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Roger Williams University *

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Physics

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Feb 20, 2024

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Newton's Laws Lab Name: Data Collection—Table 1: Trial Force used (N) Time (s) Distance (m) (fixed) Acceleration (m/s 2 ) Mass (kg) 1 50 N 9.64 5.0 0.11 454.55 2 100 N 6.76 5.0 0.22 454.55 3 150 N 5.53 5.0 0.32 468.75 Analysis 1. Using the equation d = 1 2 at 2 , the value of 5.0 m for the distance, and the time that you recorded for wagon to reach the stop block, calculate the acceleration for each trial.Show your work. Fill in Table 1 with your answers. A=(2)d/t^2 10/9.64^2=0.11 m/s 2 10/6.76^2=0.22 m/s 2 10/5.53^2=0.32 m/s 2 2. Using Newton's second law of motion, calculate the mass of the cart for each trial. Show your work. Fill in Table 1 with your answers. m=f/a 50/0.11=454.55 kg 100/0.22=454.55 kg 150/0.32=468.75 kg Questions Answer questions in complete sentences. 1. Compare the accelerations for the three trials. Explain how Newton's second law was demonstrated in the simulation? For larger applied forces, the acceleration was larger. Newton’s second law was shows that the mass*acceleration = force. I used m=F/a to calculate based off of the given values. 2. Describe how Newton's first and third laws would apply to this situation if this simulation was done in the real world. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
The object (the cart) was initially at rest, but by applying a force (the person pulling on the rope) it was set into motion. If this simulation was done in the real world we’d have to take into account the opposing force of friction. 3. Compare the masses that you calculated for the three trials. If the actual mass of the cart did not change (same cart for all trials), what measurement do you believe contributed the largest amount of error to that calculation? Explain your answer. The first two calculations resulted in the same mass (454.55 kg), which makes sense because the cart was the same for all trials. The last measurement was what largely contributed to the error. There was the most force being applied, so the time was shorter and it was more difficult to simultaneously and accurately press the stopwatch and the “Go” button. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
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