Centripetal Force Lab

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School

San Antonio College *

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Course

1611

Subject

Mechanical Engineering

Date

Dec 6, 2023

Type

pdf

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Uploaded by CorporalBook6857

1 Analysis of Centripetal Force Lab Name Course/Section PHY1611 Tables (20 points) m (kg) r (m) Max(N) Min (N) v(m/s) Brass 0.20897 0.195 0.579 -0.636 0.77 Aluminum 0.06613 0.375 0.260 -0.234 1.23 1. Calculate the theoretical value for the centripetal force for the brass mass using the formula " ! ! " . (5 points) 0.20897 x (0.77) 2 /0.195 = 0.6354N 2. Find the experimental value of the centripetal force for the brass mass. The amplitude of any simple sine wave can be calculated by dividing the difference between the maximum and minimum by 2. (5 points) 0.579-(0.636)=1.215/2 = 0.6075 3. Find the % error for the centripetal force of the brass mass. (5 points) (0.6075-0.63538/0.63538) x 100 = 4.3879 4. Calculate the theoretical value for the centripetal force for the aluminum mass using the formula " ! ! # . (5 points) (0.06613)1.23 2 /0.375 = 0.26679 N

2 5. Find the experimental value of the centripetal force for the aluminum mass. The amplitude of any simple sine wave can be calculated by dividing the difference between the maximum and minimum by 2. (5 points) [max-min/2] 0.260-(-0.234)/2 =0.247N 6. Find the % error for the centripetal force of the aluminum mass. (5points) (0.2668-0.247/(0.2668) x 100 = 7.421% 7. In regard to the force sensor in this experiment, what general direction does the centripetal acceleration vector point? (10 points) Centripetal acceleration is the point where velocity and center of rotation are perpendicular. 8. Using only the equation for centripetal force, show by what factor the force would change if the velocity of the bob was reduced by half, and briefly explain the results. (10 points) Because the velocity in this equation is squared, the force will change by a factor of ¼. 9. For a mass moving in a vertical circle, draw the free body diagram for when the mass is at the highest point of its path, and then write the force summation equation for that free body diagram. (10 points) F=m (v 2 /R) T + mg = mv 2 /R 10. Why is the force sensor zeroed when the mass is freely hanging from the hook? (5 points) To prevent mistakes, the force sensor is zeroed. 11. Centripetal force is not a fundamental force of nature. Explain what is meant by this. (5 points) The centripetal force is merely the name given to the net force that pushes an object in a circular direction; it is not a fundamental force.

3 12. Do the results of the experiment support the theory? Explain your answer. (5 points) The results of the experiment match the theoretical values. 13. What are possible reasons for the differences between the experimental and theoretical values of centripetal force? (5 points) The centripetal acceleration vector always faces the center of rotation and is perpendicular to velocity.

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