box. List them below: (5 points) 1) ____Metallic_____________________ 2) _Light weight________________ 3) _ Small in size___________________ 4) ___Bouncy__________________ 5) __Sounds like a coiled wire__________ 6) __About 3.8 cm in width_______ 7) __Thin/Skinny_________________ 8) __About 2 cm in height____________ 9) __Spring like sound______________ 10) _Circular______________________ Part III: Measuring π graphically 1. Draw two concentric circles of different radii using the drafting compass on the graph paper (Graph 1). Note that concentric circles are circles with a common center. 2. Measure the area of the circle and its diameter by counting the number of squares in the circle and diameter. Results (40 points) Place your data in this section Table 1 3
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Measurement Diameter (m) Height (m) mass (kg) Volume (m 3 ) Density (kg/m 3 ) 1 0.183 m 0.352 m 0.08647 9.26 x 10 -6 9.338 x 10 3 2 0.183 m 0.353 m 0.08646 9.28 x 10 -6 9.317 x 10 3 3 0.183 m 0.353 m 0.08647 9.26 x 10 -6 9.338 x 10 3 4 0.183 m 0.352 m 0.08646 9.28 x 10 -6 9.317 x 10 3 5 0.183m 0.352 m 0.08646 9.28 x 10 -6 9.317 x 10 3 6 0.183 m 0.352 m 0.08646 9.28 x 10 -6 9.317 x 10 3 7 0.183 m 0.352 m 0.08647 9.26 x 10 -6 9.338 x 10 3 8 0.183 m 0.352 m 0.08647 9.26 x 10 -6 9.338 x 10 3 9 0.183 m 0.353 m 0.08646 9.28 x 10 -6 9.317 x 10 3 10 0.183 m 0.352 m 0.08646 9.28 x 10 -6 9.317 x 10 3 Average 0.183 0.3523 0.08646 9.27 x 10 -6 9.325 Table 2 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 9 10 10 1 0 10 10 10 10 10 10 10 10 10 9.7 9.8 9. 8 9.9 10 10 1 0 10 10 10 10 10 10 10 10 9.5 9.9 9.5 9. 7 9.6 10 10 1 0 10 10 10 10 10 10 10 10 9.5 9.7 9.7 9. 8 9.8 10 10 1 0 10 10 10 10 10 10 10 10 9.4 9.9 9.7 9. 8 9.8 10 10 1 0 10 10 10 10 10 10 10 10 9.9 9.6 9.9 9. 9 9.7 10 10 4
1 0 10 10 10 10 10 10 10 10 9.8 9.7 9.9 9. 6 9.8 10 10 1 0 10 10 10 10 10 10 10 10 9.8 10 10 10 9.9 10 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 9.7 9 10 1 0 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 Table 3 Black box Wall thickness = 0 m (m) Object texture: Metallic Number of objects: 1 Objects composition: Metal Objects shape: Springy or Bouncy Table 4 Measurement Length (m) Width (m) Height (m) Volume (m 3 ) Diagonal (m) Black Box 0.1 m 0.1 m 0.1 m 0.001 m 3 0.1 m 5
<<<<(Graph 1) Data Analysis (35 points) Part I: Density 1. Calculate the volumetric density and its average value for the cylindrical object (table 1). Identify the material of the cylindrical object. Include a sample of your calculations below. (5 points) Volumetric density = m V V = 0.08647/ 9.26 x 10 -6 = 9.338 x 10 3 V = 0.08646/9.28 x 10 -6 = 9.317 x 10 3 6
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Average value = 9.26 x 10 -6 +9.26 x 10 -6 +9.26 x 10 -6 + 9.26 x 10 -6 + 9.28 x 10 -6 +9.28 x 10 -6 +9.28 x 10 -6 +9.28 x 10 -6 +9.28 x 10 -6 + 9.28 x 10 -6 / 10 A = 9.27 x 10 -5 The material for the cylindrical object seems to be copper, since it is the closest in Density (kg/m 3 ). 2. Calculate the standard deviation of the mean ( σ = i = 1 N ( x i x ) 2 N ( N 1 ) ) for the density. Include a sample of your calculations below. (5 points) Mean= 9.325 σ = (9.338 – 9.325) 2 +(9.338 – 9.325) 2 +(9.338 – 9.325) 2 +(9.338 – 9.325) 2 +(9.317-9.325) 2 + (9.317-9.325) 2 +(9.317-9.325) 2 + (9.317-9.325) 2 +( 9.317-9.325) 2 + (9.317-9.325) 2 = (0.000169)+ (0.000169)+ (0.000169)+ (0.000169)+(0.000064)+ (0.000064)+ (0.000064)+ (0.000064)+ (0.000064)+ (0.000064) = √0.00106/10-1 = √0.00106/9 σ = 0.01085 Part II: Black Box 7
3. Draw the object(s) contained in the black box using the distance measurements from table 2- 4, and other information from the Method section. (5 points) 4. What is the shape of the object(s) inside the black box and its dimensions? (5 points) -The shape of the object inside the black box is round with parts of the coming out like springs. The shape is quite odd and not definite. The dimensions are 3.5cm in Width x 3.6 in Length, and 4.6 cm in Height. 5. Calculate the diagonal of the black box? Show your calculations in detail and write the average value of the diagonal. (5 points) Hint: not a square diagonal! √Length 2 + Width 2 + Height 2 The box dimensions 10Wx10Lx10H √10 2 +10 2 +10 2 = 17.321 Part III: Measuring π graphically 6. Using your area and diameter measurements for both circles (in terms of number of squares), determine the experimental value of π E using the following formula: π E = 4 A D 2 . Include a sample of your calculations for each circle. (5 points) Circle 1 (inner circle): diameter =11.5, area =103 π E = 4 A D 2 = 4(103)/11.5 2 =412/132.25 = 3.1153 8
Circle 2 (outer circle): diameter=14.5, area =62 π E = 4 A D 2 = 4(63)/14.5 2 =252/210.25 =1.1985 7. Knowing that the true value of π T is 3.14159265, calculate the percent error in π for both circles. Use the following equation: percent error % = | π T π E | π T × 100% . Include a sample of your calculations for each circle. (5 points) Inner circle 1: % error = | 3.14 3.12 | 3.14 × 100% = 0.02/3.14 x 100 =0.637 Outer circle 2: % error = | 3.14 1.19 | 3.14 × 100% = 1.95/3.14 x 100 =62.102 Conclusion (15 points) State the main conclusion(s) in the first paragraph along with a discussion of your results. _ Overall, the tasks completed included measuring the cylindrical object, probing the black box, and drawing two concentric circles. The cylindrical object was not completely perfect in shape therefore, causing many measurements to be looked at. The diameter, height, mass, volume, and density were measured. Thus, concluding the object was copper due to the density being as close to the density of copper. In the second task there was a black box with a distinct object inside. By measuring all sides of the box and paying close attention to the object inside while probing the box. To not complicate the measurement, the object was kept on the side of the box. Furthermore, the objects size was determined to be 3.5x3.6x4.6cm respectively. Finally, there was the concentric circles drawn with a protractor. The are and diameter of the two circles were 9
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gathered by counting the number of squares within each circle and counting the squares across. Thus, concluding the experimental value to be 3.12 and 1.19 for each circle. When calculating the percent error, the values came out as 0.637 and 62.102. The results for all tasks completed seemed to be manipulated possibly by the materials used. Although, it could have also been the calculation part of the tasks. __________ ______________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ In the second paragraph, you must show once how your measuring tools produce a quantified experimental error and discuss its implications for your results. The measuring tools used for the different task were a vernier caliper, protractor, ruler, and a measuring scale. When measuring the cylindrical object, the actual objects size differed throughout since it was old and used before multiple times. The vernier caliper measured the object precisely but the scale used could have had incorrect measurements when the object was placed on the scale. When measuring each hole in the black box there were difficulties in measurement when placing the stick in between each hole. As well as the measurements done to try and find the size of the object made it hard because we were only using cm to measure each hole. Which could have caused an improper measurement conclusion about the object in the box. Lastly for the drawing of the concentric circles the protractor was difficult to use when attempting to draw precise circles. Although, the center for each circle was the same, the protractor created not very uniformed circles which could have messed with calculation when trying to find area and diameter. ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ In the third paragraph, you may discuss any other experimental errors qualitatively that may have influenced your results. The other kinds of experimental errors that I came across were calculations when trying to find the diagonal of the box and the dimensions of the object inside the box. I believe I did them right but there was slight hesitation if they were performed correctly. Another one I came across was calculating the standard deviation of the cylindrical object density. The average value from table 10
1 was used in my calculations but I believe the calculations may have or not been written correctly. For the most part the procedures were done smoothly and as precise as possible. _______________________________________________________________________ _______ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ ______________________________________________________________________________ _____________________________________________________________________________ 11