Lab #2 Report

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University Of Arizona *

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Course

447

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Mechanical Engineering

Date

Jan 9, 2024

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pdf

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6

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Report
McKenna Nichols BME 447 Loeffler 13 September 2023 Chapter 3 Lab Report: Diodes and Transistors Results Task 1: LED Resistance of 0. 1 ?Ω 0. 099 ?Ω Measured 𝑉 ? Measured 𝑉 ? Calculated 𝑉 ?? ( ) 𝑉 ? − 𝑉 ? Calculated 𝐼 ??? ( ) 𝑉 ? 0.099 0 0 0 0 0.2 0 0.2 0 0.46 0 0.46 0 0.76 0 0.76 0 0.98 0 0.98 0 1.25 0 1.25 0 1.5 0 1.5 0 1.78 0.02 1.76 0.0002 1.89 0.09 1.8 0.0009 2.07 0.28 1.79 0.0028
Task 2: Zener Diode Resistance of 0. 1 ?Ω 0. 99 ?Ω Measured 𝑉 ? Measured 𝑉 ? Calculated 𝑉 ?? ( ) 𝑉 ? − 𝑉 ? Calculated 𝐼 𝑧𝑒𝑛𝑒𝑟 ( ) 𝑉 ? 100 0 0 0 0 0.12 0 -0.12 0 0.2 0 -0.2 0 0.47 0 -0.47 0 0.76 0 -0.76 0 1.0 0 -1.0 0 1.26 0 -1.26 0 2.5 0.02 -2.52 -0.00002 2.7 0.04 -2.74 -0.00004 2.9 0.08 -2.98 -0.00008 3.12 0.15 -3.27 -0.00015
3.24 0.22 -3.46 -0.00022 3.4 0.34 -3.74 -0.00034 3.5 0.44 -3.94 -0.00044 3.62 0.58 -4.2 -0.00058 3.77 0.87 -4.64 -0.00087 3.92 1.27 -5.19 -0.00127 4.02 1.59 -5.61 -0.00159 4.11 1.94 -6.05 -0.00194 Discussion Throughout this lab, we completed various tasks that would allow us to gain a better understanding of transistors and diodes. For the first portion of this lab, we began by setting up the circuit that we would be using. The picture to the right shows this circuit. To
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begin we measured the the resistance of out 0.1 resistor in order to get a more accurate value. ?Ω From here we utilized the potentiometer to vary the output voltages that we were measuring. Everytime the potentiometer was turned, we would measured the value of the voltage applied to the LED, , and the value of the voltage drop across the resistor, . By using the equation 𝑉 ? 𝑉 ? , we were able to find the value of the voltage drop across the LED, . From here we 𝑉 ? − 𝑉 ? 𝑉 ?? are able to use Ohm’s law rearranged for current ( ) to find the current through the LED, 𝐼 = 𝑉 𝑅 . The equation used was . From here we were able to graph the Voltage drop across the 𝐼 ??? 𝑉 ? 99 LED versus the current through the LED. This graph can be seen in the results section under task 1. For the second portion of this lab, we began by setting up the circuit that we would be using. The picture to the right shows the schematic for the circuit used. To begin we measured the resistance of the 1 ?Ω resistor to ensure that the value used in our calculations is as accurate as possible. From here we utilized the potentiometer to vary the output voltages that we were measuring. Everytime the potentiometer was turned, we would measured the value of the voltage applied to the zener diode, , and the 𝑉 ? value of the voltage drop across the resistor, . By using the equation , we were able to 𝑉 ? 𝑉 ? − 𝑉 ? find the value of the voltage drop across the zener diode, . From here we are able to use 𝑉 ?? Ohm’s law rearranged for current ( ) to find the current through the zener diode, . The 𝐼 = 𝑉 𝑅 𝐼 𝑧𝑒𝑟𝑒𝑟
equation used was . From here we were able to graph the Voltage drop across the zener diode 𝑉 ? 990 versus the current through the zener diode. This graph can be seen in the results section under task 2. Review Questions 3.1 Calculate , , , , for the following transistor circuit (Fig. 3.13). The current gain is 𝑉 ? 𝑉 ? 𝐼 ? 𝐼 ? 𝐼 ? β 100. is 0.67 V, and is nearly constant for this transistor for a range of input voltage and 𝑉 ?? current. 𝑉 ?? = 𝑉 ? − 𝑉 ? 𝑉 ? = 𝑉 ? − 𝑉 ?? = 5. 67 𝑉 0. 67 𝑉 = 5 𝑉 𝐼 ? = (𝑉 ? −0𝑉) 𝑅 ? = (5 3300 = 5 3300 = 0. 0015 ? 𝐼 ? = 𝐼 ? (1 + β) 𝐼 ? = 𝐼 ? (1+β) = 0.0015 (1+100) = 0. 000015 ? 𝐼 ? ≈ 𝐼 ? = 0. 0015 ? 𝐼 ? = 0. 0015 ? 𝐼 ? = (20𝑉−𝑉 ? ) 𝑅 ? = (20𝑉−𝑉 ? ) 4700 𝑉 ? = 20𝑉 − (4700 * 𝐼 ? ) = 20𝑉 − (4700 * 0. 0015) = 12. 95𝑉 = 13𝑉 Answers: 𝑉 ? = 13 𝑉 𝑉 ? = 5 𝑉 𝐼 ? = 0. 0015 ? 𝐼 ? = 0. 0015 ? 𝐼 ? = 0. 000015 ?
3.2 Draw the I-V curve for an LED if it is connected in a reverse bias. 3.3 Plot (y-axis) against (x-axis) for the above data in the first quadrant. Did you − 𝑉 𝑧𝑒𝑛𝑒𝑟 − 𝐼 𝑧𝑒𝑛𝑒𝑟 notice the voltage is almost constant for a certain window of current?
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