Fluids Lab Report_ The Force of a Jet.docx
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Lab 2: The Force of a Jet
I pledge my honor that I have abided by the Stevens Honor System.
Introduction:
The objective of this experiment was to understand the fluid forces on solid objects that
deflect the momentum of an impinging jet. This was accomplished by theoretically and
experimentally calculating the force of a circular fluid jet as it acted on several differently shaped
deflecting surfaces. The forces were calculated by comparing physical data and theoretical
models derived from Linear Momentum Equations, Newton’s 2nd Law, and Reynolds Transport
Theorem. The experiment utilized a Controllable Flow Apparatus to shoot a stream of water with
varying pressure at a flat plate at 30, 45, 60, and 90 degrees, a cone at 45 and 60 degrees, and a
bucket at 160 and 90 degrees (Shown below in Figure 1). The controllable flow apparatus has a
flow control valve, pressure gage, and a digital flow meter which aids in conducting and
performing the needed calculations. Water flow pressures of 0, 30, 40, and 50 psi were used to
find the volumetric flow rate and force both theoretically and experimentally. The experiment
took place in a water bucket with a cover to prevent any water from spilling out during testing as
well as to provide a controlled environment. A force balance was connected to the test base to
calculate the force of the jet. These recorded values, although not 100% accurate to theoretical
models, are a close representation and provide physical evidence to theories learned in Fluid
Mechanics. The hypothesis that this lab intends to prove is that force increases as larger vertical
angles are introduced to an impinging jet of water, hence, it is expected to see the 160° pelton
bucket to have the largest momentum transfer out of all the test specimens.
Theory:
In order to predict the behaviors produced by the fluid within these experiments -
Newton’s 2nd Law, the Linear Momentum equations, and Reynolds transport theorem must be
used to derive equations that are capable of determining the expected forces experienced by the
various plates. Therefore the following is a comprehensive derivation that expresses the
theoretical forces for each plate used in the laboratory.
Figure 1: Plate, Bucket, and Cone Flow Diagrams
The significant equation behind all of these relationships is the linear momentum equation:
This equation can be manipulated to determine other equations that will help represent the
correlations between multiple variables of each solid surface at various angles. To simplify this
equation, the time derivative on the right side can be eliminated because the control volume does
not change with time. Another way to simplify the equation is to remove the F(B) term because
no body forces were present in this lab. The weight of the water in the stream was negligible, and
the weight of the deflecting surface was ignored because the scale was reset to zero after the
plate was placed on the stand. Now that the equation can be simplified, it is much easier to derive
equations to demonstrate relationships between variables.
As seen above in figure 1, the first schematic shows a flat plate inclined at some value
𝜃
and has an inlet volume flow of
𝑸
. When the inlet flow splits into two streams, each stream has
the same velocity but unequal volume flows,
𝛂𝑄
and (1-
𝛂
)
𝑄
where
𝛂
∈
[0,1], due to the fact
that for frictionless flow, the fluid can exert no tangential force Ft on the plate. A relationship
between
𝜃
and
𝛂
can be derived as follows:
→
There are no body forces.
𝐹
??
= 0 →
There are no surface forces acting in the x-direction because the flow is frictionless
𝐹
𝑆?
= 0
→
, The volume does not change over time
→
?
1
=
𝑉???θ →
?
2
= ?
3
= 𝑉
→ Divide both sides by
ρ𝑄
− 𝑉???θ − 𝑉(1 − α) + 𝑉α = 0
→ Divide both sides by
𝑉
− ???θ − (1 − α) + α = 0 ⇒ − ???θ − 1 + 2α = 0
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⇒ α = (1 + ???θ)/2
(2)
The linear momentum equation can also be used to derive an equation to formulate the
magnitude of the vertical force Fy to hold the flat plate in place as a function of incoming
volume flow rate
𝑄
, fluid density ρ, get area A, and inclination angle
.
θ
After the data was obtained, the applied force was plotted on a graph as a function of the square
of the mass flow rate. A line of best fit was found from the data points and the slope of the line
was found. Next, in order to determine the uncertainty in the force measurements (σ
y
), the
principle of least squares was applied, and the following formula was used:
In this formula, N represents the number of data points, and B represents the slope of the line of
best fit made from data points. Next, the uncertainty in the slope (σ
B
) was calculated using the
following formula:
Materials and Methods:
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In this lab, water is supplied from a tap where it flows through a throttling valve, a digital
flow meter, and a quick acting “ball” valve. The water then discharges through a nozzle that has
a diameter of 2.8mm. The schematic of the set up for the experiment is shown in Figure 2 below.
The flow rate of the water can be adjusted to specified values needed for the experiment by
adjusting the pressure through the pressure control valve.
Figure 2: A Schematic of the Experimental Set Up
The jet sprayed water onto the test specimens, a flat plate, two different buckets, and two
cones, which are shown in Figure 3 below. The specimens sat on the vertical rod, which is
connected to a force balance. The force balance measured the vertical component of the force
acting on the specimens.
Figure 3: Deflecting Surface Specimens (Flat Plate, 2 Cones, and 2 Buckets)
To conduct this experiment, the first specimen, the flat plate, was set on the support rod at
a 90
°
angle. The force balance displayed the weight of the specimen, so the scale was reset to
zero so that it only measured the force of the water acting on the plate. Then, the faucet was
turned on and the gage pressure control valve was adjusted to 20 psig. After waiting 15-30
seconds for the system to stabilize, the volume flow rate from the flow meter and the weight
from the force balance were recorded. The gage pressure was adjusted to 30, 40, and 50 psig and
the same measurements were recorded. These steps were then repeated for the flat plate at 60
°
,
45
°
, 30
°
, and for the two buckets and two cones which is shown in Figure 3 above. The lab setup
was adjusted so that the jet stream was spraying the specimens at the center and observing the
deflection as shown back in Figure 1.
Materials:
●
Protractor
●
Metal Plate (inclination adjustable)
●
Metal 160° Pelton Bucket
●
Metal 90° Pelton Bucket
●
Metal 45° Cone
●
Metal 60° Cone
●
Controllable Flow Apparatus
●
Force Balance
●
Flow Meter
●
Bucket with lid
Results:
The graphs below show the relationship between the force of the jet and the square of the
mass flow in each configuration tested during the experiment. This allows for visual analysis of
the relationship between the experimental and theoretical values to occur. The red line represents
the relationship for a theoretical situation, which was calculated.
Figure 4: Bucket
Figure 5: Cone
Figure 6: Flat Plate
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Discussion:
The purpose of this experiment was to analyze the relationship between the force on the
angle and shape of different surfaces. The first recognized relationship in this experiment was
increased force with an increase in pressure. This increased pressure also caused increased
volume flow rate and mass flow rate. Another trend throughout the experiment was a decrease in
force with a decrease in angle between the surface and the jet stream.
To compare the experimental results to general accepted or theoretical values, the
following methodology was used: The Mass flow rate in gallons per minute and weight of the
water were calculated and the units were then converted to kilograms per second. The theoretical
force calculations were calculated using the individual geometries. The equations are derived and
provided above in the theory section. The experimental results were compared to the theoretical
results using percent error calculations (Refer to Appendix D).
Although the results of the experiment were generally accurate, there were some errors
while conducting the experiment that could explain the discrepancies. While conducting the
experiment, each specimen was supposed to be perfectly centered underneath the jet stream to
produce the most accurate angle and results. Due to human error, not every specimen was
perfectly centered which would partially explain some of the inaccuracies. The jet stream was
assumed to hit the center of the cone, but even though the cone was centered on the force
balance, the stream would not always hit the center of the cone, causing a slight change in angle
of the stream. Furthermore, from a theoretical perspective the tangential force and spray may be
considered uniform, however in reality the steam splashes in every direction. This real life
randomness is another way in which the theoretical models differ from reality. This measurement
error also effects the results due to the splashing affecting the direct reading of the experiment as
it contacts the plate in an unpredictable or quantifiable manner.
In the experiment, it was to be assumed that the jet stream was a uniform flow, which was
not always the case. The jet stream fluctuated slightly due to an uneven pressure valve, due to
either a faucet being turned on, a toilet flushing, among other reasons. These small factors caused
both the volume flow rate and force to fluctuate frequently. The only way to get a reading for
both of these variables was to pick the most consistent number in the set of constantly changing
numbers. It was also slightly difficult to obtain the exact pressure for each trial of the experiment
using the knob on the valve. The only way to address this was to be as precise as possible when
adjusting the gage pressure.
The tests that had the best agreement between theory and reality were the bucket at 90
degrees and the flat plate at 60 degrees. The cone tests and the flat plate at 30 degrees yielded the
worst results.
Conclusion:
The deflecting plate that resulted in the highest applied force was the 160 degree Bucket,
The applied force, and therefore the slope that was calculated for each specimen, increased as the
angle of deflection increased. Since 160 was the largest deflection tested in this experiment, it
saw the highest force applied. This occurs because the force is what allows the jet to change the
direction of its momentum. The larger the change in momentum in the vertical direction, the
larger the vertical force that is needed.
Additionally, the jet impinging on the flat plate requires slightly more force at the same
angles when compared to the cone or the bucket. This is due to the fact that the jet contacting the
flat plate splits and some of the water travels up the plate. This fraction of the jet has a larger
angle of deflection than the rest of the water, which required more force to allow for the larger
change in momentum. For both the cone and the bucket, all water leaving the control volume
experiences the same angle of deflection.
The tests that achieved the smallest percent errors and best agreement between theory and
reality were the bucket at 90 degrees and the flat plate at 60 degrees. The cone tests and the flat
plate at 30 degrees yielded the worst results. The large areas of error could have come from
measurement errors due to water hitting the bottom of the tank and thus affecting the reading of
the scale. Errors such as these could be prevented in the future by reducing the distance from the
nozzle to the objects, this would reduce the expansion of the water as it leaves the nozzle and is
applied to the objects. To reduce the distance between the two simply raise the bucket system or
lower the nozzle system.
Appendix A: Figures
Figure 1:Plate, Bucket, and Cone Flow Diagrams
Figure 2: A Schematic of the Experimental Set Up
Figure 3: Deflecting Surface Specimens (Flat Plate, 2 Cones, and 2 Buckets)
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Figure 4: Bucket
Figure 5: Cone
Figure 6: Flat Plate
Appendix B: Tables
Raw Data Collected:
Bucket 160°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.316
.1750
30
1.582
.2780
40
1.780
.3520
50
1.970
.4380
Bucket 90°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.334
.1330
30
1.506
.1830
40
1.745
.2250
50
1.990
.2912
Cone 45°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.296
.1080
30
1.550
.1515
40
1.799
.2025
50
1.981
.2390
Cone 60°
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Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.280
.0925
30
1.555
.1245
40
1.757
.1545
50
2.000
.1945
Flat Plate 90°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.211
.124
30
1.553
.200
40
1.722
.255
50
1.916
.323
Flat Plate 60°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.246
.1125
30
1.515
.1590
40
1.793
.2190
50
1.960
.2650
Flat Plate 45°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.302
.1065
30
1.521
.1325
40
1.814
.1765
50
1.987
.2095
Flat Plate 30°
Pressure (psig)
Volume Flow Rate
(gal/min)
Force (kg)
20
1.307
.0915
30
1.537
.1145
40
1.751
.1410
50
1.963
.1660
Converted Experimental Data:
Bucket 160°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.006873736464
1.71675
2.167158068
30
0.009933311556
2.72718
3.131783768
40
0.0125753796
3.45312
3.964777454
50
0.0154032921
4.29678
4.856364355
Bucket 90°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.007063057764
1.30473
1.14804077
30
0.009001834884
1.79523
1.463172721
40
0.01208570423
2.20725
1.964429804
50
0.0157176369
2.856672
2.554769983
Cone 45°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.006666395904
1.05948
1.849764084
30
0.0095355225
1.486215
2.645877517
40
0.01284527557
1.986525
3.564254169
50
0.01557578881
2.34459
4.321905739
Cone 60°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.0065028096
0.907425
1.585465698
30
0.009597141225
1.221345
2.339902157
40
0.01225249748
1.515645
2.987310973
50
0.015876
1.908045
3.870765864
Flat Plate 90°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.005820621849
1.21644
0.9460932377
30
0.009572469921
1.962
1.555924658
40
0.0117692122
2.50155
1.912986681
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50
0.01457042126
3.16863
2.368299709
Flat Plate 60°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.006161936004
1.103625
1.040797449
30
0.009109748025
1.55979
1.528408191
40
0.01275973568
2.14839
2.130435026
50
0.0152473104
2.59965
2.540026901
Flat Plate 45°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.006728264676
1.044765
1.151590794
30
0.009182047329
1.299825
1.560182923
40
0.01306037552
1.731465
2.203617614
50
0.01567028276
2.055195
2.635538466
Flat Plate 30°
Pressure (psig)
Mass Flow Rate
(𝑘𝑔/?)
2
Force (N)
Theoretical Force (N)
20
0.006780040281
0.897615
1.173307099
30
0.009376242561
1.123245
1.607839495
40
0.01216895797
1.38321
2.073440998
50
0.01529402156
1.62846
2.592953854
Experimental Slope
Theoretical Slope
Uncertainty
Bucket
y=239.45x-0.1088
y = 242.19x
13.533
Cone
y=126.31x+0.1508
y = 260.85x
47.66
Flat Plate
y=138.9x+0.2098
y = 166.42x
18.853
Appendix C: Equations
Newton’s 2nd Law for Fluids (linear momentum equation)
ρdV
+
ρV • dA
(1)
𝐹
𝑆
+ 𝐹
?
=
?
??
?𝑉
∫ 𝑉
?𝑆
∫ 𝑉
Unequal Volume Flow for an Inclined Plane:
(2)
α =
(???θ + 1)
2
Force of Jet on Inclined Plane at an Angle
:
θ
(3)
𝐹
?
=
ṁ
2
⍴?
?𝑖?
2
θ Force of a Jet on a Bucket with a Deflection Angle
:
θ
[1 + cos(180 - θ)]
(4)
𝐹
?
= ṁ
2
⍴?
Force of a Jet on a Cone with a Deflection Angle
:
θ
[1
cos(θ)]
(5)
𝐹
?
= ṁ
2
⍴?
−
Uncertainty of Measurements:
(6)
σ
?
=
1
𝑁−1
Σ(?
𝑖
− ??
𝑖
)
2
Uncertainty of the Slope:
(7)
σ
?
=
σ
?
Σ?
𝑖
2
Appendix D: Sample Calculations
Flat Plate calculations 90 degrees-20psi
= (1.211 gal / min)(1 min / 60s)(3.79 L/gal)(0.001 m^3/L)(998 kg/m^3)
=0.0765kg/sec
Theoretical force
= ((0.0765kg/sec)^2)*(Sin(90))/((998
kg/m^3)*(
0.000006157521601 m^2))
=
0.9460932377
N
Measured Force on the flat plate:
F=m*a
m=0.124 kg
g= weight= 9.81 m.sec
F= 1.216 N
Percent Error
=(100)((1.216-0.946093)/(0.946093))
= 28.53%
Volume Flow Rate
(gal/min)
Force (kg)
1.280
.0925
Cone piece 60 degrees- 20 psi
=
(1.280 gal / min)(1 min / 60s)(3.79 L/gal)(0.001 m^3/L)(998 kg/m^3)
=.080692 kg/ sec
Theoretical force
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= ((.080692 kg/sec)^2)*(1-cos 60)/ ((998 kg/m^3)*(
0.000006157521601 m^2))
=1.585465698 N
Measured Force on the flat plate:
F=m*a
m=0.0925 kg
g= weight= 9.81 m.sec
F= .90743 N
Percent Error
=(100)((0.90743-1.5855)/(1.5855))
= -42.76%
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a. Using Eq. (1), derive an expression for the fluid viscosity u as a function of S.
b. Plot the viscosity of the fluid as a function of S for 0.1s¹ ≤S≤ 10 s¹.
c. Based on class discussion on fluid classification, how would you characterize this fluid?
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fluid mechanics
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A 2.0 kg object is moving to the right with a speed of 1.0 m/s when it experiences the force shown in the graph at right. What are the object’s speed and direction after the force ends? Paste the completed Bar Chart below.
1. identify the system
2. draw a quick sketch of the initial state of the object(s)
3. do a momentum bar chart
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Please solve the following
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It is a Thermodynamics subject please show the complete and step by step solution. Use the given format I inserted. Please answer it as soon as possible.
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Subject mechanical.
Caption: take time but solve handwriting accurate Solutions ok
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